COMPUTER SCIENCE ILLUMIN.-TEXT
6th Edition
ISBN: 2810016866372
Author: Dale
Publisher: JONES+BART
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Chapter 2, Problem 39E
Program Plan Intro
Octal subtraction:
The rules for subtracting two octal numbers are as follows:
- Read both the numbers to know the number of bits.
- If the number of bits in the first number is less than that of the other number, add the required number of zeros on the left side.
- Numbers are represented in bytes where one byte is equal to 8 bits.
- Align the number in correct order after padding. The octal number that is followed by a minus sign should be subtracted from the other octal number.
Explanation of Solution
b.
“1234 – 765”:
- Start numbers from right to left.
- Subtract “5” from “4”.
- Here “4” is less than “5”. As a result, borrow a number from adjacent left hand side.
- After borrowing it becomes “2” as adjacent left side number is “3”.
- After borrowing, add “8” with “4”.
- Add “8” with “4” and then subtract it from “5”, which give “7”. The equivalent octal number for number “7” is “7”. Hence, write “7” to the result.
- Subtract “6” from “2”.
- Here “2” is less than “6”. Borrow number from adjacent left side.
- After borrowing, it becomes “1” as adjacent left side number is “2”.
- After borrowing, add “8” with “2”.
- Add “8” with “2” and then subtract this from “6”, which give “4”...
- Subtract “5” from “4”.
Explanation of Solution
c.
“7766 – 5544”:
- Start with the numbers from right to left.
- Subtract “4” from “6” which results in “2”.
- Subtract “4” from “6” which results in “2”.
- Subtract “7” from “5” which results in “2”...
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Chapter 2 Solutions
COMPUTER SCIENCE ILLUMIN.-TEXT
Ch. 2 - Prob. 1ECh. 2 - Prob. 2ECh. 2 - Prob. 3ECh. 2 - Prob. 4ECh. 2 - Prob. 5ECh. 2 - Prob. 6ECh. 2 - Prob. 7ECh. 2 - Prob. 8ECh. 2 - Prob. 9ECh. 2 - Prob. 10E
Ch. 2 - Prob. 11ECh. 2 - Prob. 12ECh. 2 - Prob. 13ECh. 2 - Prob. 14ECh. 2 - Prob. 15ECh. 2 - Prob. 16ECh. 2 - Prob. 17ECh. 2 - Prob. 18ECh. 2 - Prob. 19ECh. 2 - Prob. 20ECh. 2 - Prob. 21ECh. 2 - Prob. 22ECh. 2 - Prob. 23ECh. 2 - Prob. 24ECh. 2 - Prob. 25ECh. 2 - Prob. 26ECh. 2 - Prob. 27ECh. 2 - Prob. 28ECh. 2 - Prob. 29ECh. 2 - Prob. 30ECh. 2 - Prob. 31ECh. 2 - Prob. 32ECh. 2 - Prob. 33ECh. 2 - Prob. 34ECh. 2 - Prob. 35ECh. 2 - Prob. 36ECh. 2 - Prob. 38ECh. 2 - Prob. 39ECh. 2 - Prob. 40ECh. 2 - Prob. 41ECh. 2 - Prob. 42ECh. 2 - Prob. 43ECh. 2 - Prob. 44ECh. 2 - Prob. 45ECh. 2 - Prob. 46ECh. 2 - Prob. 47ECh. 2 - Prob. 1TQCh. 2 - Prob. 2TQCh. 2 - Prob. 3TQCh. 2 - Prob. 4TQ
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