Essentials of Computer Organization and Architecture
Essentials of Computer Organization and Architecture
5th Edition
ISBN: 9781284123036
Author: Linda Null
Publisher: Jones & Bartlett Learning
bartleby

Concept explainers

bartleby

Videos

Expert Solution & Answer
Book Icon
Chapter 2, Problem 64E

Explanation of Solution

Computation of the hamming code:

The given code words are 0000000101111111 and 0000001010111111

Compare the given code words

00000001011111110000001010111111

The number of different bit positions is 4

Therefore, the hamming distance of the code words 0000000101111111 and 0000001010111111 is 4.

The given code words are 0000000101111111 and 0000010011011111

Compare the given code words

00000001011111110000010011011111

The number of different bit positions is 4

Therefore, the hamming distance of the code words 0000000101111111 and 0000010011011111 is 4.

The given code words are 0000000101111111 and 0000100011101111

Compare the given code words

00000001011111110000100011101111

The number of different bit positions is 4

Therefore, the hamming distance of the code words 0000000101111111 and 0000100011101111 is 4.

The given code words are 0000000101111111 and 0001000011110111

Compare the given code words

00000001011111110001000011110111

The number of different bit positions is 4

Therefore, the hamming distance of the code words 0000000101111111 and 0001000011110111 is 4.

The given code words are 0000000101111111 and 0010000011111011

Compare the given code words

00000001011111110010000011111011

The number of different bit positions is 4

Therefore, the hamming distance of the code words 0000000101111111 and 0010000011111011 is 4.

The given code words are 0000000101111111 and 0100000011111101

Compare the given code words

00000001011111110100000011111101

The number of different bit positions is 4

Therefore, the hamming distance of the code words 0000000101111111 and 0100000011111101 is 4.

The given code words are 0000000101111111 and 1000000011111110

Compare the given code words

00000001011111111000000011111110

The number of different bit positions is 4

Therefore, the hamming distance of the code words 0000000101111111 and 1000000011111110 is 4.

The given code words are 0000001010111111 and 0000010011011111

Compare the given code words

00000010101111110000010011011111

The number of different bit positions is 4

Therefore, the hamming distance of the code words 0000001010111111 and 0000010011011111 is 4.

The given code words are 0000001010111111 and 0000100011101111

Compare the given code words

00000010101111110000100011101111

The number of different bit positions is 4

Therefore, the hamming distance of the code words 0000001010111111 and 0000100011101111 is 4.

The given code words are 0000001010111111 and 0001000011110111

Compare the given code words

00000010101111110001000011110111

The number of different bit positions is 4

Therefore, the hamming distance of the code words 0000001010111111 and 0001000011110111 is 4.

The given code words are 0000001010111111 and 0010000011111011

Compare the given code words

00000010101111110010000011111011

The number of different bit positions is 4

Therefore, the hamming distance of the code words 0000001010111111 and 0010000011111011 is 4.

The given code words are 0000001010111111 and 0100000011111101

Compare the given code words

00000010101111110100000011111101

The number of different bit positions is 4

Therefore, the hamming distance of the code words 0000001010111111 and 0100000011111101 is 4.

The given code words are 0000001010111111 and 1000000011111110

Compare the given code words

00000010101111111000000011111110

The number of different bit positions is 4

Therefore, the hamming distance of the code words 0000001010111111 and 1000000011111110 is 4.

The given code words are 0000010011011111 and 0000100011101111

Compare the given code words

00000100110111110000100011101111

The number of different bit positions is 4

Therefore, the hamming distance of the code words 0000010011011111 and 0000100011101111 is 4

Blurred answer
Students have asked these similar questions
What are the major threats of using the internet? How do you use it? How do children use it? How canwe secure it? Provide four references with your answer. Two of the refernces can be from an article and the other two from websites.
Assume that a string of name & surname is saved in S. The alphabetical characters in S can be in lowercase and/or uppercase letters. Name and surname are assumed to be separated by a space character and the string ends with a full stop "." character. Write an assembly language program that will copy the name to NAME in lowercase and the surname to SNAME in uppercase letters. Assume that name and/or surname cannot exceed 20 characters. The program should be general and work with every possible string with name & surname. However, you can consider the data segment definition given below in your program. .DATA S DB 'Mahmoud Obaid." NAME DB 20 DUP(?) SNAME DB 20 DUP(?) Hint: Uppercase characters are ordered between 'A' (41H) and 'Z' (5AH) and lowercase characters are ordered between 'a' (61H) and 'z' (7AH) in the in the ASCII Code table. For lowercase letters, bit 5 (d5) of the ASCII code is 1 where for uppercase letters it is 0. For example, Letter 'h' Binary ASCII 01101000 68H 'H'…
What did you find most interesting or surprising about the scientist Lavoiser?

