Concept explainers
Treatment of compound C (molecular formula
Compound C signals at
Compound D signals at
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Organic Chemistry
- Compound I (C11H14O2) is insoluble in water, aqueous acid, and aqueous NaHCO3, but dissolves readily in 10% Na2CO3 and 10% NaOH. When these alkaline solutions are acidified with 10% HCl, compound I is recovered unchanged. Given this information and its 1H-NMR spectrum, deduce the structure of compound I.arrow_forwardFollowing are 1H-NMR spectra for compounds G, H, and I, each with the molecular formula C5H12O. Each is a liquid at room temperature, is slightly soluble in water, and reacts with sodium metal with the evolution of a gas. (a) Propose structural formulas of compounds G, H, and I. (b) Explain why there are four lines between 0.86 and 0.90 for compound G. (c) Explain why the 2H multiplets at 1.5 and 3.5 for compound H are so complex.arrow_forwardWhen compound A (C5H12O) is treated with HBr, it forms compound B (C5H11Br). The 1 H NMR spectrum of compound A has a 1H singlet, a 3H doublet, a 6H doublet, and two 1H multiplets. The 1 H NMR spectrum of compound B has a 6H singlet, a 3H triplet, and a 2H quartet. Identify compounds A and B.arrow_forward
- Three isomeric compounds, A, B, and C, all have molecular formulaC8H11N. The 1H NMR and IR spectral data of A, B, and C are given below.What are their structures?arrow_forwardIdentify the structure of compound C (molecular formula C11H15NO2), which has an IR absorption at 1699 cm−1 and the 1H NMR spectrum shown below.arrow_forward22. A compound with the molecular formula C8H8O produces an IR spectrum with signals at 3063, 1686, and 1646 cm-1. The 1H NMR spectrum of this compound exhibits a singlet at 2.6ppm(l=3H), and a multiplet at 7.5(l= 5H). Draw the structure and give the common name of this compound . Show the correlations between the structure and spectra.arrow_forward
- Compound A is treated with a mixture of nitric and sulfuric acids to generate Compound B. The 1H-NMR spectrum of B shows two singlets, one at 2.52 pm and one at 8.13 ppm. The 13C-NMR spectrum of B shows five signals. The mass spectrum of B shows a peak at m/z = 260 and another peak at m/z = 262; the relative height of the two peaks is 1:1 respectively. - Identify compound B, explaining your reasoningarrow_forwardOn the basis of the molecular formula, 1H NMR data, and IR data provided, propose a consistent structure. Moleculal Formula: C2H3Cl31H NMR data: δ 3.95 (d, 2H), 5.77 (t, 1H)IR data: 2950 cm–1, and several peaks below 820 cm–1.arrow_forwardAn unknown compound X has the molecular formula C6H12O2. Compound X shows a strong peak in its IR spectrum at 1700 cm-1. The 1H NMR spectral data of compound X is given below. What is the structure of compound X?arrow_forward
- How could you distinguish between these two compounds by spectroscopy? State which type you would use (IR, ¹H NMR, or 13C NMR) and what you would see for which compound. CH₂ butanal CH3arrow_forwardCompound P has molecular formula C5H9ClO2. Deduce the structure of P from its 1H and 13C NMR spectra.arrow_forwardWhat is the structure of the compound with the formula C5H12O, if it has a strong broad IR signal centered near 3330 cm-2, and the 1H-NMR spectrum is: 0.91 ppm (3H triplet) 1.19 ppm (6H singlet) 1.50 ppm (2H quartet) 2.24 ppm (1H singlet)arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning