Concept explainers
Interpretation: The path followed by emitted alpha and beta particles is to be identified.
Concept introduction: The radioactivity is a process in which an unstable nucleus releases its energy by emitting alpha rays, beta rays and gamma rays. The path of these radiations changes as they move through electric field.
The alpha particles consist of positively charged helium atoms whereas beta particles consist of negatively charged electrons.
To determine: The path followed by the emitted alpha and beta particle
Answer to Problem 2.1VP
Solution
The path followed by the emitted alpha and beta particle has been identified.
Explanation of Solution
Explanation
The path of emitted alpha and beta particle is shown in Figure 1 in red and green color.
Figure 1
The emitted alpha and beta particles are passed through electric field and they deviate from each other. The radiation shown in green color move towards positive plate while red move towards negative plate.
This indicates that red line consists of positive charged alpha particles and green line shows the presence of negatively charged beta particles.
Conclusion
The path followed by the emitted alpha and beta particle has been
identified
Want to see more full solutions like this?
Chapter 2 Solutions
CHEMISTRY W/WRKBK AND SMARTWORK (LL)
- Nonearrow_forwardJON Determine the bund energy for UCI (in kJ/mol Hcl) using me balanced chemical equation and bund energies listed? का (My (9) +36/2(g)-(((3(g) + 3(g) A Hryn = -330. KJ bond energy и-н 432 bond bond C-1413 C=C 839 N-H 391 C=O 1010 S-H 363 б-н 467 02 498 N-N 160 N=N 243 418 C-C 341 C-0 358 C=C C-C 339 N-Br 243 Br-Br C-Br 274 193 614 (-1 214||(=olin (02) 799 C=N 615 AALarrow_forwardDetermine the bond energy for HCI ( in kJ/mol HCI) using he balanced cremiculequecticnand bund energles listed? also c double bond to N is 615, read numbets carefully please!!!! Determine the bund energy for UCI (in kJ/mol cl) using me balanced chemical equation and bund energies listed? 51 (My (9) +312(g)-73(g) + 3(g) =-330. KJ спод bond energy Hryn H-H bond band 432 C-1 413 C=C 839 NH 391 C=O 1010 S-1 343 6-H 02 498 N-N 160 467 N=N C-C 341 CL- 243 418 339 N-Br 243 C-O 358 Br-Br C=C C-Br 274 193 614 (-1 216 (=olin (02) 799 C=N 618arrow_forward
- Differentiate between single links and multicenter links.arrow_forwardI need help on my practice final, if you could explain how to solve this that would be extremely helpful for my final thursday. Please dumb it down chemistry is not my strong suit. If you could offer strategies as well to make my life easier that would be beneficialarrow_forwardNonearrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY