Chapter 20, Problem 20.87QP

Interpretation Introduction

Interpretation: The wavelength of the radiation in nanometer should be calculated when the energy of the $\text{γ}$ ray is $\text{2}{\text{.4×10}}^{\text{-13}}\text{J/photon}$.

Concept Introduction:

Formula:

Gamma rays range: 0.01to0.1 A.

Planks Quantum theory

$\text{E=}\frac{\text{hc}}{\text{λ}}$

Where, E= energy of the $\text{γ}$ ray

    h=Planks constant. i.e.( $\text{6}{\text{.63×10}}^{\text{-34}}\text{J}\text{.s}$)

    c=velocity of the light i.e. $\left(\text{3}{\text{.00×10}}^{\text{8}}\text{m/s}\right)$

   $\text{λ}$=wavelength of the radiation.

Given:

E= energy of the $\text{γ}$ ray is $\text{2}{\text{.4×10}}^{\text{-13}}\text{J/photon}$.