Chapter 2, Problem 2.86QP

(a)

Interpretation Introduction

Interpretation: The chemical formulas of compounds are given. The chemical names of the given compounds are to be determined.

Concept introduction: According to IUPAC nomenclature, if the compound is made of metal and non metal, then the name of the compound begins from name of the metal followed by the oxidation state of metal and the name of the non metal. The metal name remains same as in the periodic table, but the name of non metals end with “ide”. The oxidation state is always composed in roman words within the bracket.

To determine: The name of given chemical formula.

Answer to Problem 2.86QP

Solution

The chemical compound ${\text{FePO}}_4$ is named as iron $\left(\text{III}\right)$ phosphate.

Explanation of Solution

Explanation

The chemical formula is ${\text{FePO}}_4$.

Iron is a metal present in the d block of the periodic table whereas phosphate is an anion. One iron cation and one sulphate anion combine to make electrically balance compound. The phosphate ion consists of $3-$ charge.

The compound contains one phosphate anion. The phosphate anion naming does not end with “ide” because it is not a non metal.

The oxidation state of the elements that can exhibit more than one oxidation state is mentioned after the name of the element.

The oxidation state $(x)$ of iron is calculated as,

$\left(\text{Sum}\text{of}\text{the}\text{oxidation}\text{state}\text{of}\text{the}\text{constituent}\text{atom}\right)=\left(\text{Total}\text{charge}\text{on}\text{the}\text{complex}\right)$

$\begin{array}{c}x+\left(-3\right)=0\\ x=+3\end{array}$

Therefore, the chemical compound ${\text{FePO}}_4$ is named as iron $\left(\text{III}\right)$ phosphate.

(b)

Interpretation Introduction

To determine: The name of given chemical formula.

Answer to Problem 2.86QP

Solution

The chemical compound ${\text{CuSO}}_4$ is named as copper $\left(\text{II}\right)$ sulphate.

Explanation of Solution

Explanation

The chemical formula is. ${\text{CuSO}}_4$.

Copper is a metal present in the d block of periodic table, whereas sulphate is an anion. One copper cation and one sulphate anion combine to make electrically balance compound. The sulphate ion consists of $2-$ charge.

The sulphate ion is neither a metal nor a non metal. It is an anion. Thus, its naming never ends with “ide”.

The oxidation state of the elements that can exhibit more than one oxidation state is mentioned after the name of the element.

The oxidation state $(x)$ of copper is calculated as,

$\left(\text{Sum}\text{of}\text{the}\text{oxidation}\text{state}\text{of}\text{the}\text{constituent}\text{atom}\right)=\left(\text{Total}\text{charge}\text{on}\text{the}\text{complex}\right)$

$\begin{array}{c}x-2=0\\ x=2\end{array}$

Therefore, the chemical compound ${\text{CuSO}}_4$ is named as copper $\left(\text{II}\right)$ sulphate.

(c)

Interpretation Introduction

To determine: The name of given chemical formula.

Answer to Problem 2.86QP

Solution

The chemical compound ${\text{Ag}}_2{\text{CO}}_3$ is named as silver carbonate.

Explanation of Solution

Explanation

The chemical formula is. ${\text{Ag}}_2{\text{CO}}_3$.

Silver $\left(\text{Ag}\right)$ is a metal present in the d block of the periodic table whereas carbonate is an anion. Two silver cations and one carbonate anion $\left({\text{CO}}_3{}^{2-}\right)$ combine to make electrically balance compound. The carbonate consists of $2-$ charge.

The carbonate ion naming  never ends with “ide” because it is neither a metal nor a non metal in nature.

The oxidation state of the elements that can exhibit more than one oxidation state is mentioned after the name of the element.

The charge $(x)$ on silver is calculated as,

$\left(\text{Sum}\text{of}\text{the}\text{oxidation}\text{state}\text{of}\text{the}\text{constituent}\text{atom}\right)=\left(\text{Total}\text{charge}\text{on}\text{the}\text{complex}\right)$

$\begin{array}{c}2x-2=0\\ 2x=2\\ x=1\end{array}$

Silver has only one charge so it is named without any numerals within the bracket.

Therefore, the chemical compound ${\text{Ag}}_2{\text{CO}}_3$ is named as silver carbonate.

(d)

Interpretation Introduction

To determine: The name of given chemical formula.

Answer to Problem 2.86QP

Solution

The chemical compound $\text{Zn}{\left({\text{NO}}_2\right)}_2$ is named as zinc $\left(\text{II}\right)$ nitrite.

Explanation of Solution

Explanation

The chemical formula is $\text{Zn}{\left({\text{NO}}_2\right)}_2$.

Zinc is a metal present in the d block of the periodic table whereas nitrite is an anion. One zinc cation and two nirite anion combine to make electrically balance compound.

The anion consists of $1-$ charge. Oxygen naming ends in “ide” because it is a non metal.

The oxidation state of the elements that can exhibit more than one oxidation state is mentioned after the name of the element.

The oxidation state $(x)$ of zinc is calculated as,

$\left(\text{Sum}\text{of}\text{the}\text{oxidation}\text{state}\text{of}\text{the}\text{constituent}\text{atom}\right)=\left(\text{Total}\text{charge}\text{on}\text{the}\text{complex}\right)$

$\begin{array}{c}x+\left(-2\right)=0\\ x=+2\end{array}$

Therefore, the chemical compound $\text{Zn}{\left({\text{NO}}_2\right)}_2$ is named as zinc $\left(\text{II}\right)$ nitrite.

Conclusion

1. a. The given compound ${\text{FePO}}_4$ is named as iron $\left(\text{III}\right)$ phosphate.
2. b. The given compound ${\text{CuSO}}_4$ is named as copper $\left(\text{II}\right)$ sulphate.
3. c. The given compound ${\text{Ag}}_2{\text{CO}}_3$ is named as silver carbonate.
4. d. The given compound $\text{Zn}{\left({\text{NO}}_2\right)}_2$ is named as zinc $\left(\text{II}\right)$ nitrite