Explanation Given information: The speed of the electron is 7.3 × 10 5 m / s . Refer the example 19-4 from textbook. The expression for the velocity of the electron is, v = e k m e r (1) Here, v is the velocity of the electron. k is the constant of Coulomb’s law. m e is the mass of the electron. r is the radius of the orbit. e is the charge of an electron. The value of k is 8.99 × 10 9 N ⋅ m 2 / C 2 . The mass of an electron is 9.11 × 10 − 31 kg and the charge of an electron is 1.6 × 10 − 19 C . Substitute 7.3 × 10 5 m / s for v , 9.11 × 10 − 31 kg for m e , 1.6 × 10 − 19 C for e and 8.99 × 10 9 N ⋅ m 2 / C 2 for k in equation (1)

5th Edition

ISBN: 9780321976444

Author: James S. Walker

Publisher: PEARSON

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Chapter 19, Problem 21PCE

To determine

The orbital radius of the electron.

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The orbital radius of the electron.

Solution Summary: The author explains the orbital radius of the electron and the constant of Coulomb's law.

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