Solution Summary: The author explains that the equilibrium constant of an acid dissociation reaction depends on the strength of the acid involved in the reaction.
Interpretation: The value of pKa for the given compound is to be calculated.
Concept introduction: The equilibrium constant of an acid dissociation reaction depends on the strength of an acid involved in the reaction. The Ka value is large for strong acids and small for weak acids.
Acid dissociation constant Ka represents the acidity of an acid in a solution.
For an acid dissociation reaction,
HA+H2O⇌H3O++A−
Ka=[H3O+][A−][HA]
pKa=−logKa
The strength of an acid decreases as the value of pKa increases.
Answer to Problem 2.45P
The value of pKa for the given compound is 9.3279.
Explanation of Solution
The given value of Ka is 4.7×10−10.
The value of pKa is calculated by the formula,
pKa=−logKa
Substitute the value of Ka in the above formula to calculate the value of pKa.
Hence, the value of pKa for the given compound is 9.3279.
Conclusion
The value of pKa for the given compound is 9.3279.
Expert Solution
Interpretation Introduction
(b)
Interpretation: The value of pKa for the given compound is to be calculated.
Concept introduction: The equilibrium constant of an acid dissociation reaction depends on the strength of an acid involved in the reaction. The Ka value is large for strong acids and small for weak acids.
Acid dissociation constant Ka represents the acidity of an acid in a solution.
For an acid dissociation reaction,
HA+H2O⇌H3O++A−
Ka=[H3O+][A−][HA]
pKa=−logKa
The strength of an acid decreases as the value of pKa increases.
Answer to Problem 2.45P
The value of pKa for the given compound is 4.6383.
Explanation of Solution
The given value of Ka is 2.3×10−5.
The value of pKa is calculated by the formula,
pKa=−logKa
Substitute the value of Ka in the above formula to calculate the value of pKa.
Hence, the value of pKa for the given compound is 4.6383.
Conclusion
The value of pKa for the given compound is 4.6383.
Expert Solution
Interpretation Introduction
(c)
Interpretation: The value of pKa for the given compound is to be calculated.
Concept introduction: The equilibrium constant of an acid dissociation reaction depends on the strength of an acid involved in the reaction. The Ka value is large for strong acids and small for weak acids.
Acid dissociation constant Ka represents the acidity of an acid in a solution.
For an acid dissociation reaction,
HA+H2O⇌H3O++A−
Ka=[H3O+][A−][HA]
pKa=−logKa
The strength of an acid decreases as the value of pKa increases.
Answer to Problem 2.45P
The value of pKa for the given compound is 0.23.
Explanation of Solution
The given value of Ka is 5.9×10−1.
The value of pKa is calculated by the formula,
pKa=−logKa
Substitute the value of Ka in the above formula to calculate the value of pKa.
Consider a solution of 0.00304 moles of 4-nitrobenzoic acid (pKa = 3.442) dissolved in 25 mL water and titrated with 0.0991 M NaOH. Calculate the pH at the equivalence point
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