Essentials of Computer Organization and Architecture
Essentials of Computer Organization and Architecture
5th Edition
ISBN: 9781284123036
Author: Linda Null
Publisher: Jones & Bartlett Learning
Expert Solution & Answer
Book Icon
Chapter 2, Problem 3E

Explanation of Solution

a)

Converting 137 base 10 to base 3 using subtraction method:

Step 1:

Check the possibility of multiplying any integer with the powers of 3 which may result in lower number than 137. The number that can be subtracted from the given number 137 with the power of 3 is 81. The number 81 is less than 137. So subtract 81 from 137.

137-81=34x1------------56

Step 2:

The number that can be subtracted from the given number 56 with the power of 3 is 27 and it should be multiplied by 2 in order to get the nearest number of 56. The number 54 is less than 56. So subtract 56 from 54.

56-54=33x2------------2

Step 3:

Take 3 to the power of 2 that is 9. The number 9 is greater than 2. So make the value as 0.

2-0=32x0------------2

Step 4:

Take 3 to power of 1 that is 3

Explanation of Solution

b)

Converting 248 base 10 to base 5 using subtraction method:

Step 1:

Check the possibility of multiplying any integer with the powers of 5 which may result in lower number than 248. The number that can be subtracted from the given number 248 with the power of 5 is 125. The number 125 is less than 248. So subtract 125 from 248.

248-125=53x1------------123

Step 2:

The number that can be subtracted from the given number 123 with the power of 5 is 25 and it should be multiplied by 4 in order to get the nearest number of 123. The number 100 is less than 123. So subtract 100 from 123.

123-100=52x4------------23

Step 3:

The number that can be subtracted from the given number 23 with the power of 5 is 5 and it should be multiplied by 4 in order to get the nearest number of 23

Explanation of Solution

c)

Converting 387 base 10 to base 7 using subtraction method:

Step 1:

Check the possibility of multiplying any integer with the powers of 7 which may result in lower number than 387. The number that can be subtracted from the given number 387 with the power of 7 is 343. The number 343 is less than 387. So subtract 343 from 387.

387-343=73x1------------44

Step 2:

Take 7 to power of 2 that is 49. The number 49 is greater than 44. So make the value as 0.

44-0=72x0------------44

Step 3:

The number that can be subtracted from the given number 44 with the power of 7 is 7 and it should be multiplied by 6 in order to get the nearest number of 44. The number 42 is less than 44. So subtract 42 from 44

Explanation of Solution

d)

Converting 633 base 10 to base 9 using subtraction method:

Step 1:

Check the possibility of multiplying any integer with the powers of 9 which may result in lower number than 633. The number that can be subtracted from the given number 633 with the power of 9 is 81 and it should be multiplied by 7 in order to get the nearest number of 633. The number 567 is less than 633. So subtract 567 from 633.

633-567=92x7------------66

Step 2:

The number that can be subtracted from the given number 66 with the power of 9 is 9 and it should be multiplied by 7 in order to get the nearest number of 66. The number 63 is less than 66. So subtract 63 from 66

Blurred answer
Students have asked these similar questions
What are the major threats of using the internet? How do you use it? How do children use it? How canwe secure it? Provide four references with your answer. Two of the refernces can be from an article and the other two from websites.
Assume that a string of name & surname is saved in S. The alphabetical characters in S can be in lowercase and/or uppercase letters. Name and surname are assumed to be separated by a space character and the string ends with a full stop "." character. Write an assembly language program that will copy the name to NAME in lowercase and the surname to SNAME in uppercase letters. Assume that name and/or surname cannot exceed 20 characters. The program should be general and work with every possible string with name & surname. However, you can consider the data segment definition given below in your program. .DATA S DB 'Mahmoud Obaid." NAME DB 20 DUP(?) SNAME DB 20 DUP(?) Hint: Uppercase characters are ordered between 'A' (41H) and 'Z' (5AH) and lowercase characters are ordered between 'a' (61H) and 'z' (7AH) in the in the ASCII Code table. For lowercase letters, bit 5 (d5) of the ASCII code is 1 where for uppercase letters it is 0. For example, Letter 'h' Binary ASCII 01101000 68H 'H'…
What did you find most interesting or surprising about the scientist Lavoiser?

