It has to be predicted whether the potential for the voltaic cell will be higher, lower or same as the standard potential and the verification of the prediction also has to be done. Concept introduction: According to the first law of thermodynamics , the change in internal energy of a system is equal ti the heat added to the sysytem minus the work done by the system. The equation is as follows. ΔU = Q - W ΔU = Change in internal energy Q = Heat added to the system W=Work done by the system In voltaic cell, the maximum cell potential is directly related to the free energy difference between the reactants and products in the cell. ΔG 0 = -nFE 0 n = Number of moles transferred per mole of reactant and products F = Faradayconstant=96485C/mol E 0 = Volts = Work(J)/Charge(C) The relation between standard cell potential and equilibrium constant is as follows. lnK = nE 0 0 .0257 at 298K The relation between solubility product K sp and equilibrium constant is as follows. K sp = e +lnK
It has to be predicted whether the potential for the voltaic cell will be higher, lower or same as the standard potential and the verification of the prediction also has to be done. Concept introduction: According to the first law of thermodynamics , the change in internal energy of a system is equal ti the heat added to the sysytem minus the work done by the system. The equation is as follows. ΔU = Q - W ΔU = Change in internal energy Q = Heat added to the system W=Work done by the system In voltaic cell, the maximum cell potential is directly related to the free energy difference between the reactants and products in the cell. ΔG 0 = -nFE 0 n = Number of moles transferred per mole of reactant and products F = Faradayconstant=96485C/mol E 0 = Volts = Work(J)/Charge(C) The relation between standard cell potential and equilibrium constant is as follows. lnK = nE 0 0 .0257 at 298K The relation between solubility product K sp and equilibrium constant is as follows. K sp = e +lnK
Solution Summary: The author explains that the voltaic cell's maximum cell potential is directly related to the free energy difference between the reactants and products in the cell.
Science that deals with the amount of energy transferred from one equilibrium state to another equilibrium state.
Chapter 19, Problem 84GQ
Interpretation Introduction
Interpretation:
It has to be predicted whether the potential for the voltaic cell will be higher, lower or same as the standard potential and the verification of the prediction also has to be done.
Concept introduction:
According to the first law of thermodynamics, the change in internal energy of a system is equal ti the heat added to the sysytem minus the work done by the system.
The equation is as follows.
ΔU = Q - WΔU = Change in internal energyQ = Heat added to the systemW=Work done by the system
In voltaic cell, the maximum cell potential is directly related to the free energy difference between the reactants and products in the cell.
ΔG0= -nFE0n = Number of moles transferred per mole of reactant and productsF = Faradayconstant=96485C/mol E0= Volts = Work(J)/Charge(C)
The relation between standard cell potential and equilibrium constant is as follows.
lnK = nE00.0257 at 298K
The relation between solubility product Ksp and equilibrium constant is as follows.
Complete the following reactions with the necessary reagents to complete the shown
transformation.
Example:
1.
2.
?
3.
018
Br
OH
Answer: H₂O, H2SO4, HgSO4
7:34
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Question 18 of 22
5G 50%
Submit
What is the pH of a buffer made from 0.220
mol of HCNO (Ka = 3.5 × 10-4) and 0.410
mol of NaCNO in 2.0 L of solution?
1
2
3
☑
4
5
6
C
7
8 |
9
+/-
0
×10
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Г
6:46 ✔
5G 58%
<
Question 7 of 22
Submit
What is the primary species in
solution at the halfway point in a
titration of NH3 with HBr?
A
NH3 and H+
B
NH₁+ and H+
C
NH4+
D
NH3 and NH4+
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