EBK GENERAL CHEMISTRY: THE ESSENTIAL CO
EBK GENERAL CHEMISTRY: THE ESSENTIAL CO
7th Edition
ISBN: 8220106637203
Author: Chang
Publisher: YUZU
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Chapter 19.8, Problem 2PE
Interpretation Introduction

Interpretation:

The current (in amperes) is passed that through an electrolytic cell containing molten MgCl2 has to be calculated.

Concept introduction:

Standard reduction potential: The voltage associated with a reduction reaction at an electrode when all solutes are 1M and all gases are at 1 atm. The hydrogen electrode is called the standard hydrogen electrode (SHE).

Standard emf: Eocell is composed of a contribution from the anode and a contribution from the cathode is given by,

Ecello=EcathodeoEanodeo

Where both Ecathodeo and Eanodeo are the standard reduction potentials of the electrodes.

Electrolysis: The process in which electrical energy is used to cause a non-spontaneous chemical reaction to occur. An electrolytic cell is an apparatus for carrying out electrolysis.

In a spontaneous reaction standard emf of a reaction is positive; if the value if negative then it is non-spontaneous and external energy (electrical energy) is applied to carry out that reaction.

During electrolysis, cations are reduced at cathode and anions are oxidized at anode. And in aqueous solutions water itself may be oxidized and/or reduced depends on the nature of other species involved/ present.

Quantitative aspects of Electrolysis:

The mass of product formed (or reactant consumed) at an electrode is proportional to both the amount of electricity transferred at the electrode and the molar mass of the substance.

The mass of product is calculated as follows,

  • Convert Current into coulomb using (Current)×(time)=no.ofCoulomb
  • Convert number of Coulombs into mole of electrons using moleofe-=no.ofCoulombFaradayconstant

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LTS Solid: AT=Te-Ti Trial 1 Trial 2 Trial 3 Average ΔΗ Mass water, g 24.096 23.976 23.975 Moles of solid, mol 0.01763 001767 0101781 Temp. change, °C 2.9°C 11700 2.0°C Heat of reaction, J -292.37J -170.473 -193.26J AH, kJ/mole 16.58K 9.647 kJ 10.85 kr 16.58K59.64701 KJ mol 12.35k Minimum AS, J/mol K 41.582 mol-k Remember: q = mCsAT (m = mass of water, Cs=4.184J/g°C) & qsin =-qrxn & Show your calculations for: AH in J and then in kJ/mole for Trial 1: qa (24.0969)(4.1845/g) (-2.9°C)=-292.37J qsin = qrxn = 292.35 292.37J AH in J = 292.375 0.2923kJ 0.01763m01 =1.65×107 AH in kJ/mol = = 16.58K 0.01763mol mol qrx Minimum AS in J/mol K (Hint: use the average initial temperature of the three trials, con Kelvin.) AS=AHIT (1.65×10(9.64×103) + (1.0 Jimai

