Chemistry: An Atoms First Approach
Chemistry: An Atoms First Approach
2nd Edition
ISBN: 9781305079243
Author: Steven S. Zumdahl, Susan A. Zumdahl
Publisher: Cengage Learning
Question
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Chapter 20, Problem 66E

(a)

Interpretation Introduction

Interpretation: The reaction between Fe2O3 and CO is given. The value of ΔH,ΔS and ΔG are to be calculated for the given options.

Concept introduction: The expression for ΔH is,

ΔH=npΔH(product)nfΔH(reactant)

The expression for ΔS is,

ΔS=npΔS(product)nfΔS(reactant)

The expression for standard Gibbs free energy, ΔG, is,

ΔG=ΔHTΔS

To determine: The value of ΔH and ΔS for the given reaction.

(a)

Expert Solution
Check Mark

Answer to Problem 66E

Solution

The value of ΔS for the given reaction is 38J/K_. The value of ΔH for the given reaction is 39kJ_.

Explanation of Solution

Explanation

The reaction that takes place is,

3Fe2O3(s)+CO(g)2Fe3O4(s)+CO2(g)

Refer to Appendix 4.

The value of ΔH(kJ/mol) for the given reactant and product is,

Molecules ΔH0(kJ/mol)
Fe3O4(s) 1117
CO2(g) 393.5
Fe2O3(s) 826
CO(g) 110.5

The formula of ΔH is,

ΔH=npΔH(product)nfΔH(reactant)

Where,

  • ΔH is the standard enthalpy of reaction.
  • np is the number of moles of each product.
  • nr is the number of moles each reactant.
  • ΔH(product) is the standard enthalpy of product at a pressure of 1atm.
  • ΔH(reactant) is the standard enthalpy of reactant at a pressure of 1atm.

Substitute all values from the table in the above equation.

ΔH=npΔH(product)nfΔH(reactant)=[2(1117)+2(393.5){3(826)+(110.5)}]kJ=39kJ_

The value of ΔS(J/Kmol) for the given reactant and product is,

Molecules ΔS0(kJ/mol)
Fe3O4(s) 146
CO2(g) 214
Fe2O3(s) 90
CO(g) 198

The formula of ΔS is,

ΔS=npΔS(product)nfΔS(reactant)

Where,

  • ΔS standard enthalpy of reaction.
  • np is number of moles of each product.
  • nr is number of moles each reactant.
  • ΔS(product) is standard enthalpy of product at a pressure of 1atm.
  • ΔS(reactant) is standard enthalpy of reactant at a pressure of 1atm.

Substitute all values from the table in the above equation.

ΔS=npΔS(product)nfΔS(reactant)=[2(146)+1(214){3(90)+(198)}]J/K=38J/K_

(b)

Interpretation Introduction

Interpretation: The reaction between Fe2O3 and CO is given. The value of ΔH,ΔS and ΔG are to be calculated for the given options.

Concept introduction: The expression for ΔH is,

ΔH=npΔH(product)nfΔH(reactant)

The expression for ΔS is,

ΔS=npΔS(product)nfΔS(reactant)

The expression for standard Gibbs free energy, ΔG, is,

ΔG=ΔHTΔS

To determine: The value of ΔG at 800°C for the given reaction.

(b)

Expert Solution
Check Mark

Answer to Problem 66E

Answer

The value of ΔG for the given reaction is 80kJ_.

Explanation of Solution

Explanation

Given

Temperature is 800°C.

The value of ΔH is 39kJ.

The value of ΔS is 38J/K.

The conversion of degree Celsius (°C) into Kelvin (K) is done as,

T(K)=T(°C)+273

Hence,

The conversion of 800°C into Kelvin is,

T(K)=T(°C)+273T(K)=(800+273)K=1073K

The conversion of joule (J) into kilo-joule (kJ) is done as,

1J=103kJ

Hence,

The conversion of 38J/K into kilo-joule is,

38J=(38×103)kJ=38×103kJ

Formula

The expression for standard Gibbs free energy, ΔG, is,

ΔG=ΔHTΔS

Where,

  • ΔH is the standard enthalpy of reaction.
  • ΔG is the free energy change.
  • T is the given temperature.
  • ΔS is the entropy of reaction.

Substitute the values of ΔH and ΔS in the above equation.

