Intro Stats, Books a la carte Plus NEW MyLab Statistics with Pearson eText -- Access Card Package (5th Edition)
5th Edition
ISBN: 9780134210247
Author: Richard D. De Veaux, Paul Velleman, David E. Bock
Publisher: PEARSON
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Chapter 2, Problem 5E
To determine
Match each pie chart with the correct year of bar chart.
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Teenage obesity (O), and weekly fast-food meals (F), among some selected Mississippi teenagers are:
Name Obesity (lbs) # of Fast-foods per week
Josh
185
10
Karl
172
8
Terry
168
9
Kamie
Andy
204
154
12
6
(a) Compute the variance of Obesity, s²o, and the variance of fast-food meals, s², of this data. [Must show full work].
(b) Compute the Correlation Coefficient between O and F. [Must show full work].
(c) Find the Coefficient of Determination between O and F. [Must show full work].
(d) Obtain the Regression equation of this data. [Must show full work].
(e) Interpret your answers in (b), (c), and (d). (Full explanations required).
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The average miles per gallon for a sample of 40 cars of model SX last year was 32.1, with a population standard deviation of 3.8. A sample of 40 cars from this year’s model SX has an average of 35.2 mpg, with a population standard deviation of 5.4.
Find a 99 percent confidence interval for the difference in average mpg for this car brand (this year’s model minus last year’s).Find a 99 percent confidence interval for the difference in average mpg for last year’s model minus this year’s. What does the negative difference mean?
A special interest group reports a tiny margin of error (plus or minus 0.04 percent) for its online survey based on 50,000 responses. Is the margin of error legitimate? (Assume that the group’s math is correct.)
Chapter 2 Solutions
Intro Stats, Books a la carte Plus NEW MyLab Statistics with Pearson eText -- Access Card Package (5th Edition)
Ch. 2.3 - You may be surprised to find that you already have...Ch. 2.3 - You may be surprised to find that you already have...Ch. 2.3 - You may be surprised to find that you already have...Ch. 2.3 - Prob. 4JCCh. 2.3 - Prob. 5JCCh. 2.5 - The U.S. Census Bureau reports the median family...Ch. 2.5 - Prob. 7JCCh. 2.5 - Prob. 8JCCh. 2 - SECTION 2.1 1. Automobile fatalities The table...Ch. 2 - Nonoccupant fatalities The frequencies of traffic...
Ch. 2 - Prob. 3ECh. 2 - Movie ratings The Motion Picture Association of...Ch. 2 - Prob. 5ECh. 2 - Marriage in decline Changing attitudes about...Ch. 2 - Traffic fatalities 2013 Here are two histograms...Ch. 2 - Prob. 8ECh. 2 - Prob. 9ECh. 2 - Prob. 10ECh. 2 - E-mails A university teacher saved every e-mail...Ch. 2 - Adoptions The U.S. Census Bureau keeps track of...Ch. 2 - Biceps revisited Describe the shape of the...Ch. 2 - E-mails II For the distribution of e-mails sent by...Ch. 2 - Life expectancy Here are the life expectancies at...Ch. 2 - Prob. 16ECh. 2 - Life expectancy II For the 146 life expectancies...Ch. 2 - Adoptions II For the number of adoptions in...Ch. 2 - How big is your bicep II? For the bicep...Ch. 2 - Shoe sizes II For the shoe sizes in Exercise 16,...Ch. 2 - SECTION 2.5 21. Life expectancy III For the 190...Ch. 2 - Prob. 22ECh. 2 - How big is your bicep III? For the bicep...Ch. 2 - Prob. 24ECh. 2 - Thinking about shape Would you expect...Ch. 2 - More shapes Would you expect distributions of...Ch. 2 - Movie genres again Here is a bar chart summarizing...Ch. 2 - Prob. 36ECh. 2 - Prob. 37ECh. 2 - Prob. 38ECh. 2 - Prob. 39ECh. 2 - Prob. 40ECh. 2 - Prob. 41ECh. 2 - Prob. 42ECh. 2 - Prob. 43ECh. 2 - Modalities A survey of athletic trainers asked...Ch. 2 - Cereals The histogram shows the carbohydrate...Ch. 2 - Run times One of the authors collected the times...Ch. 2 - Heart attack stays The histogram shows the lengths...Ch. 2 - Bird species 2013 The Cornell Lab of Ornithology...Ch. 2 - Super Bowl points 2016 How many points do football...Ch. 2 - Prob. 50ECh. 2 - Test scores, large class Test scores from a large...Ch. 2 - Prob. 52ECh. 2 - Mistake A clerk entering salary data into a...Ch. 2 - Sick days During contract negotiations, a company...Ch. 2 - Prob. 55ECh. 2 - Tornadoes 2015 Here are the annual numbers of...Ch. 2 - Prob. 57ECh. 2 - Tornadoes 2015 II Using the data from Exercise 56,...Ch. 2 - Pizza prices The histogram shows the distribution...Ch. 2 - Neck size The histogram shows the neck sizes (in...Ch. 2 - Pizza prices again Look again at the histogram of...Ch. 2 - Neck sizes again Look again at the histogram of...Ch. 2 - Movie lengths 2010 The histogram shows the running...Ch. 2 - Golf drives 2015 The display shows the average...Ch. 2 - Prob. 65ECh. 2 - Golf drives II 2015 Exercise 64 looked at...Ch. 2 - Prob. 67ECh. 2 - Cold weather A meteorologist preparing a talk...Ch. 2 - Gasoline 2014 In January 2014, 16 gas stations in...Ch. 2 - The great one During his 20 seasons in the NHL,...Ch. 2 - Prob. 71ECh. 2 - Prob. 72ECh. 2 - Prob. 73ECh. 2 - Prob. 74ECh. 2 - Prob. 75ECh. 2 - Prob. 76ECh. 2 - Acid rain Two researchers measured the pH (a scale...Ch. 2 - Marijuana 2015 In 2015 the Council of Europe...Ch. 2 - Prob. 79ECh. 2 - Prob. 80ECh. 2 - Prob. 81ECh. 2 - ZIP codes revisited Here are some summary...Ch. 2 - Prob. 83ECh. 2 - Prob. 84ECh. 2 - Prob. 85E
