(a)
Interpretation:
Synthesis of the given target molecule from phenylmethanol (benzyl alcohol) is to be determined.
Concept introduction:
Acid is converted to ester group by esterification reaction with the help of a strong base like

Answer to Problem 19.75P
Synthesis of the target molecule from phenylmethanol (benzyl alcohol) is
Explanation of Solution
Structure of the target molecule is
In the first step of the reaction, phenylmethanol (benzyl alcohol) is treated with oxidizing agent
In the second step of the reaction, benzoic acid undergoes esterification reaction. In this step, benzoic acid is first treated with a strong base like
The complete synthesis of the target molecule is as shown below.
By using the
(b)
Interpretation:
Synthesis of the given target molecule from phenylmethanol (benzyl alcohol) is to be determined.
Concept introduction:
For the conversion of alcohol group to Grignard reagent, alcohol (bad leaving group) is treated with
When Grignard reagent is reacted with
For the removal of water, tertiary alcohol is treated with conc.
The bromination reaction on alkene takes place in presence of

Answer to Problem 19.75P
Synthesis of the target molecule from phenylmethanol (benzyl alcohol) is
Explanation of Solution
Structure of the target molecule is
In the first step, the formation of Grignard reagent takes place. In this step, benzyl alcohol is treated with
The complete synthesis of the target molecule is as shown below.
By using the functional group conversion reactions, the synthesis of the target molecule is determined.
(c)
Interpretation:
Synthesis of the given target molecule from phenylmethanol (benzyl alcohol) is to be determined.
Concept introduction:
Grignard reagent, in presence of acidic condition, is used for the conversion of aldehyde or ketone to alcohol.
For the removal of water, tertiary alcohol is treated with conc.
Reaction of alkene with diazomethane in presence of heat results in the formation of cyclopropane ring.

Answer to Problem 19.75P
Synthesis of the target molecule from phenylmethanol (benzyl alcohol) is
Explanation of Solution
Structure of the target molecule is
In the first step, benzyl alcohol is treated with the oxidizing agent
In the second step, benzaldehyde is treated with Grignard reagent
In the third step, the presence of conc.
In the last step, alkene is treated with diazomethane in presence of heat that results in the formation of the cyclopropane ring.
The complete synthesis of the target molecule is as shown below.
By using the functional group conversion reactions, the synthesis of the target molecule is determined.
(d)
Interpretation:
Synthesis of the given target molecule from phenylmethanol (benzyl alcohol) is to be determined.
Concept introduction:
Grignard reagent, in presence of acidic condition, is used for the conversion of aldehyde or ketone to alcohol.

Answer to Problem 19.75P
Synthesis of the target molecule from phenylmethanol (benzyl alcohol) is
Explanation of Solution
Structure of the target molecule is
In the first step, benzyl alcohol is treated with the oxidizing agent
In the second step, benzaldehyde is treated with Grignard reagent
The complete synthesis of the target molecule is as shown below.
By using the functional group, conversion reactions synthesis of the target molecule is determined.
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Chapter 19 Solutions
EBK GET READY FOR ORGANIC CHEMISTRY
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- Please help, this is all the calculations i got!!! I will rate!!!Approx mass of KMnO in vial: 3.464 4 Moss of beaker 3×~0. z Nax200: = 29.9219 Massof weacerv after remosimgain N2C2O4. Need to fill in all the missing blanks. ง ง Approx mass of KMnO4 in vials 3.464 Mass of beaker + 3x ~0-304: 29.9219 2~0.20 Miss of beaker + 2x- 29.7239 Mass of beaker + 1x~0.2g Naz (204 29-5249 Mass of beaver after removing as qa Na₂ C₂O T1 T2 T3 Final Buiet reading Initial butet reading (int)) Hass of NaOr used for Titration -reading (mL) calculation Results: 8.5ml 17mL 27.4mL Oml Om Oml T1 T2 T3 Moles of No CO Moles of KMO used LOF KM. O used Molenty of KMNO Averagem Of KMOWLarrow_forwardDraw the skeletal ("line") structure of 2-hydroxy-4-methylpentanal. Click and drag to start drawing a structure. Xarrow_forwardDetermine whether the following molecule is a hemiacetal, acetal, or neither and select the appropriate box below. Also, highlight the hemiacetal or acetal carbon if there is one. hemiacetal acetal Oneither OHarrow_forward
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- What is the missing reactant R in this organic reaction? N N དལ་ད་་ + R • Draw the structure of R in the drawing area below. • Be sure to use wedge and dash bonds if it's necessary to draw one particular enantiomer. Click and drag to start drawing a structure. ㄖˋarrow_forwardDraw the condensed structure of 4-hydroxy-3-methylbutanal. Click anywhere to draw the first atom of your structure.arrow_forwardUsing the bond energy values, calculate the energy that must be supplied or is released upon the polymerization of 755 monomers. If energy must be supplied, provide a positive number; if energy is released, provide a negative number. Hint: Avogadro’s number is 6.02 × 1023.arrow_forward
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