You have a particular interest in automobile engines, so you have secured a co-op position at an automobile company while you attend school. Your supervisor is helping you to learn about the operation of an internal combustion engine. She gives you the following assignment, related to a simulation of a new engine she is designing. A gas, beginning at PA = 1.00 atm, VA = 0.500 L, and TA = 27.0°C, is compressed from point A on the PV diagram in Figure P19.31 (page 530) to point B. This represents the compression stroke in a fourcycle gasoline engine. At that point, 132 J of energy is delivered to the gas at constant volume, taking the gas to point C. This represents the transformation of potential energy in the gasoline to internal energy when the spark plug fires. Your supervisor tells you that the internal energy of a gas is proportional to temperature (as we shall find in Chapter 20), the internal energy of the gas at point A is 200 J, and she wants to know what the temperature of the gas is at point C.
Figure P19.31
Want to see the full answer?
Check out a sample textbook solutionChapter 19 Solutions
Bundle: Physics For Scientists And Engineers With Modern Physics, Loose-leaf Version, 10th + Webassign Printed Access Card For Serway/jewett's Physics For Scientists And Engineers, 10th, Single-term
- Figure P21.37 shows a PV diagram for a gas that is compressed from Vi to Vf. Find the work done by the a. gas and b. environment during this process. Does energy enter the system or leave the system as a result of work? FIGURE P21.37arrow_forwardYou have a particular interest in automobile engines, so you have secured a co-op position at an automobile company while you attend school. Your supervisor is helping you to learn about the operation of an internal combustion engine. She gives you the following assignment, related to a simulation of a new engine she is designing. A gas, beginning at PA = 1.00 atm, VA = 0.500 L, and TA = 27.0C, is compressed from point A on the PV diagram in Figure P19.31 (page 530) to point B. This represents the compression stroke in a fourcycle gasoline engine. At that point, 132 J of energy is delivered to the gas at constant volume, taking the gas to point C. This represents the transformation of potential energy in the gasoline to internal energy when the spark plug fires. Your supervisor tells you that the internal energy of a gas is proportional to temperature (as we shall find in Chapter 20), the internal energy of the gas at point A is 200 J, and she wants to know what the temperature of the gas is at point C. Figure P19.31arrow_forwardIf a gas is compressed isothermally, which of the following statements is true? (a) Energy is transferred into the gas by heat. (b) No work is done on the gas. (c) The temperature of the gas increases. (d) The internal energy of the gas remains constant. (e) None of those statements is true.arrow_forward
- Two cylinders A and B of equal capacity are connected to each other via a stopcock. A contains a gas at standard temperature and pressure. B is completely evacuated. The entire system is thermally insulated. The stopcock is suddenly opened. Answer the following :(a) What is the final pressure of the gas in A and B?(b) What is the change in internal energy of the gas?arrow_forwardQuestion 1. An ideal diatomic gas contracts from 1.25 m3to 0.500 m3 at a constant pressure of 1.50 × 105P a. Draw a PV diagram and name this process thatoccurs at constant pressure. If the initial temperature is 425 K, calculate(a) the work done on the gas,(b) the change in internal energy of the gas,(c) the energy transfer, Q, and,(d) the final temperature.arrow_forwardI need help solving number 11. In question 1, they say U=(3/2)PV I found work on the gas as -3/2PV, so therefore Q should be 6/2PV but the answer key says 6PV.arrow_forward
- A sample of an ideal gas in a cylinder of volume 2.90 L at 928K and 2.89 atm expands to 8.46 L by two different pathways. Path A is an isothermal, reversible expansion. Path B has two steps. In the first step, the gas is cooled at constant volume to 1.05 atm. In the second step, the gas is heated and allowed to expand against a constant external pressure of 1.05 atm until the final volume is 8.46 L. Calculate the work for Path A and the work for path Barrow_forwardA gas increases in pressure from 2.00 atm to 6.00 atm at a constant volume of 1.00 m3 and then expands at constant pressure to a volume of 3.00 m3 before returning to its initial state as shown in Figure P12.31. How much work is done in one cycle?arrow_forwardConsider 2.5 moles of an ideal gas, which undergoes the process shown in the PV diagram below. Make sure you are mindful of units when you are performing these problems. PV Diagram Pressure (atm) 3.000 2.500 52.000 1.500 1.000 0.500 500 1000 A 1500 2000 Volume (cm^3) B 2500 3000arrow_forward
- A cylinder containing 1.41 mol of an ideal gas is surrounded by a large reservoir at a temperature of 3.69 °C. The gas is initially at a volume of 1.24 x 10-3 m³. The gas is compressed isothermally to a volume of 4.16 x 10-4 m². How much work W is done by the gas during the compression? Use R = 8.314 J/(mol-K) for the gas constant. W = How much heat Q flows into the gas during the compression? Q = Jarrow_forwardSix moles of an ideal gas are in a cylinder fitted at one end with a movable piston. The initial temperature of the gas is 27.0C and the pressure is constant. As part of a machine design project, calculate the final temperature of the gas after it has done 2.40 * 103 J of work.arrow_forwardA certain diatomic gas has the same specific heats as an ideal gas but a slightly different equation of state: PV = R(T + αT²), α = 0.001K¯¹. The temperature of the gas is raised from T₁ = 300K to 12 at constant pressure. It is found that work done on the gas is 70% higher than what would be on an ideal gas. Choose the correct statement(s). A. T₂ = 400K internal energy increases by 250R/mole B. T₂ = 400K internal energy increases by 350R/mole C. Total heat absorbed in the process is 450R/mole D. Total heat absorbed in the process is 520R/molearrow_forward
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning