Explanation Given info: The kinetic energy of the electron is 1.51 eV . The electrostatic force is given by, F e = k | q 1 | | q 2 | r 2 = k q 1 q 2 r 2 Here, F e is the electrostatic force. q 1 is the charge of electron. q 2 is the charge of proton. r is the radius of orbit. k is the coulomb’s constant. The value of k is 8.99 × 10 9 N ⋅ m 2 / C . The charge of the proton is 1.6 × 10 − 19 C and charge of electron I s − 1.6 × 10 − 19 C . The centripetal force between electron and proton is, F c = m v 2 r Here, m is the mass of the electron. v is the speed of the electron. F c is the centripetal force between electron and proton. The electrostatic force is equal to the centripetal force. F e = F c Substitute m v 2 r for F c and k q 1 q 2 r 2 for F e in above equation. k q 1 q 2 r 2 = m v 2 r r = k q 1 q 2 m v 2 (1) The kinetic energy of the electron is, K = 1 2 m v 2 (2) Here, K is kinetic energy of the electron

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ISBN: 9780321976444

Author: James S. Walker

Publisher: PEARSON

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Chapter 19, Problem 76GP

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The radius of the orbit.

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Chapter 19, Problem 75GP

Chapter 19, Problem 77GP

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The radius of the orbit.

Solution Summary: The author explains the kinetic energy of the electron, the electrostatic force, and the centripetal force between electron and proton.

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The radius of the orbit.

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