INTRO.TO COMPUTING SYSTEMS >INTL.ED.<
3rd Edition
ISBN: 9781260565911
Author: PATT
Publisher: MCG
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Question
Chapter 2, Problem 30E
a.
Program Plan Intro
AND function:
- AND function needs two inputs and produces one output.
- It is also known as binary logical function.
- If either of the inputs or both the inputs are “0”, then one-bit AND operation produces the output as “0”.
- If both inputs are “1”, then AND operation produces the output as “1”.
- The following diagram depicts the AND operation,
b.
Explanation of Solution
101 AND 110:
The truth table for AND operation is as follows,
| X | Y | X AND Y |
| 0 | 0 | 0 |
| 0 | 1 | 0 |
| 1 | 0 | 0 |
| 1 | 1 | 1 |
Explanation for the truth table:
- In the above table, “X” and “Y” are inputs, and “Z” is output.
- When “X=0”, and “Y=0”, the output is “0”, because both the inputs “X” and “Y” contains the value “0”.
- When “X=0”, and “Y=1”, the output is “0”, because one of the input “X” contains the value “0”.
- When “X=1”, and “Y=0”, the output is “0”, because one of the input “Y” contains the value “0”...
c.
Explanation of Solution
11100000 AND 10110100:
The truth table for AND operation is as follows,
| X | Y | X AND Y |
| 0 | 0 | 0 |
| 0 | 1 | 0 |
| 1 | 0 | 0 |
| 1 | 1 | 1 |
Explanation for the truth table:
- In the above table, “X” and “Y” are inputs, and “Z” is output.
- When “X=0”, and “Y=0”, the output is “0”, because both the inputs “X” and “Y” contains the value “0”.
- When “X=0”, and “Y=1”, the output is “0”, because one of the input “X” contains the value “0”.
- When “X=1”, and “Y=0”, the output is “0”, because one of the input “Y” contains the value “0”...
d.
Explanation of Solution
00011111 AND 10110100:
The truth table for AND operation is as follows,
| X | Y | X AND Y |
| 0 | 0 | 0 |
| 0 | 1 | 0 |
| 1 | 0 | 0 |
| 1 | 1 | 1 |
Explanation for the truth table:
- In the above table, “X” and “Y” are inputs, and “Z” is output.
- When “X=0”, and “Y=0”, the output is “0”, because both the inputs “X” and “Y” contains the value “0”.
- When “X=0”, and “Y=1”, the output is “0”, because one of the input “X” contains the value “0”.
- When “X=1”, and “Y=0”, the output is “0”, because one of the input “Y” contains the value “0”...
e.
Explanation of Solution
(0011 AND 0110) AND 1101:
The truth table for AND operation is as follows,
| X | Y | X AND Y |
| 0 | 0 | 0 |
| 0 | 1 | 0 |
| 1 | 0 | 0 |
| 1 | 1 | 1 |
Explanation for the truth table:
- In the above table, “X” and “Y” are inputs, and “Z” is output.
- When “X=0”, and “Y=0”, the output is “0”, because both the inputs “X” and “Y” contains the value “0”.
- When “X=0”, and “Y=1”, the output is “0”, because one of the input “X” contains the value “0”.
- When “X=1”, and “Y=0”, the output is “0”, because one of the input “Y” contains the value “0”.
- When “X=1”, and “Y=1”, the output is “1”, because both the inputs “X” and “Y” contains the value “1”...
f.
Explanation of Solution
0011 AND (0110 AND 1101):
The truth table for AND operation is as follows,
| X | Y | X AND Y |
| 0 | 0 | 0 |
| 0 | 1 | 0 |
| 1 | 0 | 0 |
| 1 | 1 | 1 |
Explanation for the truth table:
- In the above table, “X” and “Y” are inputs, and “Z” is output.
- When “X=0”, and “Y=0”, the output is “0”, because both the inputs “X” and “Y” contains the value “0”.
