Explanation Calculation: The given circuit diagram is shown in Figure 1. The conversion from mA to A is given by, 1 mA = 10 − 3 A Hence, the value of current source I 1 is, I 1 = 10 − 3 ∠ 0 ° A The conversion from 2 mA to A is given by, 2 mA = 2 × 10 − 3 A Hence, the value of current source I 2 is, I 1 = 2 × 10 − 3 ∠ 0 ° A To calculate Thevenin equivalent voltage external to resistor R 1 , replace the resistor by open circuit. The required circuit diagram is shown in Figure 2. Apply KVL in the first loop. V 1 = 20 V + V ...... (1) From the figure it can be seen that the dependent source forms the supernode. Apply KCL at the super node, V 5 k Ω = ( 1 ∠ 0 ° + 2 ∠ 0 ° ) × mA V = ( 5 k Ω ) ( 1 ∠ 0 ° + 2 ∠ 0 ° ) × mA = 15 ∠ 0 ° V Substitute 15 ∠ 0 ° V for V in equation (1). V 1 = 20 ( 15 ∠ 0 ° V ) + 15 ∠ 0 ° V = 315 ∠ 0 ° V Therefore, the Thevenin equivalent voltage V T h is 315 ∠ 0 ° V

Introductory Circuit Analysis; Laboratory Manual For Introductory Circuit Analysis Format: Kit/package/shrinkwrap

13th Edition

ISBN: 9780134297446

Author: Boylestad, Robert L.

Publisher: Prentice Hall

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Chapter 19, Problem 32P

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