The difference in the boiling point of imidazole and N-methylimidazole has to be explained. Concept Introduction: Imidazole is the aromatic compound and also the heterocyclic ring of histidine. It exists in both protonated and non-protonated form at pH = 7.4 . The lone pair on first nitrogen are a part of the pi cloud as they are present in p orbital whereas the lone pair electrons on third nitrogen are not a part of pi cloud because they are perpendicular to the p orbitals.

Question

Want to see the full answer?

Answer 1

Question

Chapter 20.7, Problem 16P

Interpretation Introduction

Interpretation:

The difference in the boiling point of imidazole and N-methylimidazole has to be explained.

Concept Introduction:

Imidazole is the aromatic compound and also the heterocyclic ring of histidine. It exists in both protonated and non-protonated form at pH=7.4. The lone pair on first nitrogen are a part of the pi cloud as they are present in p orbital whereas the lone pair electrons on third nitrogen are not a part of pi cloud because they are perpendicular to the p orbitals.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Calculate the reflectivity of natural light when it falls normally on a flat borosilicate glass surface (n = 1.47).

None

Answer 2

Question

Chapter 20.7, Problem 16P

Interpretation Introduction

Interpretation:

The difference in the boiling point of imidazole and N-methylimidazole has to be explained.

Concept Introduction:

Imidazole is the aromatic compound and also the heterocyclic ring of histidine. It exists in both protonated and non-protonated form at pH=7.4. The lone pair on first nitrogen are a part of the pi cloud as they are present in p orbital whereas the lone pair electrons on third nitrogen are not a part of pi cloud because they are perpendicular to the p orbitals.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 20.7, Problem 16P

Interpretation Introduction

Interpretation:

The difference in the boiling point of imidazole and N-methylimidazole has to be explained.

Concept Introduction:

Imidazole is the aromatic compound and also the heterocyclic ring of histidine. It exists in both protonated and non-protonated form at pH=7.4. The lone pair on first nitrogen are a part of the pi cloud as they are present in p orbital whereas the lone pair electrons on third nitrogen are not a part of pi cloud because they are perpendicular to the p orbitals.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 20.7, Problem 16P

Interpretation Introduction

Interpretation:

The difference in the boiling point of imidazole and N-methylimidazole has to be explained.

Concept Introduction:

Imidazole is the aromatic compound and also the heterocyclic ring of histidine. It exists in both protonated and non-protonated form at pH=7.4. The lone pair on first nitrogen are a part of the pi cloud as they are present in p orbital whereas the lone pair electrons on third nitrogen are not a part of pi cloud because they are perpendicular to the p orbitals.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 20.7, Problem 16P

Interpretation Introduction

Interpretation:

The difference in the boiling point of imidazole and N-methylimidazole has to be explained.

Concept Introduction:

Imidazole is the aromatic compound and also the heterocyclic ring of histidine. It exists in both protonated and non-protonated form at pH=7.4. The lone pair on first nitrogen are a part of the pi cloud as they are present in p orbital whereas the lone pair electrons on third nitrogen are not a part of pi cloud because they are perpendicular to the p orbitals.

Answer 6

Chapter 20.7, Problem 16P

Interpretation Introduction

Interpretation:

The difference in the boiling point of imidazole and N-methylimidazole has to be explained.

Concept Introduction:

Imidazole is the aromatic compound and also the heterocyclic ring of histidine. It exists in both protonated and non-protonated form at pH=7.4. The lone pair on first nitrogen are a part of the pi cloud as they are present in p orbital whereas the lone pair electrons on third nitrogen are not a part of pi cloud because they are perpendicular to the p orbitals.

Answer 7

Chapter 20.7, Problem 16P

Interpretation Introduction

Interpretation:

The difference in the boiling point of imidazole and N-methylimidazole has to be explained.

Concept Introduction:

Imidazole is the aromatic compound and also the heterocyclic ring of histidine. It exists in both protonated and non-protonated form at pH=7.4. The lone pair on first nitrogen are a part of the pi cloud as they are present in p orbital whereas the lone pair electrons on third nitrogen are not a part of pi cloud because they are perpendicular to the p orbitals.

Answer 8

Expert Solution & Answer

Answer 9

Expert Solution & Answer

Answer 10

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 11

Ch. 20.1 - Name the following:Ch. 20.2 - Prob. 2P Ch. 20.2 - Prob. 3P Ch. 20.3 - Draw the product of each of the following...Ch. 20.5 - Prob. 6P Ch. 20.5 - When pyrrole is added to a dilute solution of...Ch. 20.5 - Explain why cyclopentadiene (pKa = 15) is more...Ch. 20.6 - Prob. 10P Ch. 20.6 - How to the mechanisms of the following reactions...Ch. 20.6 - Prob. 12P

Solution Summary: The author explains the difference in the boiling point of imidazole and N-methylimi

Want to see the full answer?

Chapter 20 Solutions