COLLEGE PHYSICS
COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 2, Problem 55QAP
To determine

(a)

The magnitude of constant acceleration for the given interval of time.

Expert Solution
Check Mark

Answer to Problem 55QAP

The magnitude of acceleration for the first five second is 0.5556ms-2. The magnitude of acceleration for the next five second is 0.5566ms-2.

Explanation of Solution

Given info:

  • The initial speed speed and final speed of the car is 35kmh-1and 45kmh-1for the first 5s.
  • Convert kilometer per hour to meter per second.
  •   35km/h=35kmh×1000m1km×1h3600s=9.722m/s45km/h=45kmh×1000m1km×1h3600s=12.5m/s

  • The initial speed speed and final speed of the car is 65kmh-1and 75kmh-1for the next 5s.
  • Convert kilometer per hour to meter per second.

      65km/h=65kmh×1000m1km×1h3600s=18.05m/s75km/h=75kmh×1000m1km×1h3600s=20.833m/s

Formula used:

Use first equation of motion to find the acceleration.

  v=u+ata=vut Equation-1

Here, v is the finalvelocity u is the initial velocity and t is the time interval.

Calculation:

Finding the acceleration:

For first 5s :

Substituting the all known values in equation-1 to find acceleration,

  a1= ( 12.5 ms -1 )2 ( 9.722 ms -1 )25s=0.5556ms-2 Equation-2

For Last 5s :

Substituting the all known values in equation-1 to find acceleration,

  a2= ( 20.833 ms -1 )2 ( 18.05 ms -1 )25s=0.5566ms-2 Equation-3

Conclusion:

From equation-3 and 4 magnitude of acceleration for the first five second is 0.5556ms-2. The magnitude of acceleration for the next five second is 0.5566ms-2.

To determine

(b)

The magnitude of constant acceleration for the given interval of time.

Expert Solution
Check Mark

Answer to Problem 55QAP

The magnitude of acceleration for the first five second is 0.5556ms-2. The magnitude of acceleration for the next five second is 0.5566ms-2.

Explanation of Solution

Given info:

  • The initial speed speed and final speed of the car is 9.722ms-1and 12.5ms-1for the first 5s.
  • The initial speed speed and final speed of the car is 18.05ms-1and 20.833ms-1for the next 5s.
  • Magnitude of acceleration for the first five second is 0.5556ms-2. The magnitude of acceleration for the next five second is 0.5566ms-2.

Formula used:

Use third equation of motion to find the distance travelled.

  v2=u2+2ass=v2u22a Equation-4

Here, v is the finalvelocity u is the initial velocity and a is the acceleration.

Calculation:

Finding the distance travelled:

For first 5s :

Substituting the all known values in equation-2 to find distance,

  s1= ( 12.5 ms -1 )2 ( 9.722 ms -1 )22×0.5556 ms 2=55.5m Equation-5s1= ( 20.833 ms -1 )2 ( 18.05 ms -1 )22×0.5566 ms 2=97.2m Equation-6

For Last 5s :

Substituting the all known values in equation-1 to find acceleration,

Conclusion:

From equation-5 and 6distance travelledin the first five second is 55.5m. The magnitude of acceleration for the next five second is 97.2m.

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