(a) Interpretation: The given reaction is to be classified as either a proton transfer reaction or a reaction of electrophile and nucleophile. The movement of electrons is to be shown by curved arrows. Concept introduction: Lewis acid accepts an electron pair. It acts as an electrophile Lewis base donates an electron pair. It acts as nucleophile. Conjugate base is formed by the loss of a proton from an acid while conjugate acid is formed by the gain of electron by a base.
(a) Interpretation: The given reaction is to be classified as either a proton transfer reaction or a reaction of electrophile and nucleophile. The movement of electrons is to be shown by curved arrows. Concept introduction: Lewis acid accepts an electron pair. It acts as an electrophile Lewis base donates an electron pair. It acts as nucleophile. Conjugate base is formed by the loss of a proton from an acid while conjugate acid is formed by the gain of electron by a base.
Solution Summary: The author explains that Lewis acid accepts an electron pair and acts as an electrophile. The movement of electrons is shown by curved arrows.
Interpretation: The given reaction is to be classified as either a proton transfer reaction or a reaction of electrophile and nucleophile. The movement of electrons is to be shown by curved arrows.
Concept introduction: Lewis acid accepts an electron pair. It acts as an electrophile Lewis base donates an electron pair. It acts as nucleophile. Conjugate base is formed by the loss of a proton from an acid while conjugate acid is formed by the gain of electron by a base.
Interpretation Introduction
(b)
Interpretation: The given reaction is to be classified as either a proton transfer reaction or a reaction of electrophile and nucleophile. The movement of electrons is to be shown by curved arrows.
Concept introduction: Lewis acid accepts an electron pair. It acts as an electrophile Lewis base donates an electron pair. It acts as nucleophile. Conjugate base is formed by the loss of a proton from an acid while conjugate acid is formed by the gain of electron by the base.
22.22 For each compound, indicate which group on the ring is more strongly activating and then
draw a structural formula of the major product formed by nitration of the compound.
Br
CHO
(a)
CH3
(b)
(c)
CHO
CH3
SO₂H
(d)
☑
OCHS
NO₂
(e)
(f)
CO₂H
NHCOCH3
NHCOCH,
(h)
CHS
22.23 The following molecules each contain two aromatic rings.
(b)
000-100-
H3C
(a)
(c)
Which ring in each undergoes electrophilic aromatic substitution more readily? Draw
the major product formed on nitration.
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