INTRO.TO COMPUTING SYSTEMS >INTL.ED.<
INTRO.TO COMPUTING SYSTEMS >INTL.ED.<
3rd Edition
ISBN: 9781260565911
Author: PATT
Publisher: MCG
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Chapter 2, Problem 40E

a.

Explanation of Solution

Decimal equivalent for “0 10000000 00000000000000000000000”:

  • The given floating point number is “0 10000000 00000000000000000000000”.
  • The LSB is “0” and this denotes a positive number.
  • The next eight bits denotes the unsigned integer “128”.
  • If “127” is subtracted from “128”, then the actual exponent is “1”.
  • The next “23” bits in the fraction field contains “0”.
  • Therefore, the decimal number being expressed is “+1

b.

Explanation of Solution

Decimal equivalent for “1 10000011 00010000000000000000000”:

  • The given floating point number is “1 10000011 00010000000000000000000”.
  • In the given floating point number, the leading bit is “1” and this denotes a negative number.
  • The next eight bits denotes the unsigned integer “131”.
  • If “127” is subtracted from “131”, then the actual exponent is “4”...

c.

Explanation of Solution

Decimal equivalent for “0 11111111 00000000000000000000000”:

  • The given floating point number is “0 11111111 00000000000000000000000”.
  • In the given floating point number, the leading bit is “0” and this denotes a positive number...

d.

Explanation of Solution

Decimal equivalent for “1 10000000 10010000000000000000000”:

  • The given floating point number is “1 10000000 10010000000000000000000”.
  • In the given floating point number, the leading bit is “1” and this denotes a negative number.
  • The next eight bits denotes the unsigned integer “128”.
  • If “127” is subtracted from “128”, then the actual exponent is “1”...

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