Concept explainers
Interpretation:
The structural formulas for the cis and trans isomers of hydrindane has to be drawn in its most stable conformation and among the two drawn isomers, the more stable isomer has to be given.
Concept Introduction:
Cis, Trans Isomerism in Cycloalkanes:
When a cycloalkane ring has substituents on two or more carbon atoms, then the cycloalkane ring show a type of stereoisomerism called cis, trans isomerism.
Cis, trans isomers have same molecular formula and same connectivity of their atoms, but the arrangement of atoms in space would be different which be interconverted by rotation about single bonds.
In cis isomer, the substituents are on the same side of the ring.
In trans isomer, the substituents are on the opposite sides of the ring.
Bicycloalkane:
Bicycloalkanes are cycloalkane with two rings that are shared by two carbon atoms. The shared carbon atoms are called bridgehead carbons and the carbon chain connecting them is called a bridge.
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Organic Chemistry
- Compounds X and Y both have the formula C7H14. Both X and Y react with one molar equivalent of hydrogen in the presence of a palladium catalyst to form 2-methylhexane. The heat of hydrogenation of X is greater than that of Y. Both X and Y react with HCI to give the same single C₂H₁5Cl compound as the major product. What is the structure of X? • In cases where there is more than one answer, just draw one. 7 0▾ ChemDoodleⓇ 146arrow_forwardCompounds X and Y both have the formula C7H₁4. Both X and Y react with one molar equivalent of hydrogen in the presence of a palladium catalyst to form 2-methylhexane. The heat of hydrogenation of X is greater than that of Y. Both X and Y react with HCI to give the same single C7H15Cl compound as the major product. What is the structure of X? • In cases where there is more than one answer, just draw one. 23 ▾ Sn [F ChemDoodleⓇ 146arrow_forwardOnly three stereoisomers are possible for 2,3-dibromo-2, 3-dichlorobutane. Draw them, indicating which pair are enantiomers (optical isomers). Why does the other isomer not have an enantiomer?arrow_forward
- The energy difference between a tert-butyl group going from equatorial to axial in a cyclohexane is 18.3 kJ/mol. When two of the carbon atoms are replaced with oxygen atoms (molecule B) the energy difference between the two chair conformations drops to 5.9 kJ/mol. Explain this difference. (Hint: Consider what makes putting groups axial unfavorable).arrow_forwardIn the drawing areas below, draw the two conformations of trans-1-bromo-4-fluorocyclohexane that are typically the most stable. Be sure your drawings make it possible to distinguish between the conformations. After you've drawn the conformations, answer the question below the drawing areas. X chair flip Click and drag to start drawing a structure. Of the two conformations you drew above, which is the more stable? ○ left O right O they are equally stable cannot decide without more information 'o X Click and drag to start drawing a structure. X ☐ : G &arrow_forwardDraw all the isomers of C5H₁0. Clearly show stereochemistry if stereoisomers are possible. Step 1: Start by drawing all the isomers with double bonds. • Consider constitutional isomers, then stereoisomers. Step 2: Draw all isomers containing a ring. • Consider constitutional isomers, then stereoisomers. Step 2: Next consider isomers containing a ring. The largest ring possible with this molecular formula contains 5 carbons, while the smallest possible ring contains 3 carbons. Draw an isomer containing a 5-carbon ring. Rings More Select Draw / C H Erase Consider a 4-carbon ring of C5H₁0. Draw stereoisomers, if applicable. Select Draw Rings More C H Erasearrow_forward
- sketch the various conformational isomers of 1,3-dimethylcyclohexane. Indicate the position (axial/equatorial) of each of the methyl groups in each structure.arrow_forwardThe heat of combustion of cis-1,2-dimethylcyclopropane is larger than that of the trans isomer. Which isomer is more stable? Use drawings to explain this difference instability.arrow_forwardAs we learned in Chapter 4, monosubstituted cyclohexanes exist as an equilibrium mixture of two conformations having either an axial or equatorial substituent. When R = CH2CH3, Keq for this process is 23.When R = C(CH3)3, Keq for this process is 4000. a.When R = CH2CH3, which conformation is present in higher concentration? b.Which R shows the higher percentage of equatorial conformation at equilibrium? c. Which R shows the higher percentage of axial conformation at equilibrium? d. For which R is ΔGo more negative? e.How is the size of R related to the amount of axial and equatorial conformations at equilibrium?arrow_forward
- Select the more stable conformation overall. D A.arrow_forwardIt is easy to imagine a cyclohexane as a flat hexagon and a lot of the time we draw it that way. Looking at 1,3,5-triethylcyclohexane we cannot tell the stability of the molecule from looking at the flat 2D drawing. Explain why we need to look at the 3D configuration and what conformation (axial,equatorial) would each of the three ethyl groups be in for the most stable configuration.arrow_forwardWhich of the following statement is false about conjugated systems? A conjugated system is more stable than an unconjugated A system. The s-trans isomer is favored over the s-cis isomer. A conjugated system has C multiple resonance structures. A conjugated system can only D contain two alkenes.arrow_forward
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