Chapter 19 Solutions

EBK GENERAL CHEMISTRY: THE ESSENTIAL CO

Ch. 19.5 - Prob. 2PECh. 19.5 - Prob. 1RCCh. 19.7 - Prob. 1RCCh. 19.8 - Prob. 1RCCh. 19.8 - An aqueous solution of Mg(NO3)2 is electrolyzed....Ch. 19.8 - Prob. 2RCCh. 19.8 - Prob. 2PECh. 19.8 - Prob. 3RCCh. 19 - Prob. 19.1QPCh. 19 - Prob. 19.2QPCh. 19 - Prob. 19.3QPCh. 19 - Prob. 19.4QPCh. 19 - Prob. 19.5QPCh. 19 - Prob. 19.6QPCh. 19 - 19.7 What is the difference between the...Ch. 19 - Prob. 19.8QPCh. 19 - Prob. 19.9QPCh. 19 - Prob. 19.10QPCh. 19 - Prob. 19.11QPCh. 19 - Prob. 19.12QPCh. 19 - Prob. 19.13QPCh. 19 - 19.14 Which of the following reagents can oxidize...Ch. 19 - 19.15 Consider the following half-reactions: (aq)...Ch. 19 - 19.16 Predict whether the following reactions...Ch. 19 - Prob. 19.17QPCh. 19 - Prob. 19.18QPCh. 19 - Prob. 19.19QPCh. 19 - Prob. 19.20QPCh. 19 - Prob. 19.21QPCh. 19 - Prob. 19.22QPCh. 19 - Prob. 19.23QPCh. 19 - Prob. 19.24QPCh. 19 - Prob. 19.25QPCh. 19 - Prob. 19.26QPCh. 19 - Prob. 19.27QPCh. 19 - Prob. 19.28QPCh. 19 - Prob. 19.29QPCh. 19 - Prob. 19.30QPCh. 19 - Prob. 19.31QPCh. 19 - Prob. 19.33QPCh. 19 - Prob. 19.34QPCh. 19 - 19.35 Explain the differences between a primary...Ch. 19 - Prob. 19.36QPCh. 19 - Prob. 19.37QPCh. 19 - Prob. 19.38QPCh. 19 - Prob. 19.39QPCh. 19 - Prob. 19.40QPCh. 19 - Prob. 19.41QPCh. 19 - Prob. 19.42QPCh. 19 - 19.43 What is the difference between a galvanic...Ch. 19 - Prob. 19.44QPCh. 19 - Prob. 19.45QPCh. 19 - Prob. 19.46QPCh. 19 - Prob. 19.47QPCh. 19 - Prob. 19.48QPCh. 19 - Prob. 19.49QPCh. 19 - Prob. 19.50QPCh. 19 - 19.51 Calculate the amounts of Cu and Br2 produced...Ch. 19 - Prob. 19.52QPCh. 19 - Prob. 19.53QPCh. 19 - Prob. 19.54QPCh. 19 - 19.55 What is the hourly production rate of...Ch. 19 - Prob. 19.56QPCh. 19 - Prob. 19.57QPCh. 19 - Prob. 19.58QPCh. 19 - Prob. 19.59QPCh. 19 - Prob. 19.60QPCh. 19 - Prob. 19.61QPCh. 19 - Prob. 19.62QPCh. 19 - Prob. 19.63QPCh. 19 - Prob. 19.64QPCh. 19 - Prob. 19.65QPCh. 19 - 19.66 A sample of iron ore weighing 0.2792 g was...Ch. 19 - Prob. 19.67QPCh. 19 - Prob. 19.68QPCh. 19 - Prob. 19.69QPCh. 19 - Prob. 19.70QPCh. 19 - Prob. 19.71QPCh. 19 - Prob. 19.72QPCh. 19 - Prob. 19.73QPCh. 19 - Prob. 19.74QPCh. 19 - Prob. 19.75QPCh. 19 - Prob. 19.76QPCh. 19 - Prob. 19.77QPCh. 19 - Prob. 19.78QPCh. 19 - Prob. 19.79QPCh. 19 - Prob. 19.80QPCh. 19 - Prob. 19.81QPCh. 19 - Prob. 19.82QPCh. 19 - Prob. 19.83QPCh. 19 - Prob. 19.84QPCh. 19 - Prob. 19.86QPCh. 19 - Prob. 19.87QPCh. 19 - Prob. 19.88QPCh. 19 - Prob. 19.89QPCh. 19 - Prob. 19.90QPCh. 19 - Prob. 19.91QPCh. 19 - Prob. 19.92QPCh. 19 - Prob. 19.93QPCh. 19 - Prob. 19.94QPCh. 19 - Prob. 19.95QPCh. 19 - Prob. 19.96QPCh. 19 - Prob. 19.97QPCh. 19 - Prob. 19.98QPCh. 19 - Prob. 19.99QPCh. 19 - Prob. 19.100QPCh. 19 - Prob. 19.101QPCh. 19 - 19.102 The magnitudes (but not the signs) of the...Ch. 19 - Prob. 19.103QPCh. 19 - Prob. 19.104QPCh. 19 - Prob. 19.105QPCh. 19 - Prob. 19.106QPCh. 19 - Prob. 19.107QPCh. 19 - Prob. 19.108QPCh. 19 - Prob. 19.109QPCh. 19 - Prob. 19.110QPCh. 19 - 19.111 A spoon was silver-plated electro lyrically...Ch. 19 - Prob. 19.112QPCh. 19 - Prob. 19.113QPCh. 19 - Prob. 19.114QPCh. 19 - Prob. 19.115QPCh. 19 - Prob. 19.116QPCh. 19 - Prob. 19.117QPCh. 19 - Prob. 19.118QPCh. 19 - Prob. 19.119QPCh. 19 - Prob. 19.120QPCh. 19 - Prob. 19.121SPCh. 19 - Prob. 19.122SPCh. 19 - Prob. 19.123SPCh. 19 - Prob. 19.124SPCh. 19 - Prob. 19.125SPCh. 19 - Prob. 19.126SPCh. 19 - Prob. 19.128SPCh. 19 - Prob. 19.129SPCh. 19 - Prob. 19.130SP
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Electrolysis; Author: Tyler DeWitt;https://www.youtube.com/watch?v=dRtSjJCKkIo;License: Standard YouTube License, CC-BY