The structure for the compound C is to be proposed. Concept introduction: DEPT stands for distortion less enhancement by polarization transfer. DEPT 13 C − NMR is used to indicate the number of hydrogen atoms that are bonded to each carbon while providing the information of chemical shift in a broadband proton-decoupled 13 C − NMR spectrum. The carbon signals in a DEPT spectrum are classified as CH 3 , CH 2 , CH or C accordingly. Presence of the electronegative compounds like halogens or oxygen or sulfur elements will downfield the signal i.e., the chemical shift will occur at higher δ than the unsubstituted carbons. The tollens test is used to distinguish between aldehyde and ketone . Aldehyde gives positive tollens test and ketone gives negative test.

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Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 20, Problem 49P

Interpretation Introduction

Interpretation:

The structure for the compound C is to be proposed.

Concept introduction:

DEPT stands for distortion less enhancement by polarization transfer. DEPT 13C−NMR is used to indicate the number of hydrogen atoms that are bonded to each carbon while providing the information of chemical shift in a broadband proton-decoupled 13C−NMR spectrum.

The carbon signals in a DEPT spectrum are classified as CH3,CH2,CH or C accordingly.

Presence of the electronegative compounds like halogens or oxygen or sulfur elements will downfield the signal i.e., the chemical shift will occur at higher δ than the unsubstituted carbons.

The tollens test is used to distinguish between aldehyde and ketone. Aldehyde gives positive tollens test and ketone gives negative test.

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Using the general properties of equilibrium constants At a certain temperature, the equilibrium constant K for the following reaction is 0.84: H2(g) + 2(g) 2 HI(g) = Use this information to complete the following table. Suppose a 34. L reaction vessel is filled with 0.79 mol of HI. What can you say about the composition of the mixture in the vessel at equilibrium? There will be very little H2 and 12. ☐ x10 There will be very little HI. Neither of the above is true. What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. 2 HI(g) H₂(9)+12(9) K = What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. 2 H2(g)+212(9) 4 HI(g) K = ☐ ☑

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For this question please solve the first question. Please explain your thought process, the steps you took, and how you would tackle a similar problem. Thank you for your help!

Answer 2

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 20, Problem 49P

Interpretation Introduction

Interpretation:

The structure for the compound C is to be proposed.

Concept introduction:

DEPT stands for distortion less enhancement by polarization transfer. DEPT 13C−NMR is used to indicate the number of hydrogen atoms that are bonded to each carbon while providing the information of chemical shift in a broadband proton-decoupled 13C−NMR spectrum.

The carbon signals in a DEPT spectrum are classified as CH3,CH2,CH or C accordingly.

Presence of the electronegative compounds like halogens or oxygen or sulfur elements will downfield the signal i.e., the chemical shift will occur at higher δ than the unsubstituted carbons.

The tollens test is used to distinguish between aldehyde and ketone. Aldehyde gives positive tollens test and ketone gives negative test.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 3

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 20, Problem 49P

Interpretation Introduction

Interpretation:

The structure for the compound C is to be proposed.

Concept introduction:

DEPT stands for distortion less enhancement by polarization transfer. DEPT 13C−NMR is used to indicate the number of hydrogen atoms that are bonded to each carbon while providing the information of chemical shift in a broadband proton-decoupled 13C−NMR spectrum.

The carbon signals in a DEPT spectrum are classified as CH3,CH2,CH or C accordingly.

Presence of the electronegative compounds like halogens or oxygen or sulfur elements will downfield the signal i.e., the chemical shift will occur at higher δ than the unsubstituted carbons.

The tollens test is used to distinguish between aldehyde and ketone. Aldehyde gives positive tollens test and ketone gives negative test.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 20, Problem 49P

Interpretation Introduction