Binary Tree: Binary tree is a non-linear data structure which contains the node such as root node that is pointed to two child nodes. A root node will have left reference node and right reference node. A complete binary tree is a tree with the property that every node must have exactly two children, and in the last level the nodes should be from left to right. The analog for binary tree is given below: struct NodeName { int value; NodeName left; NodeName right; };

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Chapter 19, Problem 8RQE

Program Plan Intro

Binary Tree:

Binary tree is a non-linear data structure which contains the node such as root node that is pointed to two child nodes. A root node will have left reference node and right reference node.

A complete binary tree is a tree with the property that every node must have exactly two children, and in the last level the nodes should be from left to right.

The analog for binary tree is given below:

struct NodeName

{

int value;

NodeName left;

NodeName right;

};

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5. Assume the following definition for a node of a binary tree. public class Node { public int data; public Node left; public Node right; public Node (int d) { data = d; left = null; right = null; } } (a) Write a recursive function height (Node root) which calculates and returns the height of the binary tree rooted at the given root node. public static int height (Node root) { } (b) Consider the following recursive function: public static void fun (int a, int b, int c) int d - 3 - (b + c); if (a > 1) fun (a-1, ь, d); System.out.println (a + " " + b +" " + c) ; if(a > 1) fun (a-1, d, c); What is the output generated by calling: fun (3, 0, 2)? Answer:

C++ PROGRAMMINGTopic: Binary Search Trees Explain the c++ code below.: SEE ATTACHED PHOTO FOR THE PROBLEM INSTRUCTIONS It doesn't have to be long, as long as you explain what the important parts of the code do. (The code is already implemented and correct, only the explanation needed) node* left(node* p) { return p->left; } node* right(node* p) { return p->right; } node* sibling(node* p){ if(p != root){ node* P = p->parent; if(left(P) != NULL && right(P) != NULL){ if(left(P) == p){ return right(P); } return left(P); } } return NULL; } node* addRoot(int e) { if(size != 0){ cout<<"Error"<<endl; return NULL; } root = create_node(e,NULL); size++; return root; } node* addLeft(node* p, int e) {…

Read this: Complete the code in Visual Studio using C++ Programming Language - Give me the answer in Visual Studio so I can copy*** - Separate the files such as .cpp, .h, or .main if any! Develop a C++ "doubly" linked list class of your own that can hold a series of signed shorts Develop the following functionality: Develop a linked list node struct/class You can use it as a subclass like in the book (Class contained inside a class) You can use it as its own separate class Your choice Maintain a private pointer to a node class pointer (head) Constructor Initialize head pointer to null Destructor Make sure to properly delete every node in your linked list push_front(value) Insert the value at the front of the linked list pop_front() Remove the node at the front of the linked list If empty, this is a no operation operator << Display the contents of the linked list just like you would print a character string operator [] Treat like…