The mixture at equilibrium needs to be estimated for K equal to 2.0. Concept Introduction: For any reaction, the reaction quotient can be calculated by taking the ratio of the concentration of the product to the reactant. For a reaction at equilibrium, the reaction quotient is equal to the equilibrium constant.

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Answer 1

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Chapter 20.4, Problem 20.10BFP

(a)

Interpretation Introduction

Interpretation: The mixture at equilibrium needs to be estimated for K equal to 2.0.

Concept Introduction: For any reaction, the reaction quotient can be calculated by taking the ratio of the concentration of the product to the reactant. For a reaction at equilibrium, the reaction quotient is equal to the equilibrium constant.

(b)

Interpretation Introduction

Interpretation: The three mixtures need to be ranked from lowest to highest change in Gibbs free energy.

Concept Introduction: For a spontaneous reaction, the sign of change in Gibbs free energy is negative. If the value of Q is less than K, the reaction moves in the right direction to increase the concentration of the product. Also, if the value of Q is greater than K, the reaction moves in the left direction to increase the concentration of reactants.

(c)

Interpretation Introduction

Interpretation: The sign of change in Gibbs free energy of reaction needs to be identified if each non-equilibrium mixture approaches equilibrium.

Concept Introduction: Any reaction moving spontaneously will have a negative value for change in Gibbs free energy.

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Part I. a) Elucidate the structure of compound A using the following information. • mass spectrum: m+ = 102, m/2=57 312=29 • IR spectrum: 1002.5 % TRANSMITTANCE Ngg 50 40 30 20 90 80 70 60 MICRONS 5 8 9 10 12 13 14 15 16 19 1740 cm M 10 0 4000 3600 3200 2800 2400 2000 1800 1600 13 • CNMR 'H -NMR Peak 8 ppm (H) Integration multiplicity a 1.5 (3H) triplet b 1.3 1.5 (3H) triplet C 2.3 1 (2H) quartet d 4.1 1 (2H) quartet & ppm (c) 10 15 28 60 177 (C=0) b) Elucidate the structure of compound B using the following information 13C/DEPT NMR 150.9 MHz IIL 1400 WAVENUMBERS (CM-1) DEPT-90 DEPT-135 85 80 75 70 65 60 55 50 45 40 35 30 25 20 ppm 1200 1000 800 600 400

• Part II. a) Elucidate The structure of compound c w/ molecular formula C10 11202 and the following data below: • IR spectra % TRANSMITTANCE 1002.5 90 80 70 60 50 40 30 20 10 0 4000 3600 3200 2800 2400 2000 1800 1600 • Information from 'HAMR MICRONS 8 9 10 11 14 15 16 19 25 1400 WAVENUMBERS (CM-1) 1200 1000 800 600 400 peak 8 ppm Integration multiplicity a 2.1 1.5 (3H) Singlet b 3.6 1 (2H) singlet с 3.8 1.5 (3H) Singlet d 6.8 1(2H) doublet 7.1 1(2H) doublet Information from 13C-nmR Normal carbon 29ppm Dept 135 Dept -90 + NO peak NO peak 50 ppm 55 ppm + NO peak 114 ppm t 126 ppm No peak NO peak 130 ppm t + 159 ppm No peak NO peak 207 ppm по реак NO peak

Could you redraw these and also explain how to solve them for me pleas

Answer 2

Question

Chapter 20.4, Problem 20.10BFP

(a)

Interpretation Introduction

Interpretation: The mixture at equilibrium needs to be estimated for K equal to 2.0.

Concept Introduction: For any reaction, the reaction quotient can be calculated by taking the ratio of the concentration of the product to the reactant. For a reaction at equilibrium, the reaction quotient is equal to the equilibrium constant.

(b)

Interpretation Introduction

Interpretation: The three mixtures need to be ranked from lowest to highest change in Gibbs free energy.

Concept Introduction: For a spontaneous reaction, the sign of change in Gibbs free energy is negative. If the value of Q is less than K, the reaction moves in the right direction to increase the concentration of the product. Also, if the value of Q is greater than K, the reaction moves in the left direction to increase the concentration of reactants.

(c)

Interpretation Introduction

Interpretation: The sign of change in Gibbs free energy of reaction needs to be identified if each non-equilibrium mixture approaches equilibrium.

Concept Introduction: Any reaction moving spontaneously will have a negative value for change in Gibbs free energy.

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Answer 3

Question

Chapter 20.4, Problem 20.10BFP

(a)

Interpretation Introduction

Interpretation: The mixture at equilibrium needs to be estimated for K equal to 2.0.

Concept Introduction: For any reaction, the reaction quotient can be calculated by taking the ratio of the concentration of the product to the reactant. For a reaction at equilibrium, the reaction quotient is equal to the equilibrium constant.

(b)

Interpretation Introduction

Interpretation: The three mixtures need to be ranked from lowest to highest change in Gibbs free energy.

Concept Introduction: For a spontaneous reaction, the sign of change in Gibbs free energy is negative. If the value of Q is less than K, the reaction moves in the right direction to increase the concentration of the product. Also, if the value of Q is greater than K, the reaction moves in the left direction to increase the concentration of reactants.

(c)

Interpretation Introduction

Interpretation: The sign of change in Gibbs free energy of reaction needs to be identified if each non-equilibrium mixture approaches equilibrium.

Concept Introduction: Any reaction moving spontaneously will have a negative value for change in Gibbs free energy.

Expert Solution & Answer

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Answer 4

Question

Chapter 20.4, Problem 20.10BFP

(a)

Interpretation Introduction

Interpretation: The mixture at equilibrium needs to be estimated for K equal to 2.0.

