Chapter 20, Problem 90A

Interpretation Introduction

Interpretation:

The equilibrium constant for the given reaction $A_{2}B\stackrel{}{\rightleftarrows }2A+B$ is to be calculated.

Concept introduction:

The equilibrium constant depends upon the concentrations of reactants and products at equilibrium and their stoichiometric coefficients.

Answer to Problem 90A

The value of K_sp is 5.018 mol²/L².

Explanation of Solution

Concentration of reactants:

$[A_{2}B]=0.855mol/L$

Concentration of products:

$\begin{array}{l}[A]=2.045mol/L\\ [B]=1.026mol/L\end{array}$

Equilibrium constant K_eq:

$\begin{array}{l}{K}_{eq}=\frac{{[A]}^2[B]}{[A_{2}B]}\\ K_{eq}=\frac{{(2.045)}^2\times 1.026}{0.855}\\ K_{eq}=5.018{(}^m\end{array}$

Conclusion

The equilibrium constant for the given reaction is 5.018 mol²/L².