Given the solubility product constant of C a C O 3 , its molar solubility in water has to be calculated. Concept Introduction: Solubility product constant, K sp correlates to the equilibrium constant for the phenomenon of solid substance dissolving in aqueous solution. Consider a solid substance ‘X’ dissolves as follows – x X ( s ) ⇄ y Y ( a q ) + z Z ( a q ) The expression for K sp is given as, K s p = [ Y ] y [ Z ] z [ X ] x Since concentration of solid remains constant during solvation the above expression becomes, K s p = [ Y ] y [ Z ] z Greater the solubility of the substance greater is its K sp value.

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Chapter 20, Problem 77AE

Interpretation Introduction

Interpretation:

Given the solubility product constant of CaCO3 , its molar solubility in water has to be calculated.

Concept Introduction:

Solubility product constant, K_sp correlates to the equilibrium constant for the phenomenon of solid substance dissolving in aqueous solution.

Consider a solid substance ‘X’ dissolves as follows –

xX(s)⇄yY(aq)+zZ(aq)

The expression for K_sp is given as,

Ksp = [Y]y[Z]z[X]x

Since concentration of solid remains constant during solvation the above expression becomes,

Ksp = [Y]y[Z]z

Greater the solubility of the substance greater is its K_sp value.

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