In addition to the maternal effect genes that establish anterior/posterior polarity in the Drosophila embryo (like bicoid and nanos), other maternal effect genes, including dorsal, pelle, and Toll, independently determine dorsal/ventral polarity. The dorsal gene encodes a transcription factor (Dorsal), originally deposited in the egg cytoplasm, that determines ventralness in a concentration-dependent manner. As shown in the following figure(Wild type), a gradient of Dorsal nuclear localization exists in early embryos: Cells whose nuclei have the highest Dorsal protein concentration become the ventral-most cells, cells whose nuclei have no Dorsal protein aredorsal-most, and lateral cells “learn” their positions and fates through the particular intermediate Dorsal proteinlevels in their nuclei. The figure shows sections through blastoderm embryos, where D = dorsal and V = ventral
Embryos from mothers homozygous for dorsal null mutations are dorsalized-every cell along the dorsal/ventral axis “thinks” it is the ventral-most cell. Embryos from mothers homozygous for loss-of-function pelle mutations or heterozygous for gain-of-function (constitutively active) TollD> mutations show altered patterns of Dorsal protein localization, as shown in the figure. Pelle and Toll expression are unaltered in dorsal loss-of-function mutants (not shown).
a. | Describe the alterations in Dorsal protein localization in embryos produced by pelle-/pelle- or TollD/Toll+mutant mothers. |
b | Based on the information given, order the dorsal, pelle, and Toll genes in a pathway. |
c. | The two kinds of embryos described in part (a) die just before hatching. Describe their morphological mutant |
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Genetics: From Genes to Genomes
- In a mutant mouse, it was discovered that a gene "W" is moved from its original chromosomal locus to the telomere region, where chromatin is packed into heterochromatin. Given what we have learned about eukaryotic gene regulation, can you speculate how the expression of gene W in the new mouse line would be changed as compare to the normal mouse? elevated in the mutant mouse than in the wild-type mouse. cannot be determined. O reduced in the mutant mouse than in the wild-type mouse. change in the mutant mouse as compared to the wild-type mouse.arrow_forwarda) Do the loss of function phenotypes differ between the genes between the genes in figure 1? What does this mean? b) What are the two cell types responsible for producing maternal gene products involved in terminal patterning in the Drosophila cocyte? In which of these two cell types is each of the three genes expressed? c) Based on the phenotypes you observed for the three genes, and on the differences in their expression patterns, which one of the genes do you think is the localised determinant of terminal patterning? d❘ From the gain-of-function experiments, do trunk and torso like work upstream or downstream of torso? Explain. (4 m e) How might you test which of the trunk and torso-like genes acts upstream of the other? f) The torso gene has been shown to have another important role in Drosophila development outside of terminal patterning. What do you think would be a good first experiment to do to begin to investigate possible other roles for the trunk or torso - like genes? C a…arrow_forwardDrosophila females homozygous for loss-of-functionmutations in the gene aubergine are sterile. RNA-Seqexperiments show that in the ovaries of these females,the levels of RNAs for many kinds of transposable elements are more than 10× higher than in wild-type ovaries. The aubergine gene encodes a Piwi-family protein.a. Why do you think these females are sterile?b. Piwi proteins interact with piRNAs that are transcribed from piRNA gene clusters. Given that thelevels of many kinds of TEs are elevated in mutantovaries, what kinds of DNA sequences do youthink are located in these clusters?c. Many investigators think of piRNAs as a kind ofdefensive mechanism that protects organisms fromthe effects of new transposable elements that mightbe introduced into genomes, for example fromother species. Explainarrow_forward
- What would be the most likely effect of inhibiting the translation of hunchback mRNA throughout a Drosophila embryo?arrow_forwardFollowing a mutagenesis experiment to identify novel genes affecting the circadian clock in Drosophila melanogaster you discover several mutants. You start considering two of those mutants that you call c and d. The two homozygous c/c and d/d are arrhythmic (arrhythmic is the definition of their phenotype), whereas the two heterozygous C/c and D/d are rhythmic (rhythmic is the definition of their phenotype) with a 24h period. You make two true-breeding stocks: stock 3 homozygous for c and stock 4 homozygous for d. You cross them in both directions and in both cases you observe complementation with no difference between males and females. Then you take the progeny of one cross, for instance the F1 of Females 3 x Males 4, and you perform a Testcross. Out of 1000 flies resulting from the Testcross only 125 are rhythmic. What is the genotype of the F1 (progeny of Females 3 x Males 4). Select only one answer. 1. C/c D/d 2. C/C d/d 3. C/C D/D 4. c/c D/d…arrow_forwardFollowing a mutagenesis experiment to identify novel genes affecting the circadian clock in Drosophila melanogaster you discover several mutants. You start considering two of those mutants that you call c and d. The two homozygous c/c and d/d are arrhythmic (arrhythmic is the definition of their phenotype), whereas the two heterozygous C/c and D/d are rhythmic (rhythmic is the definition of their phenotype) with a 24h period. You make two true-breeding stocks: stock 3 homozygous for c and stock 4 homozygous for d. You cross them in both directions and in both cases you observe complementation with no difference between males and females. Then you take the progeny of one cross, for instance the F1 of Females 3 x Males 4, and you perform a Testcross. Out of 1000 flies resulting from the Testcross only 125 are rhythmic. Which is the genotype of the rhythmic flies resulting from the testcross? Select only one answer 1. C/C d/d 2. C/c D/d 3. C/c d/d 4. c/c…arrow_forward
- Following a mutagenesis experiment to identify novel genes affecting the circadian clock in Drosophila melanogaster you discover several mutants. You start considering two of those mutants that you call c and d. The two homozygous c/c and d/d are arrhythmic (arrhythmic is the definition of their phenotype), whereas the two heterozygous C/c and D/d are rhythmic (rhythmic is the definition of their phenotype) with a 24h period. You make two true-breeding stocks: stock 3 homozygous for c and stock 4 homozygous for d. You cross them in both directions and in both cases you observe complementation with no difference between males and females. Then you take the progeny of one cross, for instance the F1 of Females 3 x Males 4, and you perform a Testcross. Out of 1000 flies resulting from the Testcross only 125 are rhythmic. Comparing the number of flies expected for the Parental and the Recombinant genotypes, what can be concluded about the C and D loci? Select only one answer. 1. The…arrow_forwardFollowing a mutagenesis experiment to identify novel genes affecting the circadian clock in Drosophila melanogaster you discover several mutants. You start considering two of those mutants that you call c and d. The two homozygous c/c and d/d are arrhythmic (arrhythmic is the definition of their phenotype), whereas the two heterozygous C/c and D/d are rhythmic (rhythmic is the definition of their phenotype) with a 24h period. You make two true-breeding stocks: stock 3 homozygous for c and stock 4 homozygous for d. You cross them in both directions and in both cases you observe complementation with no difference between males and females. Then you take the progeny of one cross, for instance the F1 of Females 3 x Males 4, and you perform a Testcross. Out of 1000 flies resulting from the lestcross only 125 are rhythmic. Using the number of flies expected for the Parental and the Recombinant genotypes and the formula that defines recombination frequency, what is the distance between loci C…arrow_forwardFollowing a mutagenesis experiment to identify novel genes affecting the circadian clock in Drosophila melanogaster you discover several mutants. You start considering two of those mutants that you call c and d. The two homozygous c/c and d/d are arrhythmic (arrhythmic is the definition of their phenotype), whereas the two heterozygous C/c and D/d are rhythmic (rhythmic is the definition of their phenotype) with a 24h period. You make two true-breeding stocks: stock 3 homozygous for c and stock 4 homozygous for d. You cross them in both directions and in both cases you observe complementation with no difference between males and females. Then you take the progeny of one cross, for instance the F1 of Females 3 x Males 4, and you perform a Testcross. Out of 1000 flies resulting from the Testcross only 125 are rhythmic. What is the genotype of Males 4? Select only one answer. 01. C/C D/D O 2. C/C D/d O3. C/C d/d O 4. C/C D/D O 5. c/c D/d O 6. C/cd/d 07. c/c D/D O 8. C/C D/d O 9. c/cd/d Karrow_forward
- Following a mutagenesis experiment to identify novel genes affecting the circadian clock in Drosophila melanogaster you discover several mutants. You start considering two of those mutants that you call C and d. The two homozygous C/C and d/d are arrhythmic (arrhythmic is the definition of their phenotype), whereas the two heterozygous C/C and D/d are rhythmic (rhythmic is the definition of their phenotype) with a 24h period. You make two true-breeding stocks: stock 3 homozygous for C and stock 4 homozygous for d. You cross them in both directions and in both cases you observe complementation with no difference between males and females. Then you take the progeny of one cross, for instance the F1 of Females 3 x Males 4, and you perform a Testcross. Out of 1000 flies resulting from the Testcross only 125 are rhythmic. Using the number of flies expected for the Parental and the Recombinant genotypes and the formula that defines recombination frequency, what is the distance between loci C…arrow_forward5.5arrow_forwardBased on the partial diploid sketched shown in Figure 3, where cross-hatched rectangles and the red bar indicate mutations that inactivate that particular genetic element of the operon, state if expression of Lacl (Lac repressor) and LacZ (Beta-Galactosidase) is (select one of the options below for each genetic element and briefly justify your answer): constitutively ON (in the presence/absence of lactose) constitutively OFF (in the presence/absence of lactose) • inducible by lactose • not enough information given to conclude • none of the above FIGURE 3: lacl laco lacz- lacY lacl laco lacz lacYarrow_forward
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