The oxidation-reduction reaction between iron metal and aqueous permanganate ions in acidic solution is 16 H + ( aq ) + 5 Fe ( s ) + 2 MnO 4 − ( aq ) → 2 Mn 2 + ( aq ) + 5 Fe 2 + + 8 H 2 O ( l ) At some temperature, the reaction proceeds at such a rate that 1.00 millimole of H + is consumed in 2 minutes 33.8 seconds. What is the rate of this reaction in units of moles of each reactant per second and moles of each product per second? How do these answers differ from the answer in the previous problem?
The oxidation-reduction reaction between iron metal and aqueous permanganate ions in acidic solution is 16 H + ( aq ) + 5 Fe ( s ) + 2 MnO 4 − ( aq ) → 2 Mn 2 + ( aq ) + 5 Fe 2 + + 8 H 2 O ( l ) At some temperature, the reaction proceeds at such a rate that 1.00 millimole of H + is consumed in 2 minutes 33.8 seconds. What is the rate of this reaction in units of moles of each reactant per second and moles of each product per second? How do these answers differ from the answer in the previous problem?
Solution Summary: The author explains the rate of a reaction, which is defined as the speed by which the reaction is proceeding, and the stoichiometric coefficient of reactant.
The oxidation-reduction reaction between iron metal and aqueous permanganate ions in acidic solution is
16
H
+
(
aq
)
+
5
Fe
(
s
)
+
2
MnO
4
−
(
aq
)
→
2
Mn
2
+
(
aq
)
+
5
Fe
2
+
+
8
H
2
O
(
l
)
At some temperature, the reaction proceeds at such a rate that
1.00
millimole of
H
+
is consumed in
2
minutes
33.8
seconds. What is the rate of this reaction in units of moles of each reactant per second and moles of each product per second? How do these answers differ from the answer in the previous problem?
Definition Definition Chemical reactions involving both oxidation and reduction processes. During a redox reaction, electron transfer takes place in such a way that one chemical compound gets reduced and the other gets oxidized.
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.