Concept explainers
Interpretation:
The IUPAC names of the given alcohol and whether it is primary, secondary or tertiary should be determined.
Concept Introduction:
When alcohol (having hydroxyl group) is attached to a primary carbon atom (carbon atom to which one carbon atom is attached) then such alcohol is said to be a primary alcohol.
When alcohol (having hydroxyl group) is attached to a secondary carbon atom (carbon atom to which two carbon atoms are attached) then such alcohol is said to be a secondary alcohol.
When alcohol (having hydroxyl group) is attached to a tertiary carbon atom (carbon atom to which three carbon atoms are attached) then such alcohol is said to be a tertiary alcohol.
In order to give the IUPAC name to the alcohol following steps are followed:
1. The parent (longest)
2. The ending of the parent chain from alkane (-e) is changed to -ol and the number is used to locate the -OH group of alcohol.
3. Name should be written in alphabetical order and numbering should be done in such a way that hydroxy group gets lowest number.
4. Configuration should be specified is there exist any cis-trans isomerism.
Interpretation:
The IUPAC names of the given alcohol and whether it is primary, secondary or tertiary should be determined.
Concept Introduction:
When alcohol (having hydroxyl group) is attached to a primary carbon atom (carbon atom to which one carbon atom is attached) then such alcohol is said to be a primary alcohol.
When alcohol (having hydroxyl group) is attached to a secondary carbon atom (carbon atom to which two carbon atoms are attached) then such alcohol is said to be a secondary alcohol.
When alcohol (having hydroxyl group) is attached to a tertiary carbon atom (carbon atom to which three carbon atoms are attached) then such alcohol is said to be a tertiary alcohol.
In order to give the IUPAC name to the alcohol following steps are followed:
1. The parent (longest) alkane chain is identified.
2. The ending of the parent chain from alkane (-e) is changed to -ol and the number is used to locate the -OH group of alcohol.
3. Name should be written in alphabetical order and numbering should be done in such a way that hydroxy group gets lowest number.
4. Configuration should be specified is there exist any cis-trans isomerism.
Interpretation:
The IUPAC names of the given alcohol and whether it is primary, secondary or tertiary should be determined.
Concept Introduction:
When alcohol (having hydroxyl group) is attached to a primary carbon atom (carbon atom to which one carbon atom is attached) then such alcohol is said to be a primary alcohol.
When alcohol (having hydroxyl group) is attached to a secondary carbon atom (carbon atom to which two carbon atoms are attached) then such alcohol is said to be a secondary alcohol.
When alcohol (having hydroxyl group) is attached to a tertiary carbon atom (carbon atom to which three carbon atoms are attached) then such alcohol is said to be a tertiary alcohol.
In order to give the IUPAC name to the alcohol following steps are followed:
1. The parent (longest) alkane chain is identified.
2. The ending of the parent chain from alkane (-e) is changed to -ol and the number is used to locate the -OH group of alcohol.
3. Name should be written in alphabetical order and numbering should be done in such a way that hydroxy group gets lowest number.
4. Configuration should be specified is there exist any cis-trans isomerism.
Want to see the full answer?
Check out a sample textbook solutionChapter 20 Solutions
Introductory Chemistry: A Foundation
- Practice Supply the missing products, reagents or starting materials as necessary. 1) NaCN 2) НCI а. OH b. 1) NABD4 2) HC, H-О с.arrow_forwardGive comen name for the given compund. Need experts solution only Don't use AI,arrow_forwardChoices a) carotene is the most non polar. b) Xantophyll is yellow spot. c) carotene has the highest rf value. d) ch b has the highest rf valuearrow_forward
- Dashboard O PRINCIPLES OF ORGANIC CHEMISTRY Identifying hydrophobic and hydrophilic parts of an organic... ALEKS Explanation Check Highlight the atoms or groups that are in hydrophobic portions of this molecule in blue, and the atoms or groups that are in hydrophilic portions of this molecule in red. CH3-CH₂-0-CH₂-CH3 A ALEKS-Kimberly Cedillos - Learn MacBook Pro X G Write down the oxidation state 3 OD 1/3 Kimberly © 2023 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility ol E Ar 0 Marrow_forwardName the following compounds. Do not use italics or boldface. H3C CO2H a) 'N' b) CH3 CH3 Submit Answer Try Another Version 2 item attempts remainingarrow_forward20. Which of the following compounds consists of molecules that show geometrical (cis-trans) isomerism? a. 2-methylpropene b. 2-butene c. 2-methyl-2-butene d. more than one response is correct e. no correct responsearrow_forward
- Practice Exercises Naming Aldehydes Give the IUPAC name for each aldehyde. a) CH3 b) || CH:CHCH— G —н CH3CH2CH2-Ç-CH2CH3 CHO CH3 c) (CH3)2CHCH,CH,CHO d) (CH3);CC(CH3)2CH2CHOarrow_forwardHow many monochloro substitution products are produced when the alkanes below are chlorinated? Consider constitutional isomers only, ignore stereoisomers. a) b) + Submit Answer The number of monochloro substitution products is 1 The number of monochloro substitution products is Retry Entire Group 8 more group attempts remainingarrow_forwardProblem 1 1. NaH, 2. LiAlH4 O NaH/ 1. LIAIH 2. TsCl, pyridine 3. NaH/ EtooC COOEt 1. NaCl/heat (decarboxylation) 2. LiAlH4 3. PCCarrow_forward
- Organic chemistry exercise. Please provide decent explanation if they are wrong or correct.arrow_forwardheterocyclic equationarrow_forward15. Alkanes have low boiling points because there are between molecules. a. hydrogen bonds b. strong attractions C. weak attractions d. ionic attractions e. no correct response is givenarrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning