Explanation Given Information: The width of the iceberg in the water in the paper = h The width of the iceberg in the paper = H The height of the iceberg = L The specific gravity of the water = 1 The specific gravity of the iceberg = 0.88 Let width of the iceberg into the paper = L Force of Buoyancy on iceberg = Weight of the iceberg For the body to be in neutral equilibrium, Meta centre should be at the centre of the gravity G M = I V d i s p − B G (GM=0) BG − the distance between the centre of buoyancy and the centre of gravity I − Moment of the Inertia V disp − Volume of water displaced Calculation: B u o y a n c y f o r c e = V o l u m e o f t h e w a t e r d i s p l a c e d × g × S G l × 1000 W e i g h t o f t h e i c e b e r g = V o l u m e o f t h e i c e b e r g × g × S G b × 1000 V o l u m e o f t h e w a t e r d i s p l a c e d = L h L V o l u m e o f t h e i c e b e r g = L H L L L H × 0

8th Edition

ISBN: 9789385965494

Author: Frank White

Publisher: MCGRAW-HILL HIGHER EDUCATION

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Chapter 2, Problem 2.129P

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The condition for the iceberg to be in neutral equilibrium at a given position.

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Chapter 2, Problem 2.128P

Chapter 2, Problem 2.130P

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Chapter 2 Solutions

Fluid Mechanics, 8 Ed

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