INTRO.TO COMPUTING SYSTEMS >INTL.ED.<
3rd Edition
ISBN: 9781260565911
Author: PATT
Publisher: MCG
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Expert Solution & Answer
Chapter 2, Problem 17E
a.
Explanation of Solution
01 + 1011:
- Express the given numbers with the same number of bits.
- Addition of leading 0’s do not affect the result.
- The process of addition can perform on “1” digit at a time from right to left.
- A sum digit and a carry digit are generated at each point.
- It the user adds “1” and “1”, it generates the sum digit “0” and carry digit “1”.
- The given 2-bit binary number “01” is extended to 4-bit binary number as “0001”
- The addition of the binary numbers is as follows,
b.
Explanation of Solution
11 + 01010101:
- Express the given numbers with the same number of bits.
- The sign of the integer is indicated by the Left most Significant Bit (LSB).
- The number is positive if LSB is “0”, and the number is negative if LSB is “1”.
- The binary number “11” is negative and it is extended by leading 1’s.
- The result does not affected by leading 1’s.
- The process of addition can perform on “1” digit at a time from right to left.
- A sum digit and a carry digit are generated at each point.
- It the user adds “1” and “1”, it generates the sum digit “0” and carry digit “1”.
- It the user adds “1” and “0”, it generates the sum digit “1” and carry digit “0”...
c.
Explanation of Solution
0101 + 110:
- Express the given numbers with the same number of bits.
- The sign of the integer is indicated by the Left most Significant Bit (LSB).
- The number is positive if LSB is “0”, and the number is negative if LSB is “1”.
- The binary number “110” is negative and it is extended by leading 1’s.
- The result does not affected by leading 1’s.
- The process of addition can perform on “1” digit at a time from right to left.
- A sum digit and a carry digit are generated at each point.
- It the user adds “1” and “1”, it generates the sum digit “0” and carry digit “1”.
- It the user adds “1” and “0”, it generates the sum digit “1” and carry digit “0”...
d.
Explanation of Solution
01 + 10:
- The given binary numbers have the same number of bits.
- The sign of the integer is indicated by the Left most Significant Bit (LSB).
- The number is positive if LSB is “0”, and the number is negative if LSB is “1”.
- The process of addition can perform on “1” digit at a time from right to left.
- A sum digit and a carry digit are generated at each point.
- It the user adds “1” and “1”, it generates the sum digit “0” and carry digit “1”.
- It the user adds “1” and “0”, it generates the sum digit “1” and carry digit “0”...
Expert Solution & Answer
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make corrections of this program based on the errors shown. this is CIS 227 .
Create 6 users: Don, Liz, Shamir, Jose, Kate, and Sal.
Create 2 groups: marketing and research.
Add Shamir, Jose, and Kate to the marketing group.
Add Don, Liz, and Sal to the research group.
Create a shared directory for each group.
Create two files to put into each directory:
spreadsheetJanuary.txt
meetingNotes.txt
Assign access permissions to the directories:
Groups should have Read+Write access
Leave owner permissions as they are
“Everyone else” should not have any access
Submit for grade:
Screenshot of /etc/passwd contents showing your new users
Screenshot of /etc/group contents showing new groups with their members
Screenshot of shared directories you created with files and permissions
⚫ your circuit diagrams for your basic bricks, such as AND, OR, XOR gates and 1 bit multiplexers,
⚫ your circuit diagrams for your extended full adder, designed in Section 1 and
⚫ your circuit diagrams for your 8-bit arithmetical-logical unit, designed in Section 2.
1 An Extended Full Adder
In this Section, we are going to design an extended full adder circuit (EFA). That EFA takes 6 one bit inputs: aj, bj,
Cin, Tin, t₁ and to. Depending on the four possible combinations of values on t₁ and to, the EFA produces 3 one bit
outputs: sj, Cout and rout.
The EFA can be specified in principle by a truth table with 26 = 64 entries and 3 outputs. However, as the EFA
ignores certain inputs in certain cases, it is easier to work with the following overview specification, depending only
on t₁ and to in the first place:
t₁ to Description
00
Output Relationship
Ignored
Inputs
Addition Mode
2 Coutsjaj + bj + Cin, Tout= 0
Tin
0 1
Shift Left Mode
Sj = Cin,
Cout=bj, rout = 0
rin, aj
10
1 1
Shift Right…
Chapter 2 Solutions
INTRO.TO COMPUTING SYSTEMS >INTL.ED.<
Ch. 2 - Prob. 1ECh. 2 - Prob. 2ECh. 2 - Prob. 3ECh. 2 - Prob. 4ECh. 2 - Prob. 5ECh. 2 - Prob. 6ECh. 2 - Prob. 7ECh. 2 - Prob. 8ECh. 2 - Prob. 9ECh. 2 - Prob. 10E
Ch. 2 - Prob. 11ECh. 2 - Prob. 12ECh. 2 - Prob. 13ECh. 2 - Prob. 14ECh. 2 - Prob. 15ECh. 2 - Prob. 17ECh. 2 - Prob. 18ECh. 2 - Prob. 19ECh. 2 - Prob. 20ECh. 2 - Prob. 21ECh. 2 - Prob. 22ECh. 2 - Prob. 23ECh. 2 - Prob. 24ECh. 2 - Prob. 25ECh. 2 - Prob. 26ECh. 2 - Prob. 27ECh. 2 - When is the output of an AND operation equal to...Ch. 2 - Prob. 29ECh. 2 - Prob. 30ECh. 2 - When is the output of an OR operation equal to 1?
Ch. 2 - Prob. 32ECh. 2 - Prob. 33ECh. 2 - Prob. 34ECh. 2 - Prob. 35ECh. 2 - Prob. 36ECh. 2 - Prob. 37ECh. 2 - Prob. 38ECh. 2 - Prob. 39ECh. 2 - Prob. 40ECh. 2 - Prob. 41ECh. 2 - A computer programmer wrote a program that adds...Ch. 2 - Prob. 43ECh. 2 - Prob. 44ECh. 2 - Prob. 45ECh. 2 - Prob. 46ECh. 2 - Prob. 47ECh. 2 - Prob. 48ECh. 2 - Prob. 49ECh. 2 - Prob. 50ECh. 2 - Prob. 51ECh. 2 - Prob. 52ECh. 2 - Prob. 53ECh. 2 - Fill in the truth table for the equations given....Ch. 2 - Prob. 55ECh. 2 - Prob. 56E
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