INSTRUMENTAL ANALYSIS-ACCESS >CUSTOM<
INSTRUMENTAL ANALYSIS-ACCESS >CUSTOM<
7th Edition
ISBN: 9781337783439
Author: Skoog
Publisher: CENGAGE C
Question
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Chapter 2, Problem 2.2QAP
Interpretation Introduction

(a)

Interpretation:

The voltage V2 should be calculated.

Concept introduction:

When resistors are in series, a voltage divider. V = V1 + V2 + V3

The current in a series circuit is everywhere the same. In other words, I = I1 = I2 = I3

The total resistance Rs of a series circuit is equal to the sum of the resistances of the individual components. Rs = R1 + R2 + R3

Ohm’s law;

Ohm’s law describes the relationship among voltage, resistance, and current in a resistive series circuit.

V = IR

Interpretation Introduction

(b)

Interpretation:

The power loss in resistor R2 should be determined.

Concept introduction:

When resistors are in series, a voltage divider. V = V1 + V2 + V3

The current in a series circuit is everywhere the same. In other words, I = I1 = I2 = I3

The total resistance Rs of a series circuit is equal to the sum of the resistances of the individual components. Rs = R1 + R2 + R3

Ohm’s law;

Ohm’s law describes the relationship among voltage, resistance, and current in a resistive series circuit.

V = IR

V = Voltage I = Current R = resistant

Power rule;

P = V I

P = Power V = voltage I = Current

Interpretation Introduction

(c)

Interpretation:

The fraction of total power lost by the circuit would be dissipated in in resistor R2 should be calculated.

Concept introduction:

When resistors are in series, a voltage divider. V = V1 + V2 + V3

The current in a series circuit is everywhere the same. In other words, I = I1 = I2 = I3

The total resistance Rs of a series circuit is equal to the sum of the resistances of the individual components. Rs = R1 + R2 + R3

Ohm’s law;

Ohm’s law describes the relationship among voltage, resistance, and current in a resistive series circuit.

V = IR

V = Voltage I = Current R = resistant

Power rule;

P = V I

P = Power V = voltage I = Current

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