(a) Interpretation: The given half reactions should be arranged in order of decreasing tendency to occur. Concept introduction: Any redox reaction consists of an oxidation half reaction and a reduction half reaction.
(a) Interpretation: The given half reactions should be arranged in order of decreasing tendency to occur. Concept introduction: Any redox reaction consists of an oxidation half reaction and a reduction half reaction.
Solution Summary: The author explains that half reactions should be arranged in order of decreasing tendency to occur.
Definition Definition Chemical reactions involving both oxidation and reduction processes. During a redox reaction, electron transfer takes place in such a way that one chemical compound gets reduced and the other gets oxidized.
Chapter 19, Problem 19.79SP
Interpretation Introduction
(a)
Interpretation:
The given half reactions should be arranged in order of decreasing tendency to occur.
Concept introduction:
Any redox reaction consists of an oxidation half reaction and a reduction half reaction.
Interpretation Introduction
(b)
Interpretation:
The strongest oxidizing agent & the reducing agents out of given chemical substances should be selected.
Concept introduction:
A reducing agent, or a reductant is a chemical species which loses electrons or donates electrons in a redox reaction while oxidizing agent is a chemical species which accepts electrons in a redox reaction.
Interpretation Introduction
(c)
Interpretation:
The cell which delivers the highest voltage should be selected.
Concept introduction:
The voltage delivers by a cell equals to the cell potential (Ecell).
Dr. Mendel asked his BIOL 260 class what their height was and what their
parent's heights were. He plotted that data in the graph below to determine if
height was a heritable trait.
A. Is height a heritable trait? If yes, what is the heritability value? (2 pts)
B. If the phenotypic variation is 30, what is the variation due to additive alleles?
(2 pts)
Offspring Height (Inches)
75
67.5
60
52.5
y = 0.9264x + 4.8519
55
60
65
MidParent Height (Inches)
70
75
12pt v
V
Paragraph B IUA
>
AT2 v
V
Experiment:
Each team will be provided with 5g of a mixture of acetanilide and salicylic acid. You will divide it into three 1.5 g portions in separate 125 mL Erlenmeyer flasks savıng some for melting point analysis. Dissolve the mixture in each flask in ~60mL of DI water by heating to boiling on a hotplate. Take the flasks off the hotplate once you have a clear solution and let them stand on the bench top for 5 mins and then allow them to cool as described below.
Sample A-Let the first sample cool slowly to room temperature by letting it stand on your lab bench, with occasional stirring to promote crystallization.
Sample B-Cool the second sample 1n a tap-water bath to 10-15 °C
Sample C-Cool the third sample in an ice-bath to 0-2 °C
Results:
weight after recrystalization and melting point temp.
A=0.624g,102-115°
B=0.765g, 80-105°
C=1.135g, 77-108
What is the percent yield of A,B, and C.
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