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- Suppose that 73 percent of a sample of 1,000 U.S. college students drive a used car as opposed to a new car or no car at all. Find an 80 percent confidence interval for the percentage of all U.S. college students who drive a used car.What sample size would cut this margin of error in half?arrow_forwardYou want to compare the average number of tines on the antlers of male deer in two nearby metro parks. A sample of 30 deer from the first park shows an average of 5 tines with a population standard deviation of 3. A sample of 35 deer from the second park shows an average of 6 tines with a population standard deviation of 3.2. Find a 95 percent confidence interval for the difference in average number of tines for all male deer in the two metro parks (second park minus first park).Do the parks’ deer populations differ in average size of deer antlers?arrow_forwardSuppose that you want to increase the confidence level of a particular confidence interval from 80 percent to 95 percent without changing the width of the confidence interval. Can you do it?arrow_forward
- A random sample of 1,117 U.S. college students finds that 729 go home at least once each term. Find a 98 percent confidence interval for the proportion of all U.S. college students who go home at least once each term.arrow_forwardSuppose that you make two confidence intervals with the same data set — one with a 95 percent confidence level and the other with a 99.7 percent confidence level. Which interval is wider?Is a wide confidence interval a good thing?arrow_forwardIs it true that a 95 percent confidence interval means you’re 95 percent confident that the sample statistic is in the interval?arrow_forward
- Tines can range from 2 to upwards of 50 or more on a male deer. You want to estimate the average number of tines on the antlers of male deer in a nearby metro park. A sample of 30 deer has an average of 5 tines, with a population standard deviation of 3. Find a 95 percent confidence interval for the average number of tines for all male deer in this metro park.Find a 98 percent confidence interval for the average number of tines for all male deer in this metro park.arrow_forwardBased on a sample of 100 participants, the average weight loss the first month under a new (competing) weight-loss plan is 11.4 pounds with a population standard deviation of 5.1 pounds. The average weight loss for the first month for 100 people on the old (standard) weight-loss plan is 12.8 pounds, with population standard deviation of 4.8 pounds. Find a 90 percent confidence interval for the difference in weight loss for the two plans( old minus new) Whats the margin of error for your calculated confidence interval?arrow_forwardA 95 percent confidence interval for the average miles per gallon for all cars of a certain type is 32.1, plus or minus 1.8. The interval is based on a sample of 40 randomly selected cars. What units represent the margin of error?Suppose that you want to decrease the margin of error, but you want to keep 95 percent confidence. What should you do?arrow_forward
- 3. (i) Below is the R code for performing a X2 test on a 2×3 matrix of categorical variables called TestMatrix: chisq.test(Test Matrix) (a) Assuming we have a significant result for this procedure, provide the R code (including any required packages) for an appropriate post hoc test. (b) If we were to apply this technique to a 2 × 2 case, how would we adapt the code in order to perform the correct test? (ii) What procedure can we use if we want to test for association when we have ordinal variables? What code do we use in R to do this? What package does this command belong to? (iii) The following code contains the initial steps for a scenario where we are looking to investigate the relationship between age and whether someone owns a car by using frequencies. There are two issues with the code - please state these. Row3<-c(75,15) Row4<-c(50,-10) MortgageMatrix<-matrix(c(Row1, Row4), byrow=T, nrow=2, MortgageMatrix dimnames=list(c("Yes", "No"), c("40 or older","<40")))…arrow_forwardDescribe the situation in which Fisher’s exact test would be used?(ii) When do we use Yates’ continuity correction (with respect to contingencytables)?[2 Marks] 2. Investigate, checking the relevant assumptions, whether there is an associationbetween age group and home ownership based on the sample dataset for atown below:Home Owner: Yes NoUnder 40 39 12140 and over 181 59Calculate and evaluate the effect size.arrow_forwardNot use ai pleasearrow_forward
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