(a) Explanation Given Information: The weight of the block A ( W A ) is 10 lb. The weight of the plate B ( W B ) is 40 lb. The spring constant ( k ) is 60 lb/ft . The plate B is slowly moved with amplitude ( x m ) is 2.4 in . . The acceleration due to gravity ( g ) value is 32.2 ft/s 2 . Calculation: Calculate the total weight of the block A and plate B using the relation: W t o t a l = W A + W B Substitute 10 lb for W A and 40 lb for W B . W t o t a l = 10 + 40 = 50 lb Calculate the mass ( m ) of the block using the relation: m = W t o t a l g Substitute 50 lb for W t o t a l and 32.2 ft/s 2 for g . m = 50 32.2 = 1.5528 lb ⋅ s 2 / ft Calculate the natural circular frequency ( ω n ) using the relation: ω n = k m Substitute 60 lb/ft for k and 1 (b) To determine The corresponding smallest allowable value of the coefficient ( μ s ) of static friction.

Vector Mechanics for Engineers: Statics and Dynamics

11th Edition

ISBN: 9780073398242

Author: Ferdinand P. Beer, E. Russell Johnston Jr., David Mazurek, Phillip J. Cornwell, Brian Self

Publisher: McGraw-Hill Education

See similar textbooks

Videos

Question

Chapter 19.1, Problem 19.9P

(a)

To determine

The amplitude (xm) and frequency (fn) of the resulting motion.

(b)

To determine

The corresponding smallest allowable value of the coefficient (μs) of static friction.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 19.1, Problem 19.8P

Chapter 19.1, Problem 19.10P

Students have asked these similar questions

The forces Qy=12 kNQy=12kN and Qz=16 kNQz=16kN act on the profile at the shear center C. Calculate: a) Shear flow at point B (2 points)b) Shear stress at point D (3 points)

Consider the feedback controlled blending system shown below, which is designed to keep theoutlet concentration constant despite potential variations in the stream 1 composition. The density of all streamsis 920 kg/m3. At the nominal steady state, the flow rates of streams 1 and 2 are 950 and 425 kg/min,respectively, the liquid level in the tank is 1.3 m, the incoming mass fractions are x1 = 0.27, x2 = 0.54. Noticethe overflow line, indicating that the liquid level remains constant (i.e. any change in total inlet flow ratetranslates immediately to the same change in the outlet flow rate). You may assume the stream 1 flowrate andthe stream 2 composition are both constant. Use minutes as the time unit throughout this problem. d) Derive the first order process and disturbance transfer functions;Gp= Kp/(tou*s+1) and Gd=Kd/(tou*s+1) and calculate and list the values and units of the parameters. e) Using the given information, write the general forms of Gm, GIP, and Gv below(in terms of…

a) Briefly explain what ratio control is. Give an example of a common chemical engineering situation in whichratio control would be useful and for that example state exactly how ratio control works (what would bemeasured, what is set, and how the controller logic works).b) Briefly explain what cascade control is. Give an example of a common chemical engineering situation inwhich cascade control would be useful and for that example state exactly how cascade control works (whatwould be measured, what is set, and how the controller logic works).

Chapter 19 Solutions

Vector Mechanics for Engineers: Statics and Dynamics

Ch. 19.1 - A particle moves in simple harmonic motion....Ch. 19.1 - Prob. 19.2P Ch. 19.1 - Prob. 19.3P Ch. 19.1 - Prob. 19.4P Ch. 19.1 - Prob. 19.5P Ch. 19.1 - Prob. 19.6P Ch. 19.1 - Prob. 19.7P Ch. 19.1 - Prob. 19.8P Ch. 19.1 - Prob. 19.9P Ch. 19.1 - Prob. 19.10P

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

The amplitude ( x m ) and frequency ( f n ) of the resulting motion.

Solution Summary: The author calculates the mass of the block A and plate B using the relation: m=W_totalg.

Videos

The amplitude (xm) and frequency (fn) of the resulting motion.

The corresponding smallest allowable value of the coefficient (μs) of static friction.

Want to see the full answer?

Chapter 19 Solutions