Chapter 20, Problem 31A

Interpretation Introduction

Interpretation:

That process in which electrons are released in zinc copper voltaic cell is to be explained.

Concept introduction:

The process in which electrons are loses or releases is called oxidation process.

Answer to Problem 31A

Oxidation process

Explanation of Solution

Oxidation process is the process in which electrons are released

The reaction which occur in zinc copper voltaic cell is

$\begin{array}{l}{\text{Zn+Cu}}^{\text{+2}}\left(\text{aq}\right)\to {\text{Zn}}^{\text{+2}}\left(\text{aq}\right)\text{+Cu}\left(\text{s}\right)\\ \text{here,}\text{zinc}\text{loss}\text{the}\text{electrons}\end{array}$

It undergoes oxidation.

Conclusion

The root mean square speed of nitrogen gas and chlorine gas are given as:

$\begin{array}{l}\frac{{\text{µ}}_{\text{rms}}\left({\text{N}}_{\text{2}}\right)}{{\text{µ}}_{\text{rms}}\left({\text{Cl}}_{\text{2}}\right)}\text{=}\frac{\sqrt{\frac{\text{3RT}}{{\text{M}}_{{\text{N}}_{\text{2}}}}}}{\sqrt{\frac{\text{3RT}}{{\text{M}}_{{\text{Cl}}_{\text{2}}}}}}\\ \text{=}\sqrt{\frac{{\text{M}}_{{\text{Cl}}_{\text{2}}}}{{\text{M}}_{{\text{N}}_{\text{2}}}}}\\ \text{=}\sqrt{\frac{\text{71}}{\text{28}}}\\ \text{=}\frac{\text{8}\text{.4}}{\text{5}\text{.3}}\end{array}$

The ratio of speed of nitrogen gas to the chlorine gas is $\frac{\text{8}\text{.4}}{\text{5}\text{.3}}$.