Chapter 19, Problem 19.90QP

Interpretation Introduction

Interpretation:

The current used in the electrolysis of $\text{NaCl}$ has to be calculated in accordance with the given conditions.

Concept Introduction:

• Electrolysis is the process in which the electric current is used for the initiation of a non-spontaneous reaction. The process is widely used for the separation of elements from a mixture or ore.  The process of electrolysis is carried out in an electrolytic cell.
• ${\text{p}}^{\text{H}}$ is the negative logarithm of the concentration of hydrogen ion in a solution.

${\text{p}}^{\text{H}}=-\log \left[{\text{H}}^{+}\right]$

  ${\text{p}}^{\text{OH}}$ is the negative logarithm of the concentration of hydroxide ion in the solution.

${\text{p}}^{\text{OH}}=-\log \left[{\text{OH}}^{-}\right]$

  For all aqueous solution at $\text{25}°\text{C}$ the ${\text{p}}^{\text{H}}$ and ${\text{p}}^{\text{OH}}$ related as given below,

${\text{p}}^{\text{H}}+{\text{p}}^{\text{OH}}=14.0$

• The amount of electrical charge that is passing through a circuit depends upon the amount and time of the flow of current.  The electrical charge is measured in Coulomb.

  $\text{Q=}\frac{\text{I}}{\text{t}}$

  Where,

  $\text{Q}$ is the charge in Coulomb

  $\text{I}$ is the current in Ampere

  $\text{t}$ is the time in second