Starting Out with C++: Early Objects (9th Edition)
9th Edition
ISBN: 9780134400242
Author: Tony Gaddis, Judy Walters, Godfrey Muganda
Publisher: PEARSON
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Chapter 19, Problem 7PC
Program Plan Intro
Tree Copy Constructor
Program Plan:
- Define a class BTreeNode to create nodes for binary search tree items.
- Include all the required header files.
- Initialize a value to the node, and set the left child of node to leftp and right child of node to rightp.
- Define a class to create a Binary Search Tree.
- Create a copy constructor BST::BST(BST &t)that copies all the items present in the binary search tree.
- Create a destructor BST & BST::operator=(BST &t)for assignment operator.
- Create a function void BST::destroyTree that deallocates all storage for nodes of a tree using the destructor.
- Create a function int width that returns width of the tree.
- Create a function bool search to search a particular item in tree.
- Create a function leafCounter that counts no. of leaves present in a level.
- Create function void insert to insert nodes into the tree.
- Create a function void inorder to sort items in inorder traversal.
- Declare the main function.
- Prompt the user to enter 5 numbers to be inserted into tree.
- Sort the items present in the tree in inorder traversal and print the items.
- Copy all the items of the tree elements.
- Prompt the user to enter a new value to be entered into tree.
- Print the items present in new tree in order traversal.
- Print the items present in original tree using copy constructor.
- Print the items present in the new tree by reassigning the values of the old tree.
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Given the following struct that represents a binary tree:
struct Node {
int key:
Node "parent; Node "left; Node "right;
Nodelint k) : key(k), parent(nullptr), left(nullptr), right(nullptr) (I:
1:
Write a recursive function that prints out the nodes in a tree stored using the above structure in order to cout. The function prints the depth (root
depth is at 0) and key of that node separated by a colon (Example "O: 10\n" for root with key 10).
Your function CAN NOT create any local variables and can only use what is passed to the function. Use the below function signature (NOTE: this is
not a class method).
void inorderAndDepth(Node "node, int depth)
Binary Search Tree Empirical and Theoretical ResultsPart 1: we need to define a binary search tree data structure. Also, we need to implement the following functions:1. Insert Sorted: BSTREE insert(BSTREE root, int num): root points to a node in a binary search tree; num is a number to be inserted in the tree rooted at “root”. This function returns the root of the modified tree.2. Print Elements: void inorder traversal(BSTREE root, FILE *fp): root points to a node in a binary search tree. This function does not return anything, but prints out, to the file specified, the nodes in the tree rooted at “root” by performing an inorder traversal.
Part 2: Test the performance of the designed data structure using theoretical and experimental approaches as follows:1. Dataset 1-Dataset is sorted- Add code to insert the numbers 1...n in that order in an initially empty doubly linked list and a binary search tree.a. Run it on different values of n where :i. n = 20,000ii. n = 50,000iii. n =…
Programming language C++ problem
Chapter 19 Solutions
Starting Out with C++: Early Objects (9th Edition)
Ch. 19.1 - Prob. 19.1CPCh. 19.1 - Prob. 19.2CPCh. 19.1 - Prob. 19.3CPCh. 19.1 - Prob. 19.4CPCh. 19.1 - Prob. 19.5CPCh. 19.1 - Prob. 19.6CPCh. 19.2 - Prob. 19.7CPCh. 19.2 - Prob. 19.8CPCh. 19.2 - Prob. 19.9CPCh. 19.2 - Prob. 19.10CP
Ch. 19.2 - Prob. 19.11CPCh. 19.2 - Prob. 19.12CPCh. 19 - Prob. 1RQECh. 19 - Prob. 2RQECh. 19 - Prob. 3RQECh. 19 - Prob. 4RQECh. 19 - Prob. 5RQECh. 19 - Prob. 6RQECh. 19 - Prob. 7RQECh. 19 - Prob. 8RQECh. 19 - Prob. 9RQECh. 19 - Prob. 10RQECh. 19 - Prob. 11RQECh. 19 - Prob. 12RQECh. 19 - Prob. 13RQECh. 19 - Prob. 14RQECh. 19 - Prob. 15RQECh. 19 - Prob. 16RQECh. 19 - Prob. 17RQECh. 19 - Prob. 18RQECh. 19 - Prob. 19RQECh. 19 - Prob. 20RQECh. 19 - Prob. 1PCCh. 19 - Prob. 2PCCh. 19 - Prob. 3PCCh. 19 - Prob. 4PCCh. 19 - Prob. 5PCCh. 19 - Prob. 6PCCh. 19 - Prob. 7PCCh. 19 - Prob. 8PCCh. 19 - Prob. 9PCCh. 19 - Prob. 10PC
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