Chapter 2 Solutions

Essentials of Computer Organization and Architecture

Ch. 2 - Prob. 11RETCCh. 2 - Prob. 12RETCCh. 2 - Prob. 13RETCCh. 2 - Prob. 14RETCCh. 2 - Prob. 15RETCCh. 2 - Prob. 16RETCCh. 2 - Prob. 17RETCCh. 2 - Prob. 18RETCCh. 2 - Prob. 19RETCCh. 2 - Prob. 20RETCCh. 2 - Prob. 21RETCCh. 2 - Prob. 22RETCCh. 2 - Prob. 23RETCCh. 2 - Prob. 24RETCCh. 2 - Prob. 25RETCCh. 2 - Prob. 26RETCCh. 2 - Prob. 27RETCCh. 2 - Prob. 28RETCCh. 2 - Prob. 29RETCCh. 2 - Prob. 30RETCCh. 2 - Prob. 31RETCCh. 2 - Prob. 32RETCCh. 2 - Prob. 33RETCCh. 2 - Prob. 34RETCCh. 2 - Prob. 1ECh. 2 - Prob. 2ECh. 2 - Prob. 3ECh. 2 - Prob. 4ECh. 2 - Prob. 5ECh. 2 - Prob. 6ECh. 2 - Prob. 7ECh. 2 - Prob. 8ECh. 2 - Prob. 9ECh. 2 - Prob. 10ECh. 2 - Prob. 11ECh. 2 - Prob. 12ECh. 2 - Prob. 13ECh. 2 - Prob. 14ECh. 2 - Prob. 15ECh. 2 - Prob. 16ECh. 2 - Prob. 17ECh. 2 - Prob. 18ECh. 2 - Prob. 19ECh. 2 - Prob. 20ECh. 2 - Prob. 21ECh. 2 - Prob. 22ECh. 2 - Prob. 23ECh. 2 - Prob. 24ECh. 2 - Prob. 25ECh. 2 - Prob. 26ECh. 2 - Prob. 27ECh. 2 - Prob. 29ECh. 2 - Prob. 30ECh. 2 - Prob. 31ECh. 2 - Prob. 32ECh. 2 - Prob. 33ECh. 2 - Prob. 34ECh. 2 - Prob. 35ECh. 2 - Prob. 36ECh. 2 - Prob. 37ECh. 2 - Prob. 38ECh. 2 - Prob. 39ECh. 2 - Prob. 40ECh. 2 - Prob. 41ECh. 2 - Prob. 42ECh. 2 - Prob. 43ECh. 2 - Prob. 44ECh. 2 - Prob. 45ECh. 2 - Prob. 46ECh. 2 - Prob. 47ECh. 2 - Prob. 48ECh. 2 - Prob. 49ECh. 2 - Prob. 50ECh. 2 - Prob. 51ECh. 2 - Prob. 52ECh. 2 - Prob. 53ECh. 2 - Prob. 54ECh. 2 - Prob. 55ECh. 2 - Prob. 56ECh. 2 - Prob. 57ECh. 2 - Prob. 58ECh. 2 - Prob. 59ECh. 2 - Prob. 60ECh. 2 - Prob. 61ECh. 2 - Prob. 62ECh. 2 - Prob. 63ECh. 2 - Prob. 64ECh. 2 - Prob. 65ECh. 2 - Prob. 66ECh. 2 - Prob. 67ECh. 2 - Prob. 68ECh. 2 - Prob. 69ECh. 2 - Prob. 70ECh. 2 - Prob. 71ECh. 2 - Prob. 72ECh. 2 - Prob. 73ECh. 2 - Prob. 74ECh. 2 - Prob. 75ECh. 2 - Prob. 76ECh. 2 - Prob. 77ECh. 2 - Prob. 78ECh. 2 - Prob. 79ECh. 2 - Prob. 80ECh. 2 - Prob. 81ECh. 2 - Prob. 82E
Knowledge Booster
Background pattern image
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Database System Concepts
Computer Science
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:McGraw-Hill Education
Text book image
Starting Out with Python (4th Edition)
Computer Science
ISBN:9780134444321
Author:Tony Gaddis
Publisher:PEARSON
Text book image
Digital Fundamentals (11th Edition)
Computer Science
ISBN:9780132737968
Author:Thomas L. Floyd
Publisher:PEARSON
Text book image
C How to Program (8th Edition)
Computer Science
ISBN:9780133976892
Author:Paul J. Deitel, Harvey Deitel
Publisher:PEARSON
Text book image
Database Systems: Design, Implementation, & Manag...
Computer Science
ISBN:9781337627900
Author:Carlos Coronel, Steven Morris
Publisher:Cengage Learning
Text book image
Programmable Logic Controllers
Computer Science
ISBN:9780073373843
Author:Frank D. Petruzella
Publisher:McGraw-Hill Education