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Concept explainers
(a)
Interpretation:
Fats and oils should be compared with respect to the identity and number of
Concept Introduction:
Triacylglycerols are triesters formed from glycerol and three molecules of fatty acids. Fats and oils are triacylglyserols which have different physical properties.
(b)
Interpretation:
Fats and oils should be compared with respect to the number of carbon-carbon double bonds present.
Concept Introduction:
Triacylglycerols are triesters formed from glycerol and three molecules of fatty acids. Fats and oils are triacylglyserols which have different physical properties.
(c)
Interpretation:
Fats and oils should be compared with respect to the melting point.
Concept Introduction:
Triacylglycerols are triesters formed from glycerol and three molecules of fatty acids. Fats and oils are triacylglyserols which have different physical properties.
(d)
Interpretation:
Fats and oils should be compared with respect to the natural source.
Concept Introduction:
Triacylglycerols are triesters formed from glycerol and three molecules of fatty acids. Fats and oils are triacylglycerols which have different physical properties.
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Chapter 19 Solutions
EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM
- 1. For the four structures provided, Please answer the following questions in the table below. a. Please draw π molecular orbital diagram (use the polygon-and-circle method if appropriate) and fill electrons in each molecular orbital b. Please indicate the number of π electrons c. Please indicate if each molecule provided is anti-aromatic, aromatic, or non- aromatic TT MO diagram Number of π e- Aromaticity Evaluation (X choose one) Non-aromatic Aromatic Anti-aromatic || ||| + IVarrow_forward1.3 grams of pottasium iodide is placed in 100 mL of o.11 mol/L lead nitrate solution. At room temperature, lead iodide has a Ksp of 4.4x10^-9. How many moles of precipitate will form?arrow_forwardQ3: Circle the molecules that are optically active: ДДДДarrow_forward
- 6. How many peaks would be observed for each of the circled protons in the compounds below? 8 pts CH3 CH3 ΤΙ A. H3C-C-C-CH3 I (₁₁ +1)= 7 H CI B. H3C-C-CI H (3+1)=4 H LIH)=2 C. (CH3CH2-C-OH H D. CH3arrow_forwardNonearrow_forwardQ1: Draw the most stable and the least stable Newman projections about the C2-C3 bond for each of the following isomers (A-C). Are the barriers to rotation identical for enantiomers A and B? How about the diastereomers (A versus C or B versus C)? H Br H Br (S) CH3 (R) CH3 H3C (S) H3C H Br Br H A C enantiomers H Br H Br (R) CH3 H3C (R) (S) CH3 H3C H Br Br H B D identicalarrow_forward
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