EBK FUNDAMENTALS OF GENERAL, ORGANIC, A
8th Edition
ISBN: 8220102895805
Author: Peterson
Publisher: PEARSON
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Textbook Question
Chapter 2, Problem 2.73AP
Without looking back in the text, write the electron configurations for the following:
(a) Titanium Z = 22
(b) Phosphorus, Z = 15
(c) Argon, Z = 18
(d) Lanthanum, Z = 57
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for each pair of biomolecules, identify the type of reaction (oxidation-reduction, hydrolysis, isomerization, group transfer, or
nternal rearrangement) required to convert the first molecule to the second. In each case, indicate the general type of enzyme
and cofactor(s) c reactants required, and any other products that would result.
R-CH-CH-CH-C-S-COA
A(n)
A(n)
A(n)
A(n)
Palmitoyl-CoA
R-CH-CH=CH-C-S-CoA
°
trans-A-Enoyl-CoA
reaction converts palmitoyl-CoA to trans-A2-enoyl-CoA. This reaction requires
and also produces
Coo
HN-C-H
CH₂
CH₂
CH
CH
CH, CH,
L-Leucine
CH, CH,
D-Leucine
8/6881
COO
HÌNH:
reaction converts L-leucine to D-leucine. This reaction is catalyzed by a(n)
H-C-OH
H-C-OH
C=0
HO-C-H
HO-C-H
H-C-OH
H-C-OH
H-C-OH
CH,OH
Glucose
H-C-OH
CH,OH
Fructose
OH OH OH
CH-C-CH₂
reaction converts glucose to fructose. This reaction is catalyzed by a(n)
OH
OH OPO
I
CH-C-CH
H
Glycerol
Glycerol 3-phosphate
H
reaction converts glycerol to glycerol 3-phosphate. This reaction requires
H,N-
H,N
H…
After adding a small amount of ATP labeled with radioactive phosphorus in the terminal position, [7-32P]ATP, to a yeast extract,
a researcher finds about half of the 32P activity in P; within a few minutes, but the concentration of ATP remains unchanged. She
then carries out the same experiment using ATP labeled with 32P in the central position, [ẞ-³2P]ATP, but the 32P does not appear
in P; within such a short time.
Which statements explain these results?
Yeast cells reincorporate P; released from [ß-³2P]ATP into ATP more quickly than P¡ released from [y-³2P]ATP.
Only the terminal (y) phosphorous atom acts as an electrophilic target for nucleophilic attack.
The terminal (y) phosphoryl group undergoes a more rapid turnover than the central (B) phosphate group.
Yeast cells maintain ATP levels by regulating the synthesis and breakdown of ATP.
Correct Answer
Compare the structure of the nucleoside triphosphate CTP with the structure of ATP.
NH₂
0-
0-
0-
·P—O—P—O—P—O—CH₂
H
H
H
H
OH OH
Cytidine triphosphate (CTP)
Consider the reaction:
ATP + CDP
ADP + CTP
NH
0-
0-
0-
¯0— P—O— P—O—P-O-CH₂
H
Η
о
H
H
OH
OH
Adenosine triphosphate (ATP)
NH₂
Now predict the approximate K'eq for this reaction.
Now predict the approximate AG for this reaction.
