Dimethyl ether ( CH 3 OCH 3 ) and ethanol ( CH 3 CH 2 OH ) are isomers, but has ( CH 3 OCH 3 ) a p K a of 40 and ( CH 3 CH 2 OH ) has a p K a of 16 . Why are these p K a values so different?
Dimethyl ether ( CH 3 OCH 3 ) and ethanol ( CH 3 CH 2 OH ) are isomers, but has ( CH 3 OCH 3 ) a p K a of 40 and ( CH 3 CH 2 OH ) has a p K a of 16 . Why are these p K a values so different?
Solution Summary: The author explains that diethyl ether and ethanol are stereoisomers. The acidity of a compound depends on the stability of its conjugate base.
Dimethyl ether
(
CH
3
OCH
3
)
and ethanol
(
CH
3
CH
2
OH
)
are isomers, but has
(
CH
3
OCH
3
)
a
p
K
a
of
40
and
(
CH
3
CH
2
OH
)
has a
p
K
a
of
16
. Why are these
p
K
a
values so different?
Explain why in the representation of a one-dimensional velocity distribution function for a particular gas, the maximum occurs for vi = 0 m/s.
Explain why the representation of a one-dimensional velocity distribution function for a particular gas becomes flatter as the temperature increases.
Draw a Lewis structure for each of the following molecules and assign
charges where appropriate. The order in which the atoms are connected
is given in parentheses.
a. CIFCIF
b. BrCNBrCN
0
c. SOCI2 × (CISCIO) SOC₁₂ (CISCI)
You can draw both an octet and a valence
shell expanded structure. Considering the following structural information, which
is the better one: The measured S-OS-O bond length in SOC12SOCl2 is 1.43 Å.
For comparison, that in SO2SO2 is 1.43 Å [Exercise 1-9, part (b)], that in
CHзSOHCH3 SOH
d. CH3NH2CH3NH2
(methanesulfenic acid) is 1.66 A.
e. CH3OCH3 CH3 OCH3
NH2
f. N2H2× (HNNH) N2 H2 (HNNH)
g. CH2COCH₂ CO
h. HN3× (HNNN) HN3 (HNNN)
i. N20 × (NNO) N2O (NNO)
Chapter 2 Solutions
Package: Loose Leaf for Organic Chemistry with Biological Topics with Connect Access Card
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