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a. num1 = 35;
Explanation of Solution
num1 = 35; is a valid assignment as integer 35 is be...
b. newNum = num1 – num2;
Explanation of Solution
newNum = num1 – num2; is a valid assignment although the variables num1 and num2 have not been initialized. If a variable is used in an expression, the expression would yield a meaningf...
c. num1 = 5; num2 = 2 + num1; num1 = num2 / 3;
Explanation of Solution
num1 = 5; num2 = 2 + num1; num1 = num2 / 3; are valid assignments. num1 =5; declares and initializes the variable num1. num2 = 2 + num1; assigns the value of the expression 2 + num1 to num2. Since num1 has been declared and assigned a value, the right-hand expression value is 2 + 5 = 7...
d. num1 * num2 = newNum;
Explanation of Solution
num1 * num2 = newNum; is not a valid assignment as the left hand of a valid assignment is a variable and not an expression...
e. x = 12 * num1 - 15.3;
Explanation of Solution
x = 12 * num1 - 15.3; is a valid assignment although the variable num1 in the expression on the right-hand side has been declared but not initialized before being used in the expression. If a variable is used in an expression, the expression would yield a meaningful value only if the variable has first been initialized...
f. num1 * 2 = newNum + num2;
Explanation of Solution
num1 * 2 = newNum + num2; is not a valid assignment as the left hand of a valid assignment is a variable and not an expression...
g. x / y = x * y;
Explanation of Solution
x / y = x * y; is not a valid assignment as the left hand of a valid assignment is a variable and not an expression...
h. num2 = num1 % 2.0;
Explanation of Solution
num2 = num1 % 2.0; is not a valid assignment as the expression on the right-hand side would not evaluate. The expression on the right-hand si...
i. newNum = static_cast<int> (x) % 5;
Explanation of Solution
newNum = static_cast<int> (x) % 5; is a valid assignment. The double variable is explicitly cast to an int type before it participates as an oper...
j. x = x + y - 5;
Explanation of Solution
x = x + y - 5; is a valid assignment although the variables x and y have not been initialized before being used in the expression. The expression on the right side...
k. newNum = num1 + static_cast<int> (4.6 / 2);
Explanation of Solution
newNum = num1 + static_cast<int> (4.6 / 2); is a valid assignment. The expression on the right-hand side evaluates an unpredictable but int type value. The expression inside the parentheses is evaluated first where the denominator is implicitly casted to floating-point type (as the numerator is floating-point type)...
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Chapter 2 Solutions
C++ Programming: From Problem Analysis to Program Design
- oop_c++ TEST_cases(Question2_1, First) {// static Employee *SI[10]; Employee e[10],obj,**t;for(int k=0;k<10;k++){e[k].setSalary(1000+100*k); }t=obj.Temporary(e); double result=obj.print(t,e,5); ASSERT_EQ(1611,int(result));}TEST(Question2_2, second) {// static Employee *SI[10]; Employee e[10],obj,**t;for(int k=0;k<10;k++){e[k].setSalary(1000+100*k); }t=obj.Temporary(e); double result=obj.print(t,e,5); ASSERT_EQ(1640,int(result));} Double print (Employee**, Employee [], int)arrow_forwardExplain how to use the new and delete operators to manipulate dynamic variables.arrow_forwardYou have the following workspace in MATLAB: Workspace Name Value Beccentricity Egrav_const Binclination Emass_Earth Horbit_period Bradius_Earth E semi_major E spacecraft_loc 6918900 E spacecraft_vel 7.5883e+03 2.8300e-04 6.6730e-11 28.4700 5.9720e+24 95.4320 6378000 6917100 In the box below, fill in the exact command necessary to delete the variable spacecraft_vel from the workspace without deleting any other variables clear spacecraft_vel Question 2 In MATLAB, you are calculating friction forces on five rail materials for a comparison study. One variable you must define is the time traveled on the aluminum rail. Which of the following are appropriate, descriptive variable names that could be used for this variable? Select all that apply. timeAl alum time Alt U aluminum timearrow_forward
- In the C programming language, if all function prototypes are listed at the top of your code, outside and above all functions, you do not need to worry about the order of the function definitions within the code. True Falsearrow_forwardStatic_cast (8•6+Statie_cast (17)/3)=arrow_forwardin c language typedef _people { int age; char name[ 32 ] ; } People_T ; People_T data [ 3 ]; Using string lib function, Assign 30 and Cathy to the first cell, Assign 40 and John to the second cell and Assign 50 and Tom to the third cellarrow_forward
- Describe how pointers work with functions as parameters and functions as return values.arrow_forward#define _CRT_SECURE_NO_WARNINGS #include <stdio.h> #define NAME_LEN 25 #define MAX_PARTS 100 struct part { int number; char name[NAME_LEN + 1]; int on_hand; double price; } inventory[MAX_PARTS]; int num_parts = 0; int find_part(int number); void insert(void); void search(void); void update(void); void print(void); int read_line(char str[], int n); int main(void) { char code; for (;;) { printf("Enter operation code: "); scanf(" %c", &code); while (getchar() != '\n') /* skips to end of line */ ; switch (code) { case 'i': insert(); break; case 's': search(); break; case 'u': update(); break; case 'p': print(); break; case 'q': return 0; default: printf("Illegal code\n"); } printf("\n"); } } int find_part(int number) { int i; for (i = 0; i < num_parts; i++) if…arrow_forwardQuestions Question 1 How is the static_cast operator different from the dynamic_cast operator?arrow_forward
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