N
Chapter 2 Solutions
EBK FUNDAMENTALS OF GENERAL, ORGANIC, A
Ch. 2.1 - Prob. 2.1CIAPCh. 2.1 - For the Kanji character in the lower portion of...Ch. 2.2 - Use the list inside the front cover to identify...Ch. 2.3 - Prob. 2.2PCh. 2.3 - Prob. 2.3PCh. 2.3 - Prob. 2.4PCh. 2.4 - Prob. 2.5PCh. 2.4 - Prob. 2.6PCh. 2.4 - Prob. 2.7PCh. 2.4 - Prob. 2.8P
Ch. 2.4 - Prob. 2.9PCh. 2.5 - Prob. 2.10PCh. 2.5 - Prob. 2.11PCh. 2.5 - Prob. 2.12PCh. 2.5 - Prob. 2.13KCPCh. 2.5 - Prob. 2.3CIAPCh. 2.5 - Prob. 2.4CIAPCh. 2.6 - Prob. 2.14PCh. 2.7 - Prob. 2.15PCh. 2.7 - Write electron configurations for the following...Ch. 2.7 - Prob. 2.17PCh. 2.7 - Identify the atom with the following...Ch. 2.8 - Prob. 2.19PCh. 2.8 - Prob. 2.20PCh. 2.8 - Prob. 2.21PCh. 2.8 - Prob. 2.22KCPCh. 2.9 - Prob. 2.23PCh. 2.9 - Write electron-dot symbols for radon, lead, xenon,...Ch. 2.9 - Prob. 2.25PCh. 2.9 - Prob. 2.5CIAPCh. 2.9 - Prob. 2.6CIAPCh. 2 - Where on the following outline of a periodic table...Ch. 2 - Is the element marked in red on the following...Ch. 2 - Prob. 2.28UKCCh. 2 - What atom has the following orbital-filling...Ch. 2 - Use the following orbital-filling diagram to show...Ch. 2 - What four fundamental assumptions about atoms and...Ch. 2 - How do atoms of different elements differ?Ch. 2 - Prob. 2.33APCh. 2 - Prob. 2.34APCh. 2 - Prob. 2.35APCh. 2 - Prob. 2.36APCh. 2 - How many O atoms of mass 15.99 amu are in 15.99 g...Ch. 2 - Prob. 2.38APCh. 2 - What are the names of the three subatomic...Ch. 2 - Prob. 2.40APCh. 2 - Prob. 2.41APCh. 2 - Prob. 2.42APCh. 2 - Which of the following symbols represent isotopes...Ch. 2 - Prob. 2.44APCh. 2 - Prob. 2.45APCh. 2 - Prob. 2.46APCh. 2 - One of the most widely used isotopes in medical...Ch. 2 - Prob. 2.48APCh. 2 - Prob. 2.49APCh. 2 - Prob. 2.50APCh. 2 - Prob. 2.51APCh. 2 - Prob. 2.52APCh. 2 - Prob. 2.53APCh. 2 - Prob. 2.54APCh. 2 - Prob. 2.55APCh. 2 - For (a) rubidium (b) tungsten, (c) germanium, and...Ch. 2 - For (a) calcium, (b) palladium, (c) carbon, and...Ch. 2 - Prob. 2.58APCh. 2 - Prob. 2.59APCh. 2 - Prob. 2.60APCh. 2 - Prob. 2.61APCh. 2 - Prob. 2.62APCh. 2 - Prob. 2.63APCh. 2 - Prob. 2.64APCh. 2 - Prob. 2.65APCh. 2 - Prob. 2.66APCh. 2 - Prob. 2.67APCh. 2 - Prob. 2.68APCh. 2 - Prob. 2.69APCh. 2 - Prob. 2.70APCh. 2 - Prob. 2.71APCh. 2 - Determine the number of unpaired electrons for...Ch. 2 - Without looking back in the text, write the...Ch. 2 - Prob. 2.74APCh. 2 - Prob. 2.75APCh. 2 - Prob. 2.76APCh. 2 - Prob. 2.77APCh. 2 - Prob. 2.78APCh. 2 - Using n for the number of the valence shell and...Ch. 2 - What elements in addition to helium make up the...Ch. 2 - Prob. 2.81CPCh. 2 - What is the atomic number of the yet-undiscovered...Ch. 2 - Give the number of electrons in each shell for...Ch. 2 - Identify the highest-energy occupied subshell in...Ch. 2 - Prob. 2.85CPCh. 2 - Prob. 2.86CPCh. 2 - Germanium, atomic number 32, is used in building...Ch. 2 - Prob. 2.88CPCh. 2 - Prob. 2.89CPCh. 2 - What is wrong with the following electron...Ch. 2 - Prob. 2.91CPCh. 2 - Prob. 2.92CPCh. 2 - Prob. 2.93CPCh. 2 - Prob. 2.94CPCh. 2 - Prob. 2.95GPCh. 2 - Prob. 2.96GPCh. 2 - Prob. 2.97GPCh. 2 - Look again at the trends illustrated in Figures...