ΔG=ΔHTΔS=39kJ1073K(38×103kJ/K)=80kJ_

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Chapter 20 Solutions

Chemistry: An Atoms First Approach

Ch. 20 - Prob. 1ALQCh. 20 - Prob. 2ALQCh. 20 - Prob. 3ALQCh. 20 - Prob. 4ALQCh. 20 - Prob. 5QCh. 20 - Four different octahedral chromium coordination...Ch. 20 - Prob. 7QCh. 20 - Prob. 8QCh. 20 - Prob. 9QCh. 20 - Prob. 10QCh. 20 - Prob. 11QCh. 20 - Prob. 12QCh. 20 - Prob. 13QCh. 20 - Prob. 14QCh. 20 - Prob. 15QCh. 20 - Prob. 16QCh. 20 - Prob. 17QCh. 20 - Prob. 18QCh. 20 - Prob. 19QCh. 20 - Prob. 20QCh. 20 - Prob. 21ECh. 20 - Prob. 22ECh. 20 - Prob. 23ECh. 20 - Prob. 24ECh. 20 - Prob. 25ECh. 20 - Prob. 26ECh. 20 - Prob. 27ECh. 20 - Prob. 28ECh. 20 - Prob. 29ECh. 20 - Prob. 30ECh. 20 - Prob. 31ECh. 20 - A coordination compound of cobalt(III) contains...Ch. 20 - Prob. 33ECh. 20 - Prob. 34ECh. 20 - Prob. 35ECh. 20 - Prob. 36ECh. 20 - Prob. 37ECh. 20 - Give formulas for the following complex ions. a....Ch. 20 - Prob. 39ECh. 20 - Prob. 40ECh. 20 - Prob. 41ECh. 20 - Amino acids can act as ligands toward transition...Ch. 20 - Prob. 43ECh. 20 - Prob. 44ECh. 20 - Prob. 45ECh. 20 - Prob. 46ECh. 20 - Prob. 47ECh. 20 - Prob. 48ECh. 20 - Prob. 49ECh. 20 - Prob. 50ECh. 20 - Prob. 51ECh. 20 - Prob. 52ECh. 20 - The CrF64 ion is known to have four unpaired...Ch. 20 - Prob. 54ECh. 20 - Prob. 55ECh. 20 - The complex ion Fe(CN)63 is paramagnetic with one...Ch. 20 - Prob. 57ECh. 20 - Prob. 58ECh. 20 - Prob. 59ECh. 20 - Prob. 60ECh. 20 - The wavelength of absorbed electromagnetic...Ch. 20 - The complex ion NiCL42 has two unpaired electrons,...Ch. 20 - How many unpaired electrons are present in the...Ch. 20 - Prob. 64ECh. 20 - Prob. 65ECh. 20 - Prob. 66ECh. 20 - Prob. 67ECh. 20 - Prob. 68ECh. 20 - Silver is sometimes found in nature as large...Ch. 20 - Prob. 70ECh. 20 - Prob. 71AECh. 20 - The compound cisplatin, Pt(NH3)2Cl2, has been...Ch. 20 - Prob. 73AECh. 20 - Prob. 74AECh. 20 - Prob. 75AECh. 20 - Prob. 76AECh. 20 - Prob. 77AECh. 20 - Name the following coordination compounds. a....Ch. 20 - Prob. 79AECh. 20 - Prob. 80AECh. 20 - Carbon monoxide is toxic because it binds more...Ch. 20 - For the process Co(NH3)5Cl2++ClCO(NH3)4Cl2++NH3...Ch. 20 - Prob. 83CWPCh. 20 - Which of the following molecules exhibit(s)...Ch. 20 - Prob. 85CWPCh. 20 - Prob. 86CWPCh. 20 - Prob. 87CWPCh. 20 - Which of the following statement(s) is( are) true?...Ch. 20 - Prob. 89CPCh. 20 - Consider the pseudo-octahedral complex ion of...Ch. 20 - Prob. 91CPCh. 20 - Prob. 92CPCh. 20 - Prob. 93CPCh. 20 - Prob. 94CPCh. 20 - Prob. 95CPCh. 20 - Prob. 96CPCh. 20 - Prob. 97CPCh. 20 - Prob. 98IPCh. 20 - Prob. 99IPCh. 20 - Prob. 100IPCh. 20 - Prob. 101MP
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