Chapter 2, Problem 57QAP

To determine

(1)

The acceleration in unit of meter per second square for Bugatti Veyron car.

Answer to Problem 57QAP

The acceleration for Bugatti Veyron 16.4 caris $11.2{\text{ms}}^{\text{-2}}$.

Explanation of Solution

Given info:

• The initial speed and final speed of the car is $0{\text{mih}}^{\text{-1}}$and $60{\text{mih}}^{\text{-1}}$.

Convert miles per hour into kilometer per hour.

  $\begin{array}{c}60{\text{mih}}^{\text{-1}}=60{\text{mih}}^{\text{-1}}\times \frac{\text{1}\text{.60934}\text{km}}{\text{1}\text{mi}}\\ =96.56{\text{kmh}}^{\text{-1}}\end{array}$

Next convert kilometer per hour to meter per second.

  $\begin{array}{c}96.56{\text{kmh}}^{\text{-1}}=96.56{\text{kmh}}^{\text{-1}}\times \frac{\text{1}\text{h}}{\text{3600}\text{s}}\text{×}\frac{\text{1000}\text{m}}{\text{1}\text{km}}\\ =26.82{\text{ms}}^{\text{-1}}\end{array}$

• The time of travel is $2.4\text{s}$.

Formula used:

Use first equation of motion to find the acceleration.

  $\begin{array}{l}v=u+at\\ a=\frac{v-u}{t}\text{Equation-1}\end{array}$

Here, $v$ is the finalvelocity $u$ is the initial velocity and $t$ is the time interval.

Calculation:

Finding the acceleration for Bugatti Veyron:

Substituting the all known values in equation-1 to find acceleration,

  $\begin{array}{c}{a}_1=\frac{{\left(26.82{\text{ms}}^{\text{-1}}\right)}^2-{\left(0{\text{ms}}^{\text{-1}}\right)}^2}{2.4\text{s}}\\ =11.2{\text{ms}}^{\text{-2}}\text{Equation-2}\end{array}$

Conclusion:

From equation-2the acceleration for Bugatti Veyron 16.4 caris $11.2{\text{ms}}^{\text{-2}}$.

To determine

(2)

The acceleration in unit of meter per second square for capro T1 car.

Answer to Problem 57QAP

The acceleration for capro T1 caris $10.7{\text{ms}}^{\text{-2}}$.

Explanation of Solution

Given info:

• The initial speed and final speed of the car is $0{\text{ms}}^{\text{-1}}$and $26.82{\text{ms}}^{\text{-1}}$.
• The time of travel is $2.5\text{s}$.

Formula used:

Use first equation of motion to find the acceleration.

  $\begin{array}{l}v=u+at\\ a=\frac{v-u}{t}\text{Equation-1}\end{array}$

Here, $v$ is the finalvelocity $u$ is the initial velocity and $t$ is the time interval.

Calculation:

Finding the acceleration for capro T1:

Substituting the all known values in equation-1 to find acceleration,

  $\begin{array}{c}{a}_2=\frac{{\left(26.82{\text{ms}}^{\text{-1}}\right)}^2-{\left(0{\text{ms}}^{\text{-1}}\right)}^2}{2.5\text{s}}\\ =10.7{\text{ms}}^{\text{-2}}\text{Equation-3}\end{array}$

Conclusion:

From equation-3 the acceleration for capro T1 caris $10.7{\text{ms}}^{\text{-2}}$.

To determine

(3)

The acceleration in unit of meter per second square for Ultima GTR.

Answer to Problem 57QAP

The acceleration for Ultima GTR caris $10.3{\text{ms}}^{\text{-2}}$.

Explanation of Solution

Given info:

• The initial speed and final speed of the car is $0{\text{ms}}^{\text{-1}}$and $26.82{\text{ms}}^{\text{-1}}$.
• The time of travel is $2.6\text{s}$.

Formula used:

Use first equation of motion to find the acceleration.

  $\begin{array}{l}v=u+at\\ a=\frac{v-u}{t}\text{Equation-1}\end{array}$

Here, $v$ is the finalvelocity $u$ is the initial velocity and $t$ is the time interval.

Calculation:

Finding the acceleration for Ultima GTR:

Substituting the all known values in equation-1 to find acceleration,

  $\begin{array}{c}{a}_3=\frac{{\left(26.82{\text{ms}}^{\text{-1}}\right)}^2-{\left(0{\text{ms}}^{\text{-1}}\right)}^2}{2.6\text{s}}\\ =10.3{\text{ms}}^{\text{-2}}\text{Equation-4}\end{array}$

Conclusion:

From equation-3 the acceleration for Ultima GTR caris $10.3{\text{ms}}^{\text{-2}}$.

To determine

(4)

The acceleration in unit of meter per second square for SSC Ultimate Aero TT.

Answer to Problem 57QAP

The acceleration for SSC Ultimate Aero TT caris $9.93{\text{ms}}^{\text{-2}}$.

Explanation of Solution

Given info:

• The initial speed and final speed of the car is $0{\text{ms}}^{\text{-1}}$and $26.82{\text{ms}}^{\text{-1}}$.
• The time of travel is $2.7\text{s}$.

Formula used:

Use first equation of motion to find the acceleration.

  $\begin{array}{l}v=u+at\\ a=\frac{v-u}{t}\text{Equation-1}\end{array}$

Here, $v$ is the finalvelocity $u$ is the initial velocity and $t$ is the time interval.

Calculation:

Finding the acceleration for SSC Ultimate Aero TT:

Substituting the all known values in equation-1 to find acceleration,

  $\begin{array}{c}{a}_4=\frac{{\left(26.82{\text{ms}}^{\text{-1}}\right)}^2-{\left(0{\text{ms}}^{\text{-1}}\right)}^2}{2.7\text{s}}\\ =9.93{\text{ms}}^{\text{-2}}\text{Equation-4}\end{array}$

Conclusion:

From equation-3 the acceleration for SSC Ultimate Aero TT caris $9.93{\text{ms}}^{\text{-2}}$.

To determine

(5)

The acceleration in unit of meter per second square for Saleen S7 twin turbo.

Answer to Problem 57QAP

The acceleration for Saleen S7 twin turbo caris $9.93{\text{ms}}^{\text{-2}}$.

Explanation of Solution

Given info:

• The initial speed and final speed of the car is $0{\text{ms}}^{\text{-1}}$and $26.82{\text{ms}}^{\text{-1}}$.
• The time of travel is $2.8\text{s}$.

Formula used:

Use first equation of motion to find the acceleration.

  $\begin{array}{l}v=u+at\\ a=\frac{v-u}{t}\text{Equation-1}\end{array}$

Here, $v$ is the finalvelocity $u$ is the initial velocity and $t$ is the time interval.

Calculation:

Finding the acceleration for Saleen S7 twin turbo:

Substituting the all known values in equation-1 to find acceleration,

  $\begin{array}{c}{a}_5=\frac{{\left(26.82{\text{ms}}^{\text{-1}}\right)}^2-{\left(0{\text{ms}}^{\text{-1}}\right)}^2}{2.8\text{s}}\\ =9.58{\text{ms}}^{\text{-2}}\text{Equation-5}\end{array}$

Conclusion:

From equation-3 the acceleration for Saleen S7 twin turbo caris $9.58{\text{ms}}^{\text{-2}}$.