(a) Interpretation: The value of standard potential for the cell reaction needs to be determined in the PEM fuel cell. Concept introduction: In the cell, oxidation takes place at anode and reduction at cathode. The oxidation of aluminum and reduction of oxygen gas takes place. The overall cell reaction is sum of reaction at cathode and anode.
(a) Interpretation: The value of standard potential for the cell reaction needs to be determined in the PEM fuel cell. Concept introduction: In the cell, oxidation takes place at anode and reduction at cathode. The oxidation of aluminum and reduction of oxygen gas takes place. The overall cell reaction is sum of reaction at cathode and anode.
Solution Summary: The author explains that the value of standard potential for the cell reaction needs to be determined in the PEM fuel cell.
The value of standard potential for the cell reaction needs to be determined in the PEM fuel cell.
Concept introduction:
In the cell, oxidation takes place at anode and reduction at cathode. The oxidation of aluminum and reduction of oxygen gas takes place. The overall cell reaction is sum of reaction at cathode and anode.
Interpretation Introduction
(b)
Interpretation:
The cell voltage needs to be determined if partial pressure of hydrogen and oxygen gas is 6 atm and 0.20 atm respectively.
Concept introduction:
The Nernst equation of a cell is used to determine the electrode potential of the cell using the standard cell potential
The reaction queotient of the cell is ratio of concentration of products to reactants in the cell reaction.
The Nernst equation can be represented as follows:
E=Eo−2.303RTnFlogQ
Here, E is cell potential, Eo is standard cell potential, R is Universal gas constant, n is number of electrons involved in cell reaction, T is temperature, F is Faraday’s constant and Q us reaction quotient.
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Question 59 of 70
The volume of
1
unit of plasma is 200.0 mL
If the recommended dosage
for adult patients is 10.0 mL per kg of body mass, how many units are needed for
a patient with a body mass of 80.0
kg ?
80.0
kg
10.0
DAL
1
units
X
X
4.00
units
1
1
Jeg
200.0
DAL
L
1 units
X
200.0 mL
= 4.00 units
ADD FACTOR
*( )
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ANSWER
RESET
D
200.0
2.00
1.60 × 10³
80.0
4.00
0.0400
0.250
10.0
8.00
&
mL
mL/kg
kg
units/mL
L
unit
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110
19
Identify the starting material in the following reaction. Click the "draw structure" button to launch the
drawing utility.
draw structure ...
[1] 0 3
C10H18
[2] CH3SCH3
H
In an equilibrium mixture of the formation of ammonia from nitrogen and hydrogen, it is found that
PNH3 = 0.147 atm, PN2 = 1.41 atm and Pн2 = 6.00 atm. Evaluate Kp and Kc at 500 °C.
2 NH3 (g) N2 (g) + 3 H₂ (g)
K₂ = (PN2)(PH2)³ = (1.41) (6.00)³ = 1.41 x 104
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell