The difference in the boiling point of imidazole and N-methylimidazole has to be explained. Concept Introduction: Imidazole is the aromatic compound and also the heterocyclic ring of histidine. It exists in both protonated and non-protonated form at pH = 7.4 . The lone pair on first nitrogen are a part of the pi cloud as they are present in p orbital whereas the lone pair electrons on third nitrogen are not a part of pi cloud because they are perpendicular to the p orbitals.

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Answer 1

Question

Chapter 19.7, Problem 16P

Interpretation Introduction

Interpretation:

The difference in the boiling point of imidazole and N-methylimidazole has to be explained.

Concept Introduction:

Imidazole is the aromatic compound and also the heterocyclic ring of histidine. It exists in both protonated and non-protonated form at pH=7.4. The lone pair on first nitrogen are a part of the pi cloud as they are present in p orbital whereas the lone pair electrons on third nitrogen are not a part of pi cloud because they are perpendicular to the p orbitals.

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Answer 2

Question

Chapter 19.7, Problem 16P

Interpretation Introduction

Interpretation:

The difference in the boiling point of imidazole and N-methylimidazole has to be explained.

Concept Introduction:

Imidazole is the aromatic compound and also the heterocyclic ring of histidine. It exists in both protonated and non-protonated form at pH=7.4. The lone pair on first nitrogen are a part of the pi cloud as they are present in p orbital whereas the lone pair electrons on third nitrogen are not a part of pi cloud because they are perpendicular to the p orbitals.

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Answer 3

Question

Chapter 19.7, Problem 16P

Interpretation Introduction

Interpretation:

The difference in the boiling point of imidazole and N-methylimidazole has to be explained.

Concept Introduction:

Imidazole is the aromatic compound and also the heterocyclic ring of histidine. It exists in both protonated and non-protonated form at pH=7.4. The lone pair on first nitrogen are a part of the pi cloud as they are present in p orbital whereas the lone pair electrons on third nitrogen are not a part of pi cloud because they are perpendicular to the p orbitals.

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Answer 4

Question

Chapter 19.7, Problem 16P

Interpretation Introduction

Interpretation:

The difference in the boiling point of imidazole and N-methylimidazole has to be explained.

Concept Introduction:

Imidazole is the aromatic compound and also the heterocyclic ring of histidine. It exists in both protonated and non-protonated form at pH=7.4. The lone pair on first nitrogen are a part of the pi cloud as they are present in p orbital whereas the lone pair electrons on third nitrogen are not a part of pi cloud because they are perpendicular to the p orbitals.

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Answer 5

Chapter 19.7, Problem 16P

Interpretation Introduction

Interpretation:

The difference in the boiling point of imidazole and N-methylimidazole has to be explained.

Concept Introduction:

Imidazole is the aromatic compound and also the heterocyclic ring of histidine. It exists in both protonated and non-protonated form at pH=7.4. The lone pair on first nitrogen are a part of the pi cloud as they are present in p orbital whereas the lone pair electrons on third nitrogen are not a part of pi cloud because they are perpendicular to the p orbitals.

Answer 6

Chapter 19.7, Problem 16P

Interpretation Introduction

Interpretation:

The difference in the boiling point of imidazole and N-methylimidazole has to be explained.

Concept Introduction:

Imidazole is the aromatic compound and also the heterocyclic ring of histidine. It exists in both protonated and non-protonated form at pH=7.4. The lone pair on first nitrogen are a part of the pi cloud as they are present in p orbital whereas the lone pair electrons on third nitrogen are not a part of pi cloud because they are perpendicular to the p orbitals.

Answer 7

Chapter 19.7, Problem 16P

Interpretation Introduction

Interpretation:

The difference in the boiling point of imidazole and N-methylimidazole has to be explained.

Concept Introduction:

Imidazole is the aromatic compound and also the heterocyclic ring of histidine. It exists in both protonated and non-protonated form at pH=7.4. The lone pair on first nitrogen are a part of the pi cloud as they are present in p orbital whereas the lone pair electrons on third nitrogen are not a part of pi cloud because they are perpendicular to the p orbitals.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 19.1 - Name the following:Ch. 19.2 - Prob. 3P Ch. 19.2 - Prob. 4P Ch. 19.3 - Draw the product of each of the following...Ch. 19.5 - Prob. 6P Ch. 19.5 - Explain why cyclopentadiene (pKa = 15) is more...Ch. 19.5 - When pyrrole is added to a dilute solution of...Ch. 19.6 - Prob. 10P Ch. 19.6 - How to the mechanisms of the following reactions...Ch. 19.6 - Prob. 12P

Solution Summary: The author explains the difference in the boiling point of imidazole and N-methylimi

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