A steam—hydrocarbon reforming process is one method for producing hydrogen from fossil fuels for use in a fuel cell. In the first step, steam reacts with hydrocarbons, such as CH4 at high temperatures in the presence of a catalyst, yielding H 2 and CO. In the second step, the reaction of CO and H 2 O called the water-gas shift reaction removes toxic carbon monoxide and produces more hydrogen. Step 1: H 2 O ( g ) + CH 4 ( g ) → CO ( g ) + 3 H 2 ( g ) Step 2: CO ( g ) + H 2 O ( g ) → CO 2 ( g ) + H 2 ( g ) (a) In step 1, which element is oxidized and which is reduced? (b) In step 2, which element is oxidized and which is reduced? What is the oxidizing agent and reducing agent? (c) What are drawbacks of steam reforming in the production of hydrogen?
A steam—hydrocarbon reforming process is one method for producing hydrogen from fossil fuels for use in a fuel cell. In the first step, steam reacts with hydrocarbons, such as CH4 at high temperatures in the presence of a catalyst, yielding H 2 and CO. In the second step, the reaction of CO and H 2 O called the water-gas shift reaction removes toxic carbon monoxide and produces more hydrogen. Step 1: H 2 O ( g ) + CH 4 ( g ) → CO ( g ) + 3 H 2 ( g ) Step 2: CO ( g ) + H 2 O ( g ) → CO 2 ( g ) + H 2 ( g ) (a) In step 1, which element is oxidized and which is reduced? (b) In step 2, which element is oxidized and which is reduced? What is the oxidizing agent and reducing agent? (c) What are drawbacks of steam reforming in the production of hydrogen?
Solution Summary: The author explains that the element that is oxidized and reduced in step 1 should be stated. Oxidation is the process of adding oxygen or an electronegative element to the substance.
A steam—hydrocarbon reforming process is one method for producing hydrogen from fossil fuels for use in a fuel cell. In the first step, steam reacts with hydrocarbons, such as CH4 at high temperatures in the presence of a catalyst, yielding H2 and CO. In the second step, the reaction of CO and H2O called the water-gas shift reaction removes toxic carbon monoxide and produces more hydrogen. Step 1:
H
2
O
(
g
)
+ CH
4
(
g
)
→
CO
(
g
)
+ 3 H
2
(
g
)
Step 2:
CO
(
g
)
+ H
2
O
(
g
)
→
CO
2
(
g
)
+ H
2
(
g
)
(a) In step 1, which element is oxidized and which is reduced? (b) In step 2, which element is oxidized and which is reduced? What is the oxidizing agent and reducing agent? (c) What are drawbacks of steam reforming in the production of hydrogen?
1.
How many neighbors does the proton that produces the multiplet below have?
2.
3.
اللـ
Draw a partial structure from the multiplet below. (The integration of the multiplet is 6)
M
Using the additivity constants found in appendix G of your lab manual, calculate the approximate chemical
shifts of the protons indicated below. (Show your work!!!)
B
A
Br
SH
1) Suppose 0.1 kg ice at 0°C (273K) is in 0.5kg water at 20°C (293K). What is the change in entropy of the ice as it melts at 0°?
To produce the original "water gas" mixture, carbon (in a combustible form known as coke) is reacted with steam: 131.4 kJ + H20(g) + C(s) → CO(g) + H2(g) From this information and the equations in the previous problem, calculate the enthalpy for the combustion or carbon to form carbon dioxide.
kindly show me how to solve this long problem. Thanks
4.
An 'H-NMR of a compound is acquired. The integration for signal A is 5692 and the integration for signal
B is 25614. What is the simplest whole number ratio of protons for signals A and B? (Show your work!!!)
5.
Assign the carbons in the NMR below as either carbonyl, aromatic, or alkyl.
200
150
100
50
ō (ppm)
1
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Calorimetry Concept, Examples and Thermochemistry | How to Pass Chemistry; Author: Melissa Maribel;https://www.youtube.com/watch?v=nSh29lUGj00;License: Standard YouTube License, CC-BY