Chapter 2 Solutions

Essentials of Computer Organization and Architecture

Ch. 2 - Prob. 11RETCCh. 2 - Prob. 12RETCCh. 2 - Prob. 13RETCCh. 2 - Prob. 14RETCCh. 2 - Prob. 15RETCCh. 2 - Prob. 16RETCCh. 2 - Prob. 17RETCCh. 2 - Prob. 18RETCCh. 2 - Prob. 19RETCCh. 2 - Prob. 20RETCCh. 2 - Prob. 21RETCCh. 2 - Prob. 22RETCCh. 2 - Prob. 23RETCCh. 2 - Prob. 24RETCCh. 2 - Prob. 25RETCCh. 2 - Prob. 26RETCCh. 2 - Prob. 27RETCCh. 2 - Prob. 28RETCCh. 2 - Prob. 29RETCCh. 2 - Prob. 30RETCCh. 2 - Prob. 31RETCCh. 2 - Prob. 32RETCCh. 2 - Prob. 33RETCCh. 2 - Prob. 34RETCCh. 2 - Prob. 1ECh. 2 - Prob. 2ECh. 2 - Prob. 3ECh. 2 - Prob. 4ECh. 2 - Prob. 5ECh. 2 - Prob. 6ECh. 2 - Prob. 7ECh. 2 - Prob. 8ECh. 2 - Prob. 9ECh. 2 - Prob. 10ECh. 2 - Prob. 11ECh. 2 - Prob. 12ECh. 2 - Prob. 13ECh. 2 - Prob. 14ECh. 2 - Prob. 15ECh. 2 - Prob. 16ECh. 2 - Prob. 17ECh. 2 - Prob. 18ECh. 2 - Prob. 19ECh. 2 - Prob. 20ECh. 2 - Prob. 21ECh. 2 - Prob. 22ECh. 2 - Prob. 23ECh. 2 - Prob. 24ECh. 2 - Prob. 25ECh. 2 - Prob. 26ECh. 2 - Prob. 27ECh. 2 - Prob. 29ECh. 2 - Prob. 30ECh. 2 - Prob. 31ECh. 2 - Prob. 32ECh. 2 - Prob. 33ECh. 2 - Prob. 34ECh. 2 - Prob. 35ECh. 2 - Prob. 36ECh. 2 - Prob. 37ECh. 2 - Prob. 38ECh. 2 - Prob. 39ECh. 2 - Prob. 40ECh. 2 - Prob. 41ECh. 2 - Prob. 42ECh. 2 - Prob. 43ECh. 2 - Prob. 44ECh. 2 - Prob. 45ECh. 2 - Prob. 46ECh. 2 - Prob. 47ECh. 2 - Prob. 48ECh. 2 - Prob. 49ECh. 2 - Prob. 50ECh. 2 - Prob. 51ECh. 2 - Prob. 52ECh. 2 - Prob. 53ECh. 2 - Prob. 54ECh. 2 - Prob. 55ECh. 2 - Prob. 56ECh. 2 - Prob. 57ECh. 2 - Prob. 58ECh. 2 - Prob. 59ECh. 2 - Prob. 60ECh. 2 - Prob. 61ECh. 2 - Prob. 62ECh. 2 - Prob. 63ECh. 2 - Prob. 64ECh. 2 - Prob. 65ECh. 2 - Prob. 66ECh. 2 - Prob. 67ECh. 2 - Prob. 68ECh. 2 - Prob. 69ECh. 2 - Prob. 70ECh. 2 - Prob. 71ECh. 2 - Prob. 72ECh. 2 - Prob. 73ECh. 2 - Prob. 74ECh. 2 - Prob. 75ECh. 2 - Prob. 76ECh. 2 - Prob. 77ECh. 2 - Prob. 78ECh. 2 - Prob. 79ECh. 2 - Prob. 80ECh. 2 - Prob. 81ECh. 2 - Prob. 82E
Knowledge Booster
Background pattern image
Computer Science
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Database System Concepts
Computer Science
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:McGraw-Hill Education
Text book image
Starting Out with Python (4th Edition)
Computer Science
ISBN:9780134444321
Author:Tony Gaddis
Publisher:PEARSON
Text book image
Digital Fundamentals (11th Edition)
Computer Science
ISBN:9780132737968
Author:Thomas L. Floyd
Publisher:PEARSON
Text book image
C How to Program (8th Edition)
Computer Science
ISBN:9780133976892
Author:Paul J. Deitel, Harvey Deitel
Publisher:PEARSON
Text book image
Database Systems: Design, Implementation, & Manag...
Computer Science
ISBN:9781337627900
Author:Carlos Coronel, Steven Morris
Publisher:Cengage Learning
Text book image
Programmable Logic Controllers
Computer Science
ISBN:9780073373843
Author:Frank D. Petruzella
Publisher:McGraw-Hill Education
Control Structure in Data Structure - Data Structures - Computer Science Class 12; Author: Ekeeda;https://www.youtube.com/watch?v=9FTw2pXLhv4;License: Standard YouTube License, CC-BY