Chapter 2, Problem 2.57E

Interpretation Introduction

(a)

Interpretation:

The number of grams of nitrogen that are present in $\text{70}\text{.0}\text{g}$ of ${\text{C}}_6{\text{H}}_5{\text{NO}}_3$ is to be determined.

Concept introduction:

Avogadro’s number is used to determine the number of atoms present in $1\text{mol}$ of an element.

Therefore, $1\text{mol}=6.022\times {10}^{23}$

Interpretation Introduction

(b)

Interpretation:

The number of moles of oxygen atoms that are present in $\text{1}\text{.50}\text{mol}$ of ${\text{C}}_6{\text{H}}_5{\text{NO}}_3$ is to be determined.

Concept introduction:

Avogadro’s number is used to determine the number of atoms present in $1\text{mol}$ of an element.

Therefore, $1\text{mol}=6.022\times {10}^{23}$

Interpretation Introduction

(c)

Interpretation:

The number of carbon atoms that are present in $9.00\times {10}^{22}\text{molecules}$ of ${\text{C}}_6{\text{H}}_5{\text{NO}}_3$ is to be determined.

Concept introduction:

Avogadro’s number is used to determine the number of atoms present in $1\text{mol}$ of an element.

Therefore, $1\text{mol}=6.022\times {10}^{23}$