Concept Introduction: For any reaction, the reaction quotient can be calculated by taking the ratio of the concentration of the product to the reactant. For a reaction at equilibrium, the reaction quotient is equal to the equilibrium constant.

(b)

Interpretation Introduction

Interpretation: The three mixtures need to be ranked from lowest to highest change in Gibbs free energy.

Concept Introduction: For a spontaneous reaction, the sign of change in Gibbs free energy is negative. If the value of Q is less than K, the reaction moves in the right direction to increase the concentration of the product. Also, if the value of Q is greater than K, the reaction moves in the left direction to increase the concentration of reactants.

(c)

Interpretation Introduction

Interpretation: The sign of change in Gibbs free energy of reaction needs to be identified if each non-equilibrium mixture approaches equilibrium.

Concept Introduction: Any reaction moving spontaneously will have a negative value for change in Gibbs free energy.

Expert Solution & Answer

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Answer 5

Chapter 20.4, Problem 20.10BFP

(a)

Interpretation Introduction

Interpretation: The mixture at equilibrium needs to be estimated for K equal to 2.0.

Concept Introduction: For any reaction, the reaction quotient can be calculated by taking the ratio of the concentration of the product to the reactant. For a reaction at equilibrium, the reaction quotient is equal to the equilibrium constant.

(b)

Interpretation Introduction

Interpretation: The three mixtures need to be ranked from lowest to highest change in Gibbs free energy.

Concept Introduction: For a spontaneous reaction, the sign of change in Gibbs free energy is negative. If the value of Q is less than K, the reaction moves in the right direction to increase the concentration of the product. Also, if the value of Q is greater than K, the reaction moves in the left direction to increase the concentration of reactants.

(c)

Interpretation Introduction

Interpretation: The sign of change in Gibbs free energy of reaction needs to be identified if each non-equilibrium mixture approaches equilibrium.

Concept Introduction: Any reaction moving spontaneously will have a negative value for change in Gibbs free energy.

Answer 6

Chapter 20.4, Problem 20.10BFP

(a)

Interpretation Introduction

Interpretation: The mixture at equilibrium needs to be estimated for K equal to 2.0.

Concept Introduction: For any reaction, the reaction quotient can be calculated by taking the ratio of the concentration of the product to the reactant. For a reaction at equilibrium, the reaction quotient is equal to the equilibrium constant.

Answer 7

Chapter 20.4, Problem 20.10BFP

(a)

Interpretation Introduction

Interpretation: The mixture at equilibrium needs to be estimated for K equal to 2.0.

Concept Introduction: For any reaction, the reaction quotient can be calculated by taking the ratio of the concentration of the product to the reactant. For a reaction at equilibrium, the reaction quotient is equal to the equilibrium constant.

Answer 8

(b)

Interpretation Introduction

Interpretation: The three mixtures need to be ranked from lowest to highest change in Gibbs free energy.

Concept Introduction: For a spontaneous reaction, the sign of change in Gibbs free energy is negative. If the value of Q is less than K, the reaction moves in the right direction to increase the concentration of the product. Also, if the value of Q is greater than K, the reaction moves in the left direction to increase the concentration of reactants.

Answer 9

(b)

Interpretation Introduction

Interpretation: The three mixtures need to be ranked from lowest to highest change in Gibbs free energy.

Concept Introduction: For a spontaneous reaction, the sign of change in Gibbs free energy is negative. If the value of Q is less than K, the reaction moves in the right direction to increase the concentration of the product. Also, if the value of Q is greater than K, the reaction moves in the left direction to increase the concentration of reactants.

Answer 10

(c)

Interpretation Introduction

Interpretation: The sign of change in Gibbs free energy of reaction needs to be identified if each non-equilibrium mixture approaches equilibrium.

Concept Introduction: Any reaction moving spontaneously will have a negative value for change in Gibbs free energy.

Answer 11

(c)

Interpretation Introduction

Interpretation: The sign of change in Gibbs free energy of reaction needs to be identified if each non-equilibrium mixture approaches equilibrium.

Concept Introduction: Any reaction moving spontaneously will have a negative value for change in Gibbs free energy.

Answer 12

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Answer 13

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Answer 14

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Answer 15

Ch. 20.1 - Prob. 20.1AFP Ch. 20.1 - Prob. 20.1BFP Ch. 20.2 - Prob. 20.2AFP Ch. 20.2 - Prob. 20.2BFP Ch. 20.2 - Prob. 20.3AFP Ch. 20.2 - Prob. 20.3BFP Ch. 20.3 - Prob. 20.4AFP Ch. 20.3 - Prob. 20.4BFP Ch. 20.3 - Prob. 20.5AFP Ch. 20.3 - Prob. 20.5BFP

Solution Summary: The author explains that the reaction quotient can be calculated by taking the ratio of the product to the reactant.

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Interpretation: The sign of change in Gibbs free energy of reaction needs to be identified if each non-equilibrium mixture approaches equilibrium.

Concept Introduction: Any reaction moving spontaneously will have a negative value for change in Gibbs free energy.

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Chapter 20 Solutions

Solution Summary: The author explains that the reaction quotient can be calculated by taking the ratio of the product to the reactant.

Videos

Interpretation: The sign of change in Gibbs free energy of reaction needs to be identified if each non-equilibrium mixture approaches equilibrium. Concept Introduction: Any reaction moving spontaneously will have a negative value for change in Gibbs free energy.

Want to see the full answer?

Chapter 20 Solutions

Interpretation: The sign of change in Gibbs free energy of reaction needs to be identified if each non-equilibrium mixture approaches equilibrium.

Concept Introduction: Any reaction moving spontaneously will have a negative value for change in Gibbs free energy.