Explanation Given: Height of air, h a = 60 cm. Height of oil, h o = 80 cm. Height of water, h w = 90 cm. Concept Used: Force acting on the panel is given by F = p . A Where p is the pressure in N/m 2 and A is the area in m 2 . Pressure p is given by p = ρ g h Where ρ is the density in kg/m 3 and h is the height in m. Calculation: From the table of “Properties of some common liquids”, we find Density of water, ρ w = 998 kg/m 3 . Density of oil, ρ o = 891 kg/m 3 . The force acts at the centroid of the panel A B . The centroid of the panel A B is located at 45 cm above the point B . The force acting on the panel A B is F A B = p G . A A B Where, A A B is the area of the panel A B and p G is the pressure at the centroid of the panel A B . The above equation can be written as F A B = p G To determine (b) The gage pressure of air if the hydrostatic force on the bottom panel B C is 97 kN.

8th Edition

ISBN: 9789385965494

Author: Frank White

Publisher: MCGRAW-HILL HIGHER EDUCATION

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Chapter 2, Problem 2.101P

To determine

(a)

The gage pressure of air if the hydrostatic force on panel AB is 48 kN.

To determine

(b)

The gage pressure of air if the hydrostatic force on the bottom panel BC is 97 kN.

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Chapter 2, Problem 2.100P

Chapter 2, Problem 2.102P

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(a) The gage pressure of air if the hydrostatic force on panel A B is 48 kN.

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(a) The gage pressure of air if the hydrostatic force on panel AB is 48 kN.

(b) The gage pressure of air if the hydrostatic force on the bottom panel BC is 97 kN.

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Chapter 2 Solutions

(a)

The gage pressure of air if the hydrostatic force on panel AB is 48 kN.

(b)

The gage pressure of air if the hydrostatic force on the bottom panel BC is 97 kN.