CHEMISTRY 1111 LAB MANUAL >C<
CHEMISTRY 1111 LAB MANUAL >C<
1st Edition
ISBN: 9781307092097
Author: Chang
Publisher: MCG/CREATE
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Chapter 19, Problem 19.21QP
Interpretation Introduction

Interpretation:

The nuclear binding energy and the binding energy per nucleon for the following isotope s should be calculated

Concept introduction:

  • Nuclear binding energy: It is the minimum amount of energy required to disassemble the nucleus of an atom into its component parts.

    The component parts are neutrons and protons, which are collectively called as nucleons.

  • Binding energy per nucleon:
  • The maximum binding energy per nucleon occurs at around mass number A=50.

    Example –Iron nucleolus (Fe56) is located closed to the peak with a binding energy per nucleon value of approximately 8.8 MeV.

  • Energy required to break the nucleus into its corresponding proton and neutron is called nuclear binding energy
  • This quantity represents the conversion of mass to energy occurs during an exothermic reaction.
  • Nuclear binding energy can be calculated by Einstein’s mass energy equivalence relationship that is,ΔE =(Δm)c2

    Where, (Δm) is called mass defect.

  • The difference between mass of an atom and the sum of the masses of its proton, electron, and neutron is called Mass defect

Formula:

Einstein mass energy relationship [ΔE=(ΔM)c2]

nuclear binding energy per nucleon =nuclear binding energynumber of nucleons

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Chapter 19 Solutions

CHEMISTRY 1111 LAB MANUAL >C<

Ch. 19 - Prob. 19.3QPCh. 19 - Prob. 19.4QPCh. 19 - Prob. 19.5QPCh. 19 - Prob. 19.6QPCh. 19 - Prob. 19.7QPCh. 19 - Prob. 19.8QPCh. 19 - Prob. 19.9QPCh. 19 - Prob. 19.10QPCh. 19 - Prob. 19.11QPCh. 19 - Prob. 19.12QPCh. 19 - Prob. 19.13QPCh. 19 - Prob. 19.14QPCh. 19 - The radius of a uranium-235 nucleus is about 7.0 ...Ch. 19 - For each pair of isotopes listed, predict which...Ch. 19 - Prob. 19.17QPCh. 19 - In each pair of isotopes shown, indicate which one...Ch. 19 - Prob. 19.19QPCh. 19 - Prob. 19.20QPCh. 19 - Prob. 19.21QPCh. 19 - Prob. 19.22QPCh. 19 - Prob. 19.23QPCh. 19 - Prob. 19.24QPCh. 19 - Prob. 19.25QPCh. 19 - Prob. 19.26QPCh. 19 - Prob. 19.27QPCh. 19 - Prob. 19.28QPCh. 19 - Prob. 19.29QPCh. 19 - Prob. 19.30QPCh. 19 - Prob. 19.31QPCh. 19 - Prob. 19.32QPCh. 19 - Prob. 19.33QPCh. 19 - Prob. 19.34QPCh. 19 - Prob. 19.35QPCh. 19 - Prob. 19.36QPCh. 19 - Prob. 19.37QPCh. 19 - Prob. 19.38QPCh. 19 - Prob. 19.39QPCh. 19 - Prob. 19.40QPCh. 19 - Prob. 19.41QPCh. 19 - Prob. 19.42QPCh. 19 - Prob. 19.43QPCh. 19 - Prob. 19.44QPCh. 19 - Prob. 19.45QPCh. 19 - Prob. 19.46QPCh. 19 - Prob. 19.47QPCh. 19 - Prob. 19.48QPCh. 19 - Prob. 19.49QPCh. 19 - Prob. 19.50QPCh. 19 - Prob. 19.51QPCh. 19 - Prob. 19.52QPCh. 19 - Prob. 19.53QPCh. 19 - Prob. 19.54QPCh. 19 - Prob. 19.55QPCh. 19 - Prob. 19.56QPCh. 19 - Prob. 19.57QPCh. 19 - Prob. 19.58QPCh. 19 - Prob. 19.59QPCh. 19 - Prob. 19.60QPCh. 19 - Prob. 19.61QPCh. 19 - Prob. 19.62QPCh. 19 - Prob. 19.63QPCh. 19 - Prob. 19.64QPCh. 19 - Prob. 19.65QPCh. 19 - Prob. 19.66QPCh. 19 - Prob. 19.67QPCh. 19 - Prob. 19.68QPCh. 19 - Prob. 19.69QPCh. 19 - Prob. 19.70QPCh. 19 - Prob. 19.71QPCh. 19 - Prob. 19.72QPCh. 19 - Prob. 19.73QPCh. 19 - Prob. 19.74QPCh. 19 - Prob. 19.75QPCh. 19 - Prob. 19.76QPCh. 19 - Prob. 19.77QPCh. 19 - Prob. 19.78QPCh. 19 - Prob. 19.79QPCh. 19 - Prob. 19.80QPCh. 19 - Prob. 19.81QPCh. 19 - Prob. 19.82QPCh. 19 - Prob. 19.83QPCh. 19 - Prob. 19.84QPCh. 19 - Prob. 19.85QPCh. 19 - Prob. 19.86QPCh. 19 - Prob. 19.87QPCh. 19 - Prob. 19.88QPCh. 19 - Prob. 19.89QPCh. 19 - Prob. 19.90QPCh. 19 - Prob. 19.91QPCh. 19 - Prob. 19.92QPCh. 19 - In each of the diagrams (a)(c), identify the...Ch. 19 - Prob. 19.94QPCh. 19 - Prob. 19.95QPCh. 19 - Prob. 19.96QPCh. 19 - Prob. 19.97QPCh. 19 - Prob. 19.98QPCh. 19 - Prob. 19.99QPCh. 19 - Prob. 19.100QPCh. 19 - Prob. 19.101QPCh. 19 - Prob. 19.102QPCh. 19 - Prob. 19.103QPCh. 19 - Prob. 19.104QPCh. 19 - The volume of an atoms nucleus is 1.33 1042 m3....Ch. 19 - Prob. 19.106QPCh. 19 - Prob. 19.107IMECh. 19 - Prob. 19.108IMECh. 19 - Prob. 19.109IMECh. 19 - Prob. 19.110IME
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