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- The standard free energy, AGO, of hydrolysis of inorganic polyphosphate, polyP, is about −20 kJ/mol for each P; released. In a cell, it takes about 50 kJ/mol of energy to synthesize ATP from ADP and Pi. ○ P O Inorganic polyphosphate (polyP) Is it feasible for a cell to use polyP to synthesize ATP from ADP? Why or why not? No. The reaction is unidirectional and always proceeds in the direction of polyP synthesis from ATP. Yes. If [ADP] and [polyP] are kept high, and [ATP] is kept low, the actual free-energy change would be negative. No. The synthesis of ATP from ADP and P; has a large positive G'o compared to polyP hydrolysis. Yes. The hydrolysis of polyP has a sufficiently negative AG to overcome the positive AGO of ATP synthesis. Correct Answerarrow_forwardIn the glycolytic pathway, a six-carbon sugar (fructose 1,6-bisphosphate) is cleaved to form two three-carbon sugars, which undergo further metabolism. In this pathway, an isomerization of glucose 6-phosphate to fructose 6-phosphate (as shown in the diagram) occurs two steps before the cleavage reaction. The intervening step is phosphorylation of fructose 6-phosphate to fructose 1,6-bisphosphate. H H | H-C-OH H-C-OH C=0 HO-C-H HO-C-H phosphohexose isomerase H-C-OH H-C-OH H-C-OH H-C-OH CH₂OPO CH₂OPO Glucose 6-phosphate Fructose 6-phosphate What does the isomerization step accomplish from a chemical perspective? Isomerization alters the molecular formula of the compound, allowing for subsequent phosphorylation. Isomerization moves the carbonyl group, setting up a cleavage between the central carbons. Isomerization causes the gain of electrons, allowing for the eventual release of NADH. Isomerization reactions cause the direct production of energy in the form of ATP.arrow_forwardFrom data in the table, calculate the AG value for the reactions. Reaction AG' (kJ/mol) Phosphocreatine + H₂O →>> creatine + P -43.0 ADP + Pi → ATP + H₂O +30.5 Fructose +P → fructose 6-phosphate + H₂O +15.9 Phosphocreatine + ADP creatine + ATP AG'O ATP + fructose → ADP + fructose 6-phosphate AG'° kJ/mol kJ/molarrow_forward
- Macmillan Learning The phosphorylation of glucose to glucose 6-phosphate is the initial step in the catabolism of glucose. The direct phosphorylation of glucose by P, is described by the equation Glucose + P ← glucose 6-phosphate + H₂O AG = 13.8 kJ/mol Coupling ATP hydrolysis to glucose phosphorylation makes thermodynamic sense, but consider how the coupling might take place. Given that coupling requires a common intermediate, one conceivable mechanism is to use ATP hydrolysis to raise the intracellular concentration of Pi. The increase in P; concentration would drive the unfavorable phosphorylation of glucose by Pi- Is increasing the P; concentration a reasonable way to couple ATP hydrolysis and glucose phosphorylation? No. The phosphate salts of divalent cations would be present in excess and precipitate out. Yes. Increasing the concentration of P; would decrease K'eq and shift equilibrium to the right. Yes. The extra ATP hydrolysis would provide enough free energy to drive the…arrow_forwardThe phosphorylation of glucose to glucose 6-phosphate is the initial step in the catabolism of glucose. The direct phosphorylation of glucose by P, is described by the equation Glucose + P → glucose 6-phosphate + H₂O AG' = 13.8 kJ/mol In principle, at least, one way to increase the concentration of glucose 6-phosphate (G6P) is to drive the equilibrium reaction to the right by increasing the intracellular concentrations of glucose and Pj. The maximum solubility of glucose is less than 1 M, and the normal physiological concentration of G6P is 250 μM. Assume a fixed concentration of P, at 4.8 mM. The calculated value of K'cq is 4.74 × 10-³ M-¹. Calculate the intracellular concentration of glucose when the equilibrium concentration of glucose 6-phosphate is 250 μM, the normal physiological concentration. [glucose] = 10.99 Correct Answer Would increasing the concentration of glucose be a physiologically reasonable way to increase the concentration of G6P? No. Because the concentration of P,…arrow_forwardCalculate the equilibrium constant for the phosphorylation of glucose to glucose 6-phosphate at 37.0 °C. K'eq = M-' In the rat hepatocyte, the physiological concentrations of glucose and P, are maintained at approximately 4.8 mM. What is the equilibrium concentration of glucose 6-phosphate (G6P) obtained by the direct phosphorylation of glucose by P.? [G6P] = Does this reaction represent a reasonable metabolic step for the catabolism of glucose? Why or why not? Yes, because the value of AG" is positive. No, because the K'eq is too large for the reaction to proceed in the forward direction. Yes, because AG is negative at the calculated value of K'eq No, because [G6P] is likely to be higher than the calculated value. Marrow_forward
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