- When “X=0”, and “Y=1”, the output is “0”, because one of the input “X” contains the value “0”.
- When “X=1”, and “Y=0”, the output is “0”, because one of the input “Y” contains the value “0”.
- When “X=1”, and “Y=1”, the output is “1”, because both the inputs “X” and “Y” contains the value “1”...
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make corrections of this program based on the errors shown. this is CIS 227 .
Create 6 users: Don, Liz, Shamir, Jose, Kate, and Sal.
Create 2 groups: marketing and research.
Add Shamir, Jose, and Kate to the marketing group.
Add Don, Liz, and Sal to the research group.
Create a shared directory for each group.
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spreadsheetJanuary.txt
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Screenshot of /etc/passwd contents showing your new users
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⚫ your circuit diagrams for your basic bricks, such as AND, OR, XOR gates and 1 bit multiplexers,
⚫ your circuit diagrams for your extended full adder, designed in Section 1 and
⚫ your circuit diagrams for your 8-bit arithmetical-logical unit, designed in Section 2.
1 An Extended Full Adder
In this Section, we are going to design an extended full adder circuit (EFA). That EFA takes 6 one bit inputs: aj, bj,
Cin, Tin, t₁ and to. Depending on the four possible combinations of values on t₁ and to, the EFA produces 3 one bit
outputs: sj, Cout and rout.
The EFA can be specified in principle by a truth table with 26 = 64 entries and 3 outputs. However, as the EFA
ignores certain inputs in certain cases, it is easier to work with the following overview specification, depending only
on t₁ and to in the first place:
t₁ to Description
00
Output Relationship
Ignored
Inputs
Addition Mode
2 Coutsjaj + bj + Cin, Tout= 0
Tin
0 1
Shift Left Mode
Sj = Cin,
Cout=bj, rout = 0
rin, aj
10
1 1
Shift Right…
Chapter 2 Solutions
INTRO.TO COMPUTING SYSTEMS >INTL.ED.<
Ch. 2 - Prob. 1ECh. 2 - Prob. 2ECh. 2 - Prob. 3ECh. 2 - Prob. 4ECh. 2 - Prob. 5ECh. 2 - Prob. 6ECh. 2 - Prob. 7ECh. 2 - Prob. 8ECh. 2 - Prob. 9ECh. 2 - Prob. 10E
Ch. 2 - Prob. 11ECh. 2 - Prob. 12ECh. 2 - Prob. 13ECh. 2 - Prob. 14ECh. 2 - Prob. 15ECh. 2 - Prob. 17ECh. 2 - Prob. 18ECh. 2 - Prob. 19ECh. 2 - Prob. 20ECh. 2 - Prob. 21ECh. 2 - Prob. 22ECh. 2 - Prob. 23ECh. 2 - Prob. 24ECh. 2 - Prob. 25ECh. 2 - Prob. 26ECh. 2 - Prob. 27ECh. 2 - When is the output of an AND operation equal to...Ch. 2 - Prob. 29ECh. 2 - Prob. 30ECh. 2 - When is the output of an OR operation equal to 1?
Ch. 2 - Prob. 32ECh. 2 - Prob. 33ECh. 2 - Prob. 34ECh. 2 - Prob. 35ECh. 2 - Prob. 36ECh. 2 - Prob. 37ECh. 2 - Prob. 38ECh. 2 - Prob. 39ECh. 2 - Prob. 40ECh. 2 - Prob. 41ECh. 2 - A computer programmer wrote a program that adds...Ch. 2 - Prob. 43ECh. 2 - Prob. 44ECh. 2 - Prob. 45ECh. 2 - Prob. 46ECh. 2 - Prob. 47ECh. 2 - Prob. 48ECh. 2 - Prob. 49ECh. 2 - Prob. 50ECh. 2 - Prob. 51ECh. 2 - Prob. 52ECh. 2 - Prob. 53ECh. 2 - Fill in the truth table for the equations given....Ch. 2 - Prob. 55ECh. 2 - Prob. 56E
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